Be sure your lab pages are numbered (7-7c). Add one more (7d) to glue in your lab analysis questions from Friday. Set up the NEXT page as follows: page = 8 date = 9-19-16 title = Kinematics Notes Set up your page for Cornell notes essential question = How can I describe the concepts of one-dimensional motion?

How Far? SI units = meters (m) POSITION: where an object is located relative to an origin DISTANCE: total length of travel scalar quantity (has no particular direction) DISPLACEMENT: change in position, or how far away an object is from its starting point vector quantity (has a specific direction)

practice 4.3 mi + 4.3 mi = 8.6 mi 4.3 mi + 4.3 mi + 2.1 mi = 10.7 mi Before describing motion, you must set up a coordinate system by defining an origin and a positive direction. If you drive from your house to the grocery store and back, what is the total distance you traveled? 4.3 mi + 4.3 mi = 8.6 mi If you drive from your house to the grocery store and then to your friend’s house, what is your total distance? What is your displacement? 4.3 mi + 4.3 mi + 2.1 mi = 10.7 mi 2.1 mi

HOW FAST? SI units = meters per second (m/s) SPEED: how fast an object is moving average speed = distance traveled / time elapsed scalar quantity ALWAYS positive VELOCITY: how fast an object is moving in a particular direction average velocity = displacement / time elapsed vector quantity can be positive or negative

practice What is his overall average speed? A runner sprints 50.0 m in 8.0 s. What is his average sprinting velocity? He walks back to the start in 40.0 s. What is his average walking velocity? displacement / time = 50.0 m / 8.0 s = 6.3 m/s displacement / time = 50.0 m / 40.0 s = 1.25 m/s What is his overall average speed? What is his overall average velocity? distance / time = 100.0 m / 48.0 s = 2.08 m/s ZERO / 48.0 s = ZERO

acceleration ∆v ∆t = vf −vi t ACCELERATION: a change in velocity SI units = meters per second per second (m/s2) average acceleration = change in velocity / time it took to change ∆v ∆t = vf −vi t vector quantity can be positive or negative

-1.8 m/s2 practice change in velocity time elapsed A runner traveling at 3.0 m/s sees the finish line ahead and begins to slow down, coming to a complete stop in 1.7 seconds. What is his average acceleration? change in velocity time elapsed 0 m s −3.0 m/s 1.7 s −3.0 m/s 1.7 s = = = -1.8 m/s2

Distance-time graphs Sketch the graph below onto your notes. You will be labeling the line segments. Distance (m) Time (s)

Distance-time graphs Distance (m) Slope = Time (s) 2) Horizontal line = 4) Diagonal line downwards = Distance (m) Slope = 3) Curved line = Diagonal line = Time (s)

Velocity-time graphs Sketch the graph below onto your notes. You will be labeling the line segments. Velocity (m/s) Time (s)

Velocity-time graphs Velocity (m/s) Slope = Time (s) 1) Upwards line = 4) Downward line = Velocity (m/s) 3) Upwards line = Slope = 2) Horizontal line = Time (s)