Linford Group Meeting Department of Chemistry and Biochemistry Brigham Young University Thursday, Feb. 23, 2017 Problems on the oxidation of tertiary amines,

Slides:



Advertisements
Similar presentations
Bisection Method (Midpoint Method for Equations).
Advertisements

Lectures on Numerical Methods 1 Numerical Methods Charudatt Kadolkar Copyright 2000 © Charudatt Kadolkar.
FP1: Chapter 2 Numerical Solutions of Equations
- + Suppose f(x) is a continuous function of x within interval [a, b]. f(a) = - ive and f(b) = + ive There exist at least a number p in [a, b] with f(p)
Section 5.5 – The Real Zeros of a Rational Function
Numerical Analysis 1 EE, NCKU Tien-Hao Chang (Darby Chang)
Theorems on continuous functions. Weierstrass’ theorem Let f(x) be a continuous function over a closed bounded interval [a,b] Then f(x) has at least one.
Solving Non-Linear Equations (Root Finding)
Rolle’s theorem and Mean Value Theorem ( Section 3.2) Alex Karassev.
Limits Basic facts about limits The concept of limit underlies all of calculus. Derivatives, integrals and series are all different kinds of limits. Limits.
Continuity ( Section 1.8) Alex Karassev. Definition A function f is continuous at a number a if Thus, we can use direct substitution to compute the limit.
Intermediate Value Theorem If f is continuous on [ a,b ] and k is any number between f(a) and f(b), inclusive, then there is at least one number c in the.
Sec 5: Vertical Asymptotes & the Intermediate Value Theorem
MAT 1234 Calculus I Section 1.8 Continuity
Section 5.4a FUNDAMENTAL THEOREM OF CALCULUS. Deriving the Theorem Let Apply the definition of the derivative: Rule for Integrals!
Warm Up – NO CALCULATOR Let f(x) = x2 – 2x.
Warm up 1. Do in notebook. Be seated before the bell rings DESK homework Warm-up (in your notes) Agenda : warm-up Go over homework homework quiz Notes.
Recall the definitions of even/odd functions:
2.4 Continuity and its Consequences and 2.8 IVT Tues Sept 15 Do Now Find the errors in the following and explain why it’s wrong:
Review Limits When you see the words… This is what you think of doing…  f is continuous at x = a  Test each of the following 1.
1.4 Continuity  f is continuous at a if 1. is defined. 2. exists. 3.
Solving Non-Linear Equations (Root Finding)
Numerical Methods Solution of Equation.
Intermediate Value Theorem Vince Varju. Definition The Intermediate Value Theorem states that if a function f is a continuous function on [a,b] then there.
Recursive Methods for Finding Roots of Functions Bisection & Newton’s Method.
CONTINUITY. A function f(x) is continuous at a number a if: 3 REQUIREMENTS f(a) exists – a is in the domain of f exists.
Limits and Continuity Unit 1 Day 4.
Chapter 6 Integration Section 4 The Definite Integral.
AP Calc AB IVT. Introduction Intermediate Value Theorem If a function is continuous between a and b, then it takes on every value between and. Because.
Theorems Lisa Brady Mrs. Pellissier Calculus AP 28 November 2008.
Algebra and Calculus 8-1 Copyright © Genetic Computer School 2007 Lesson 8 Fundamentals of Calculus.
MATH342: Numerical Analysis Sunjae Kim.
Continuity and One-Sided Limits
Rolle’s theorem and Mean Value Theorem (Section 4.2)
Hypothesis: Conclusion:
Lesson 63 Rolle’s Theorem and the Mean Value Theorem
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Polynomial Functions of Higher Degree with Modeling
Solution of Nonlinear Equations (Root finding Problems
Numerical Methods and Analysis
Locating Real Zeros of Polynomials
Table of Contents 8. Section 2.7 Intermediate Value Theorem.
Linford Group Meeting Department of Chemistry and Biochemistry Brigham Young University Thursday, Feb. 9, 2017 Acidities of organic compounds, the dicarboxylic.
Read Chapters 5 and 6 of the textbook
MATH 2140 Numerical Methods
Graphing Polynomial Functions
Important Values for Continuous functions
Roots of equations Class IX.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Intermediate Value Theorem
Revision Class Chapters 7 and 8.
Intermediate Value Theorem
Table of Contents 8. Section 2.7 Intermediate Value Theorem.
Continuity and Intermediate Value Theorem
Problem of the day.
Continuity and One-Sided Limits
1.4 Continuity and One-Sided Limits (Part 2)
Sec 2.5: Continuity Continuous Function
Continuity Alex Karassev.
FP1: Chapter 2 Numerical Solutions of Equations
Sec:5.2 The Bisection Method.
4.2 Graphing Polynomial Functions
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Intermediate Value Theorem
5. Continuity on an Interval
Sec 2.5: Continuity Continuous Function
EXTREMELY important for the AP Exam
Lesson 63 - Intermediate Value Theorem
Solutions for Nonlinear Equations
Presentation transcript:

Linford Group Meeting Department of Chemistry and Biochemistry Brigham Young University Thursday, Feb. 23, 2017 Problems on the oxidation of tertiary amines, the Cope elimination, the triangle function, and the Bisection Method for finding roots of equations by Matthew Linford

Chemistry What happens when I treat the following tertiary amine with mCPBA? Hint: assuming R1 – R4 are alkyl/aryl groups, where is the molecule most likely to oxidize? Draw a mechanism for the following reaction (the Cope Elimination). Note the stereochemistry. What is the structure of the byproduct that is not drawn? mCPBA

Math The triangle function is defined as follows: Λ(x) = 0 for |x| > 1 and 1 - |x| for |x| < 1 Graph Λ(x). What is the area of Λ(x)? What is lim τ  0 Λ(x/τ). What is the area of this function? This is an example of what kind of function? What is lim τ  0 (1/τ) Λ(x/τ). What is the area of this function? This is an example of what kind of function?

Math An important problem in numerical analysis is that of finding roots of equations. (A ‘root’ is a point where a function crosses the x-axis.) The simplest method for determining the roots of a function, f(x), is the bisection method. We’ll start with this method/algorithm. The bisection method is based on the Intermediate Value Theorem (IVT). This theorem says that if f ε C[a,b], i.e., if f, the function, is continuous over the closed interval that lies between a and b, and K is any number between f(a) and f(b), then there exists a c in [a,b] for which f(c) = K. Draw a picture that explains this theorem, and convince yourself that it is reasonable.

Math The bisection method says: Suppose a continuous function is defined on [a,b] and that f(a) and f(b) have opposite signs. By the IVT, there exists a p, a < p < b for which f(p) = 0. The bisection method consists of repeatedly halving the subinterval [a,b] and at each step locating the ‘half’ containing p. Use the bisection method to find a root of f(x) = 3x4 – 2x2 – 4 over [1,2]. Find this root to an accuracy of 10-2. In the above definition of the Bisection Method, could we replace the statement: “f(a) and f(b) have opposite signs” with “f(a)*f(b) < 0”? Where might this new definition be useful?

Math Derive an equation that gives the accuracy (error) of the Bisection Method, or at least an upper limit for its accuracy, in terms of n, the number of steps (bisections) made. Calculate the number of steps (bisections) you would have to take to guarantee an error less than 10-5 for the problem we just solved: Use the bisection method to find a root of f(x) = 3x4 – 2x2 – 4 over [1,2]. Find the root to an accuracy of 10-2. What can you see as an important advantage and an important disadvantage of the Bisection Method?