Solubility Equilibria

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Presentation transcript:

Solubility Equilibria Lead (II) iodide precipitates when potassium iodide is mixed with lead (II) nitrate. Graphic: Wikimedia Commons user PRHaney

Ksp Values for Some Salts at 25C Name Formula Ksp  Barium carbonate   BaCO3   2.6 x 10-9   Barium chromate   BaCrO4   1.2 x 10-10   Barium sulfate   BaSO4   1.1 x 10-10   Calcium carbonate   CaCO3   5.0 x 10-9   Calcium oxalate   CaC2O4   2.3 x 10-9   Calcium sulfate   CaSO4   7.1 x 10-5   Copper(I) iodide   CuI   1.3 x 10-12   Copper(II) iodate   Cu(IO3)2   6.9 x 10-8   Copper(II) sulfide   CuS   6.0 x 10-37   Iron(II) hydroxide   Fe(OH)2   4.9 x 10-17   Iron(II) sulfide   FeS   6.0 x 10-19   Iron(III) hydroxide   Fe(OH)3   2.6 x 10-39   Lead(II) bromide   PbBr2   6.6 x 10-6   Lead(II) chloride   PbCl2   1.2 x 10-5   Lead(II) iodate   Pb(IO3)2   3.7 x 10-13   Lead(II) iodide   PbI2   8.5 x 10-9   Lead(II) sulfate   PbSO4   1.8 x 10-8  Name Formula Ksp  Lead(II) bromide   PbBr2   6.6 x 10-6   Lead(II) chloride   PbCl2   1.2 x 10-5   Lead(II) iodate   Pb(IO3)2   3.7 x 10-13   Lead(II) iodide   PbI2   8.5 x 10-9   Lead(II) sulfate   PbSO4   1.8 x 10-8   Magnesium carbonate   MgCO3   6.8 x 10-6   Magnesium hydroxide   Mg(OH)2   5.6 x 10-12   Silver bromate   AgBrO3   5.3 x 10-5   Silver bromide   AgBr   5.4 x 10-13   Silver carbonate   Ag2CO3   8.5 x 10-12   Silver chloride   AgCl   1.8 x 10-10   Silver chromate   Ag2CrO4   1.1 x 10-12   Silver iodate   AgIO3   3.2 x 10-8   Silver iodide   AgI   8.5 x 10-17   Strontium carbonate   SrCO3   5.6 x 10-10   Strontium fluoride   SrF2   4.3 x 10-9   Strontium sulfate   SrSO4   3.4 x 10-7   Zinc sulfide   ZnS   2.0 x 10-25 

Solving Solubility Problems For the salt AgI at 25C, Ksp = 1.5 x 10-16 AgI(s)  Ag+(aq) + I-(aq) I C E O O +x +x x x 1.5 x 10-16 = x2 x = solubility of AgI in mol/L = 1.2 x 10-8 M

Solving Solubility Problems For the salt PbCl2 at 25C, Ksp = 1.6 x 10-5 PbCl2(s)  Pb2+(aq) + 2Cl-(aq) I C E O O +x +2x x 2x 1.6 x 10-5 = (x)(2x)2 = 4x3 x = solubility of PbCl2 in mol/L = 1.6 x 10-2 M

Solving Solubility with a Common Ion For the salt AgI at 25C, Ksp = 1.5 x 10-16 What is its solubility in 0.05 M NaI? AgI(s)  Ag+(aq) + I-(aq) I C E O 0.05 +x 0.05+x x 0.05+x 1.5 x 10-16 = (x)(0.05+x)  (x)(0.05) x = solubility of AgI in mol/L = 3.0 x 10-15 M

Precipitation and Qualitative Analysis

Complex Ions A Complex ion is a charged species composed of: 1. A metallic cation 2. Ligands – Lewis bases that have a lone electron pair that can form a covalent bond with an empty orbital belonging to the metallic cation

NH3, CN-, and H2O are Common Ligands

Coordination Number Coordination number refers to the number of ligands attached to the cation 2, 4, and 6 are the most common coordination numbers Coordination number Example(s) 2 Ag(NH3)2+ 4 CoCl42- Cu(NH3)42+ 6 Co(H2O)62+ Ni(NH3)62+

Complex Ions and Solubility AgCl(s)  Ag+ + Cl- Ksp = 1.6 x 10-10 Ag+ + NH3  Ag(NH3)+ K1 = 2.1 x 103 Ag(NH3)+ NH3  Ag(NH3)2+ K2 = 8.2 x 103 AgCl + 2NH3  Ag(NH3)2+ + Cl- K = KspK1K2