Standard Form.

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Standard Form

Slope-intercept form  y = mx + b Different Forms Slope-intercept form  y = mx + b slope y-intercept Standard form  Ax + By = C Cannot both be 0 Point-Slope form  y – y1 = m(x – x1) y-coordinate slope x-coordinate

Finding the x-intercept and y-intercept Standard form  2x + 4y = 12 To find the x-intercept, substitute 0 for y and solve for x. To find the y-intercept, substitute 0 for x and solve for y. 2x + 4(0) = 12 2(0) + 4y = 12 2x = 12 x = 6 4y = 12 y = 3 x-intercept is (6,0) y-intercept is (0,3)

Finding the x-intercept and y-intercept 4x – 9y = 18 5x + 2y = -10 4x – 9(0) = 18 5x + 2(0) = -10 4x = 18 x = 4.5 5x = -10 x = -2 x-intercept is (4.5,0) x-intercept is (-2,0) 5(0) + 2y = -10 4(0) – 9y = 18 -9y = 18 y = -2 2y = -10 y = -5 y-intercept is (0,-2) y-intercept is (0,-5)

Graphing Lines Using Intercepts 2x + 3y = 12 Steps 1) Find the intercepts  2x = 12 x = 6 (6,0) 3y = 12 y = 4 (0,4)  2) Plot the intercepts and draw a line through the points.

Graphing Lines Using Intercepts 5x + 2y = -10 1) 5x = -10 x = -2 (-2,0) 2y = -10 y = -5 (0,-5) 2)    4x – 9y = 18 4x = 18 x = 4.5 (4.5,0) -9y = 18 y = -2 (0,-2) 

Graphing Horizontal and Vertical Lines y = -3 Steps 1) Write in standard form if needed 0x + 1y = -3 2) This means that for all values of x, y = -3   x = 2 1) 1x + 0y = 2 2) This means that for all values of y, x = 2

Graphing Horizontal and Vertical Lines y = 5 y = -1  x = -4    x = 6

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Assignments Class Work Page 333 #1 – 18 #19 – 25 odd Page 334 #38 – 46 Homework Page 335 #73 – 76