Word Problems Involving Triangle.

Slides:



Advertisements
Similar presentations
Copyright © 2013, 2009, 2006 Pearson Education, Inc. 1 1 Section 2.5 An Introduction to Problem Solving Copyright © 2013, 2009, 2006 Pearson Education,
Advertisements

REVIEW for TEST Parallel and Perpendicular Solving Systems of Equations.
2.5Formulas and Additional Applications from Geometry
4.7 Quadratic Equations and Problem Solving BobsMathClass.Com Copyright © 2010 All Rights Reserved. 1 General Strategy for Problem Solving Understand the.
Today: Lecture on Section 2.6: More word problems! Next class session: Review for Test 1 (covers everything since the beginning of the semester, including.
2.3 Solving Word Problems. Goals SWBAT solve linear inequalities SWBAT solve linear inequalities SWBAT solve compound inequalities SWBAT solve compound.
Applications of Geometry Example 1: The perimeter of a rectangular play area is 336 feet. The length is 12 feet more than the width. Determine the dimensions.
Perimeter Is the sum of the lengths of the sides. When solving a perimeter problem, it is helpful to draw and label a figure to model the region.
Green text p.138 #s The length of the second side of a triangle is 2 inches less than the length of the first side. The length of the third.
© by S-Squared, Inc. All Rights Reserved. 1.Find the distance, d, and the midpoint, m, between (4, − 2) and (2, 6) Distance Formula: d = (x.
Do Now. Homework Solutions 1)c 2 – 26c – 56 = 0 (c – 28)(c + 2) = 0 {-2, 28} 2)n 2 + 4n – 32 = 0 (n + 8)(n – 4) = 0 {-8, 4} 3)h 2 + 2h – 35 = 0 (h + 7)(h.
Formulas and Problem Solving
CHAPTER 8 Geometry Slide 2Copyright 2012, 2008, 2004, 2000 Pearson Education, Inc. 8.1Basic Geometric Figures 8.2Perimeter 8.3Area 8.4Circles 8.5Volume.
Algebra Foundations 1 Fall Semester Review.
Handout Solve the following applications. Draw a table or diagram when necessary.
The area of a rectangle equals its length times the width (base times the height). A = length x width = lw or A = base x height = bh Area of a Rectangle.
Solving Equations with Grouping Symbols
Perimeter of Rectangles
Problem Solving Chapter 2 Honors Math – Grade 8. A poll reported the approval rating of the CEO of a corporation to be 62%. If the poll is accurate within.
Solve Equations with Two Operations Honors Math – Grade 8.
EXAMPLE 2 Rewrite a formula with three variables SOLUTION Solve the formula for w. STEP 1 P = 2l + 2w P – 2l = 2w P – 2l 2 = w Write perimeter formula.
Solving Quadratic Word Problems by Factoring March 11, 2014 SWBAT Solve Quadratic Word Problems by Factoring.
EXAMPLE 3 Standardized Test Practice A = lw 63 = 9w 63 = = w Write area formula. Substitute values. Divide each side by 9. Simplify. ANSWERThe.
Copyright © Ed2Net Learning, Inc.1 Good Afternoon! Today we will be learning about Review of Right Triangles Let’s warm up : Find the length of the missing.
Write an algebraic expression to represent 5 less than a number “n”.
Writing & Solving Equations
Triangle Sum Theorem In a triangle, the three angles always add to 180°: A + B + C = 180° 38° + 85° + C = 180° C = 180° C = 57°
4.8 Polynomial Word Problems. a) Define the variable, b) Write the equation, and c) Solve the problem. 1) The sum of a number and its square is 42. Find.
Math 71 Chapter 1. Use the order of operations to simplify each expression. What is your first step? and/or
The length of a rectangle is twice the width. The perimeter is 72 inches. Find the length and the width of the rectangle.
Solve the following word problem. Manny is two years older Enrique. The sum of the their ages is 40. How old is Manny and Enrique? Let: m = Manny’s age.
Solve for x. Do Now. Homework Solutions 1)c 2 – 26c – 56 = 0 (c – 28)(c + 2) = 0 {-2, 28} 2)d 2 – 5d = 0 d (d – 5) = 0 {0, 5} 3)v 2 – 7v = 0 v (v – 7)
Optimization Problems Section 4-4. Example  What is the maximum area of a rectangle with a fixed perimeter of 880 cm? In this instance we want to optimize.
2.7 Mathematical Models. Optimization Problems 1)Solve the constraint for one of the variables 2)Substitute for the variable in the objective Function.
Problem Solving: Geometry and Uniform Motion. 1. Find two supplementary angles such that the measure of the first angle is three times the measures of.
Slide 1 Copyright © 2015, 2011, 2008 Pearson Education, Inc. Perimeter Section9.2.
Example: cost of bananas at $0.19 each 0.19b Objective.
Perimeter and Area Riddles
Lesson Days Equations and Problem Solving Pages
11-1 Areas of Triangles and Parallelograms Hubarth Geometry.
Algebra 2 Lesson 1-3 Examples (part 2). Solving Equations A solution to an equation is __________________________________________ __________________________________________.
3.4 – Geometric problems – 5 step approach (p200)
Copyright 2013, 2010, 2007, 2005, Pearson, Education, Inc.
5-6 to 5-7 Using Similar Figures
Rewrite a formula with three variables
Special Right Triangles
EXAMPLE 1 Finding Area and Perimeter of a Triangle
Word Problems Involving & NUMBERS.
Word Problems.
Steps to solving a word problem
Area and perimeter jeopardy TriangleRectangleTrapezoidCircle Circle Part II Final Jeopardy.
Algebraic Expressions and
Honors Calculus 4.8. Optimization.
8.1 Ratio and Proportion.
IDENTIFYING TRIANGLES
Similar Polygons.
Combine Like Terms and Distribute
Warm up Match each of the phrases with its appropriate operation
Warm Up 1. If ∆QRS  ∆ZYX, identify the pairs of congruent angles and the pairs of congruent sides. Solve each proportion Q  Z; R 
Warm Up Problem of the Day Lesson Presentation Lesson Quizzes.
Problem Solving and Using Formulas
3.3 – solving Inequalities (multi-step)
Chapter 9 Basic Algebra © 2010 Pearson Education, Inc. All rights reserved.
Metric Conversions and Properties of Equalilty
6.4 Solving by Factoring.
one of the equations for one of its variables Example: -x + y = 1
Cost of fencing.
Area and Perimeter Review
Goal: The learner will find area and perimeter.
Metric Conversions and Properties of Equalilty
Presentation transcript:

