GRAPHS OF THE POLAR EQUATIONS r = a ± b cos θ r = a ± b sin θ

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GRAPHS OF THE POLAR EQUATIONS r = a ± b cos θ r = a ± b sin θ
Presentation transcript:

GRAPHS OF THE POLAR EQUATIONS r = a ± b cos θ r = a ± b sin θ

HOW THE SIZES OF a, b IMPACT THE GENERAL SHAPE OF THE GRAPH r = a ± b cos θ r = a ± b sin θ

CIRCLE r = a + b cos θ, where |a|=0 r = 2 cos θ

LIMACON WITH LOOP r = a + b cos θ, where |a|<|b| r = 1 + 2 cos θ

CARDIOID r = a + b cos θ, where |a|=|b| r = 2 + 2 cos θ

LIMACON WITH DIMPLE r = a + b cos θ, where |b|<|a|<2|b| r = 3 + 2 cos θ

CONVEX LIMACON r = a + b cos θ, where |a|=2|b| r = 4 + 2 cos θ

CONVEX LIMACON r = a + b cos θ, where |a|>2|b| r = 5 + 2 cos θ

HOW THE TRIGONOMETRIC FUNCTION IMPACTS THE ORIENTATION OF THE GRAPH r = a ± b cos θ r = a ± b sin θ

r = a + b cos θ, where a > 0, b > 0 r = 1 + 2 cos θ

r = a + b sin θ, where a > 0, b > 0 r = 1 + 2 sin θ

HOW THE SIGNS OF a, b IMPACT THE DIRECTION OF THE GRAPH r = a ± b cos θ r = a ± b sin θ

r = a + b cos θ, where a > 0, b > 0 r = 1 + 2 cos θ

r = a + b cos θ, where a > 0, b < 0 r = 1 - 2 cos θ

r = a + b cos θ, where a < 0, b > 0 r = -1 + 2 cos θ

r = a + b cos θ, where a < 0, b < 0 r = -1 - 2 cos θ

HOW WOULD YOU FIND THE x- AND y-INTERCEPTS OF A POLAR CURVE r = f(θ) ?

FIND THE VALUES OF r FOR θ = 0, π/2, π AND 3π/2 BE CAREFUL OF NEGATIVE VALUES OF r (THE INTERCEPTS WILL APPEAR ON THE “OPPOSITE” SIDE OF THE AXIS)

GRAPHS OF THE POLAR EQUATIONS r = a ± b cos θ r = a ± b sin θ 1. Determine the shape of the graph by comparing |a| to |b| and 2|b| 2. Determine the axis of symmetry from the trigonometric function 3. Determine the direction of the “fat” part from the sign of the trigonometric function 4. Find and plot the x- and y-intercepts by finding the values of r for θ = 0, π/2, π AND 3π/2 5. Connect and form the appropriate shape Circles, cardioids and limacons with loops pass through the pole; dimpled and convex limacons do not

PUTTING IT TOGETHER GUESS THE GRAPH BY DETERMINING THE SHAPE, THE ORIENTATION, THE DIRECTION & THE INTERCEPTS r = -4 - 3 sin θ

r = -4 - 3 sin θ

PUTTING IT TOGETHER GUESS THE GRAPH BY DETERMINING THE SHAPE, THE ORIENTATION, THE DIRECTION & THE INTERCEPTS r = -4 + 4 cos θ

r = -4 + 4 cos θ

GRAPHS OF THE POLAR EQUATIONS r = a cos nθ r = a sin nθ

HOW THE VALUE OF n IMPACTS THE GENERAL SHAPE OF THE GRAPH r = a cos nθ r = a sin nθ

r = 3 cos θ

r = 3 cos 2θ

r = 3 cos 3θ

r = 3 cos 4θ

r = 3 cos 5θ

r = 3 cos 6θ

PUTTING IT TOGETHER GUESS THE EQUATION OF A ROSE CURVE WITH [a] 16 petals [b] 15 petals [c] 14 petals

PUTTING IT TOGETHER [a] r = a sin 8θ or r = a sin 8θ [b] r = a sin 15θ or r = a sin 15θ [c] no such rose curve

HOW THE TRIGONOMETRIC FUNCTION IMPACTS THE ORIENTATION OF THE GRAPH r = a cos nθ r = a sin nθ

r = 3 cos θ

r = 3 sin θ

r = 3 cos 2θ

r = 3 sin 2θ

r = 3 cos 3θ

r = 3 sin 3θ

r = 3 cos 4θ

r = 3 sin 4θ

r = 3 cos 5θ

r = 3 sin 5θ

r = 3 cos 6θ

r = 3 sin 6θ