A B C Which of the circuits shown above are wired in parallel?

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Presentation transcript:

A B C Which of the circuits shown above are wired in parallel? 1) A only 2) B only 3) C only 4) B and C 5) all of them

A B C Which of the circuits shown above are wired in parallel? 1) A only 2) B only 3) C only 4) B and C 5) all of them When resistors are in parallel, the voltage drop across each is the same.

What is the current at point P? A) 2 A B) 3 A C) 6 A D) 10 A E) need more info to answer

I1 = I2 + I3 IC = IA + IB Kirchhoff’s Rules (rules of thumb) I1 I2 IB The SUM OF CURRENTS entering any junction equals the sum of all currents leaving. I1 I2 IB I1 = I2 + I3 I3 IC IA IC = IA + IB This follows from Conservation of Charge!

+24v – 24v = 0 When fully charged at Q=CV=(12pF)(24v) the circuit has two competing voltage steps: +24v – 24v = 0 + - 24 volts

12 V The voltage drop is 6  12  3  greatest across R1. 4. the same across each of the three resistors.

The current through the 2 resistor is 4  2  12 V The current through the 2 resistor is half the current through the 4. the same as thru the 4. twice the current through the 4.

The current through the 2 resistor is 4  2  I 12 V The current through the 2 resistor is half the current through the 4. the same as thru the 4. twice the current through the 4. ½ Ampere 2. 1 Ampere 2 Ampere 4. 3 Ampere 5. 4 Ampere 6. 6 Ampere

What is the “VOLTAGE DROP” across each resistor? 4  2  I 12 V The current through the 2 resistor is half the current through the 4. the same as thru the 4. twice the current through the 4. ½ Ampere 2. 1 Ampere 2 Ampere 4. 3 Ampere 5. 4 Ampere 6. 6 Ampere What is the “VOLTAGE DROP” across each resistor?

V = + 12 V – 8 V – 4 V = 0  Current in each resistor? Total resistance = 6  Ohm’s Law: I = V / R = 12 V / 6  = 2 A –IR = –8 V –IR = – 4 V 4  2  I 12 V Voltage drop across a resistor? V = I R + = 12 V Start V = + 12 V – 8 V – 4 V = 0 

e Kirchhoff’s Rules (rules of thumb) = IR1+ IR2 + IR3 + IR4 or 2. The SUM OF POTENTIAL DIFFERENCES across all components of ANY closed circuit loop is ZERO. R1 R2 = IR1+ IR2 + IR3 + IR4 or - IR1 - IR2 - IR3 - IR4 = 0 e R3 R4 This follows from Conservation of Energy!