Starter Find the gradient function for each of the following:

Slides:



Advertisements
Similar presentations
Section 3.3a. The Do Now Find the derivative of Does this make sense graphically???
Advertisements

The Chain Rule Section 3.6c.
C1: Tangents and Normals
Integrals 5. Integration by Parts Integration by Parts Every differentiation rule has a corresponding integration rule. For instance, the Substitution.
4.1 Antiderivatives and Indefinite Integrals Defn. A function F(x) is an antiderivative of f(x) on an interval I if F '(x)=f(x) for all x in I. ex. Find.
Copyright © Cengage Learning. All rights reserved.
C1: Simple Differentiation
4.1 The Indefinite Integral. Antiderivative An antiderivative of a function f is a function F such that Ex.An antiderivative of since is.
24: Indefinite Integration © Christine Crisp “Teach A Level Maths” Vol. 1: AS Core Modules.
Antiderivatives Indefinite Integrals. Definition  A function F is an antiderivative of f on an interval I if F’(x) = f(x) for all x in I.  Example:
C1:Indefinite Integration
Differential Equations
Section 5.2 Integration: “The Indefinite Integral”
Integration Copyright © Cengage Learning. All rights reserved.
ANTIDERIVATIVES Definition: reverse operation of finding a derivative.
Introduction Integration is the reverse process of Differentiation Differentiating gives us a formula for the gradient Integrating can get us the formula.
Tangents.
Integration 4 Copyright © Cengage Learning. All rights reserved.
Chapter 4 Integration 4.1 Antidifferentiation and Indefinate Integrals.
HIGHER MATHEMATICS Unit 2 - Outcome 2 Integration.
Calculus continued The reverse of differentiation The reverse process of differentiation is called Integration.
Introduction to Integrals Unit 4 Day 1. Do Now  Write a function for which dy / dx = 2 x.  Can you think of more than one?
Copyright © Cengage Learning. All rights reserved.
4 Integration.
Antiderivatives.
Copyright © Cengage Learning. All rights reserved.
Section 6.2 Constructing Antiderivatives Analytically
Integration-Example Find the area between the 2 curves between the 2 points of intersection. X=1 and X=3 1)The.
Antidifferentiation and Indefinite Integrals
2 Differentiation.
The Factor Theorem.
Chapter 10 Limits and the Derivative
3.6 Chain Rule.
Equations of Tangents.
Differentiating Polynomials & Equations of Tangents & Normals
Differentiation from First Principles
Section 15.5 The Chain Rule.
INTEGRATION.
Anti-differentiation
Copyright © Cengage Learning. All rights reserved.
Copyright © Cengage Learning. All rights reserved.
and Indefinite Integration (Part I)
Part (a) Keep in mind that dy/dx is the SLOPE! We simply need to substitute x and y into the differential equation and represent each answer as a slope.
Calculus for ENGR2130 Lesson 2 Anti-Derivative or Integration
Antiderivatives and Indefinite Integration
Fundamental Theorem of Calculus Indefinite Integrals
Copyright © Cengage Learning. All rights reserved.
Differentiation.
Solving Differential Equations
Chapter 4 More Derivatives Section 4.1 Chain Rule.
Calculus (Make sure you study RS and WS 5.3)
Copyright © Cengage Learning. All rights reserved.
INTEGRATION To find the area under a curve you could draw a series if trapezia and add their areas which would give an approximation to the area. As the.
Copyright © Cengage Learning. All rights reserved.
(Indefinite) Integration
“Teach A Level Maths” Vol. 1: AS Core Modules
Chapter 6 Applications of Derivatives Section 6.2 Definite Integrals.
Copyright © Cengage Learning. All rights reserved.
Antiderivatives and Indefinite Integration
Tutorial 4 Techniques of Differentiation
Integration L.O. All pupils understand what integration is
Rate of change / Differentiation (2)
5.1 Integrals Rita Korsunsky.
Gradients and Tangents
Chapter 4 More Derivatives Section 4.1 Chain Rule.
AS-Level Maths: Core 1 for Edexcel
Copyright © Cengage Learning. All rights reserved.
Function Notation.
Presentation transcript:

Starter Find the gradient function for each of the following: y = x3 + 7 y = x3 y = x3 – 5 y = x3 + 2 y = x3 – 8 What do you notice? Why do you think this has happened?

Calculus 2 Integration

Calculus 2 As you saw in the starter dy/dx = 3x2 is the gradient function for lots of equations. How many equations have dy/dx = 3x2? Curves of the form y = x3 + c, where c is any number all have dy/dx = 3x2

Integration If we are given a gradient function (dy/dx), integration, is the process of working backwards from this to find the equation of the curve. ∫ means “integrate”

Integration Is the gradient function enough to find the equation of the curve? Suppose dy/dx = 2x what curve has this gradient function? Hint: Think back to the start of differentiation, what differentiates to give you 2x? Are there any others?

Differentiation What is the general rule for differentiating xn? If y = xn then dy/dx = nxn-1 Integration has a similar pattern…..

Integration If dy/dx = xn then ∫ xn dx = xn+1 + c n+1 Explain what the ‘dx’ is for and what the ‘c’ means This just means that you are integrating ‘with respect to x’ as opposed to any other letter This stands for any constant number

How does this work??? The notation can look confusing but when you put it into practice it gets easier You can remember it as: “add one to the power, divide by the new power”

Examples Integrate the following: x7 x2 5 3x3 Hint: Remember “add one to the power and divide by the new power”

What if the equation is more complicated? Suppose dy/dx = 3x2 + 2x + 5 How do we integrate that? You just take each part of the equation at a time to get: ∫ 3x2 + 2x + 5 dx = 3(x3/3) + 2(x2/2) + 5x + c = x3 + x2 + 5x + c Solutions that involve ‘c’ are called indefinite integrals

INTEGRALS Finding the value of c

Finding c Find the general solution to: dy/dx = 6x2 + 2x – 5 y = 6(x3/3) + 2(x2/2) – 5(x) + c y = 2x3 + x2 – 5x + c

Finding c Find the equation of the curve with this gradient function that passes through the point (1,7) So we know the equation is of the form y = 2x3 + x2 – 5x + c How can we find the value of c?

Finding c 7 = 2(13) + (12) - 5(1) + c 7 = 2 + 1 – 5 + c 7 = -2 + c So the equation of the curve is: y = 2x3 + x2 – 5x + 9

Summary To find the equation of a curve: Integrate the gradient function Substitute the coordinates of a point on the curve to find the value of c Write the full equation of the curve