Word Problems Involving Triangle

Before We Start Recall How we can change

WORDS I N T O MATH

The following slides show how many words in word problems can be translated into Math Symbols. The translations shown are not always the only translations and there may be others more appropriate for each word problem you encounter. However, the examples in the next slides typify the most common translations of words into Math Symbols.

MATH WORDS = is

MATH WORDS = is of

MATH WORDS + more

MATH WORDS + more less

MATH WORDS product

MATH WORDS product quotient FRACTION

MATH WORDS sum

MATH WORDS sum difference

MATH WORDS twice

MATH WORDS Twice as many

MATH WORDS Twice as many Three times as many

MATH WORDS Twice as many Three times as many Triple

MATH WORDS Half of

MATH WORDS Half of Half as many

MATH WORDS One third of

MATH WORDS One third of A third as many

In the following slides you will find several different types of perimeter word problems. If you wish to see how to solve the problem, click on the problem and you will be taken to the solution.

RECTANGLE PROBLEMS The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length. 1 The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width. 2 The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? 3

TRIANGLE PROBLEMS A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. 4 The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side 5

1 Example #1

The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length Click to go To List of Problems

Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length

Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length

Perimeter Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length Perimeter

Perimeter Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length Perimeter

Perimeter Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length Perimeter

Perimeter Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length Perimeter

Clearly shows that you are dividing by the same thing on both sides

Go back and read the problem

Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length

Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length

Let x represent the width The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length The width is 12 the length is 36 Click to go To List of Problems

2 Example #2

The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width. Click to go To List of Problems

The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width.

Let w represent the width The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width.

50 Let w represent the width The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width. 50

50 Let w represent the width The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width. 50

50 Let w represent the width The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width. 50

50 Let w represent the width The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width. 50

Symmetric Prop. Of Equality Not Absolutely Necessary but it’s nice to have the unknown variable on the left side

Clearly shows that you are subtracting the same thing from both sides

Clearly shows that you are dividing by the same thing on both sides

Go back and read the problem

Let w represent the width The length of a rectangle is 50 meters. This is 6 meters more than twice the width. Find the width. The width is 22 meters Click to go To List of Problems

3 Example #3

The length of a rectangular field is 18 m longer than the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? Click to go To List of Problems

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216 216 =

Clearly shows that you are subtracting the same thing from both sides

Clearly shows that you are dividing by the same thing on both sides

Go back and read the problem

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

Let w represent the width The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? The width = 36 m and The length = 54 m

Check if the fencing = 216 m FENCING = 216 The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle? FENCING = 216 Click to go To List of Problems

4 Example #4

A triangle is isosceles, that is, it has two sides of equal length A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. Click to go To List of Problems

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. Perimeter = 570

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. Perimeter = 570

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. Perimeter = 570

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. Perimeter = 570

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. Perimeter = 570

Clearly shows that you are adding the same thing to both sides

Clearly shows that you are dividing by the same thing on both sides

Go back and read the problem

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side.

Let x represent the length of each equal side A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. The equal sides = 150 in and The third side = 270 in

Check out the Perimeter A triangle is isosceles, that is, it has two sides of equal length. The third side is 30 inches shorter than twice the length of each congruent side. The perimeter is 570 inches. Find the length of each side. Perimeter = 570 Click to go To List of Problems

5 Example #5

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side 1st 2nd Click to go To List of Problems

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side Perimeter = 26

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side Perimeter = 26

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side Perimeter = 26

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side Perimeter = 26

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side Perimeter = 26

Clearly shows that you are adding the same thing to both sides

Clearly shows that you are dividing by the same thing on both sides

Go back and read the problem

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side

Let x represent the length of the second side The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side The second side = 11 m and The first side = 3 m The third side = 12 m

Check out the Perimeter The first side of a triangle is 8 m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side Perimeter = 26 26 Click to go To List of Problems