Table 4(Lawrence, Justin, Paul, Jaehoon) #22, 26,30,34 Table 4(Lawrence, Justin, Paul, Jaehoon)

#22 If Ben invests $4000 at 4% interest per year, how much additional money must he invest at 5.5% annual interest to ensure that the interest he receives each year is 4.5% of the total amount invested? Identify the variable: x=additional money for invest Translate from the words to algebra: Ben invest 4000$ 4.5% per year A, he needs to invest x 5.5% per year B, such that A+B=4.5%(4000+X) Set up the model:0.04(4000)+0.055(X)+0.045(4000+x) 0.04(4000)+0.055(X)+0.045(4000+x) 40(4000)+55(x)=45(4000+x) 55x-45x=180000-160000 10x=20000 X=2000

#26 A woman earns 15% more than her husband. Together they make $69,875 per year. What is the husband’s annual salary? X = Husband’s annual salary 1.15X = Woman’s annual salary +___________________________ 2.25X = Their annual salary = $69,875 69,875/2.25 = 31,056 = X Husband’s annual salary is $31,056

Father’s age = f | Daughter’s age = d #30 A father is four times as old as his daughter. In 6 years, he will be three times as old as she is. How old is the daughter now? Father’s age = f | Daughter’s age = d f/ 4 = d f= 4d (f+ 6) / 3 = d + 6 f + 6 = 3d + 18 = f = 3d +12 Since f = 4d 4d = 3d +12 = d = 12 Daughter’s age is 12

#34 Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have? Equation: 0.05(2x+5)+0.1(2x)+0.25(x)=3 0.55x+0.25=3 0.55X=2.75 X=5 Answer: 15 nickel, 10 dimes, 5 quarters # of nickel: 2x+5 # of dime: 2x # of quarter: x