6.7 Areas of Triangles and Quadrilaterals

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Presentation transcript:

6.7 Areas of Triangles and Quadrilaterals

Objectives: Find the areas of squares, rectangles, parallelograms and triangles. Find the areas of trapezoids, kites and rhombuses.

Area Theorems Area of a Square —The area of a square is the product of its side squared. A = s(s)

Area Theorems Area of a Rectangle —The area of a rectangle is the product of its base and height. h b A = bh

Area Theorems Area of a Parallelogram—The area of a parallelogram is the product of a base and height. h b A = bh

Area Theorems Area of a Triangle—The area of a triangle is one half the product of a base and height. h b A = ½ bh

Justification You can justify the area formulas for triangles follows. The area of a triangle is half the area of a parallelogram with the same base and height.

Ex. 1 Using the Area Theorems Find the area of ABCD. Solution: Method 1: Use AB as the base. So, b=16 and h=9 Area=bh=16(9) = 144 square units. Method 2: Use AD as the base. So, b=12 and h=12 Area=bh=12(12)= 144 square units. Notice that you get the same area with either base. 9

Ex. 2: Finding the height of a Triangle Rewrite the formula for the area of a triangle in terms of h. Then use your formula to find the height of a triangle that has an area of 12 and a base length of 6. Solution: Rewrite the area formula so h is alone on one side of the equation. A= ½ bh Formula for the area of a triangle 2A=bh Multiply both sides by 2. 2A=h Divide both sides by b. b Substitute 12 for A and 6 for b to find the height of the triangle. h=2A = 2(12) = 24 = 4 b 6 6 The height of the triangle is 4.

Ex. 3: Finding the Height of a Triangle A triangle has an area of 52 square feet and a base of 13 feet. Are all triangles with these dimensions congruent? Solution: Using the formula from Ex. 2, the height is h = 2(52) = 104 =8 13 13 Here are a few triangles with these dimensions: 8 8 8 8 13 13 13 13

Areas of Trapezoids Area of a Trapezoid—The area of a trapezoid is one half the product of the height and the sum of the bases. A = ½ h(b1 + b2) b1 h b2

Areas of Kites Area of a Kite — d1 Area of a Kite — The area of a kite is one half the product of the lengths of its diagonals. A = ½ d1d2 d2

Areas of Rhombuses Area of a Rhombus —The area of a rhombus is one half the product of the lengths of the diagonals. A = ½ d1 d2 d2 d1

Ex. 4: Finding the Area of a Trapezoid Find the area of trapezoid WXYZ. Solution: The height of WXYZ is h=5 – 1 = 4 Find the lengths of the bases. b1 = YZ = 5 – 2 = 3 b2 = XW = 8 – 1 = 7

Ex. 5 Finding the area of a rhombus Use the information given in the diagram to find the area of rhombus ABCD. Solution— Method 1: Use the formula for the area of a rhombus d1 = BD = 30 and d2 = AC =40 15 20 20 A C 24 15 D E

Ex. 5 Finding the area of a rhombus A = ½ d1 d2 A = ½ (30)(40) A = ½ (120) A = 60 square units Method 2: Use the formula for the area of a parallelogram, b=25 and h = 24. A = bh = 25(24) = 600 square units 15 20 20 A C 24 15 D E

ROOF Find the area of the roof ROOF Find the area of the roof. G, H, and K are trapezoids and J is a triangle. The hidden back and left sides of the roof are the same as the front and right sides.

SOLUTION: Area of J = ½ (20)(9) = 90 ft2. Area of G = ½ (15)(20+30) = 375 ft2. Area of H = ½ (15)(42+50) = 690 ft2. Area of K = ½ (12)(30+42) = 432 ft2. The roof has two congruent faces of each type. Total area=2(90+375+690+432)=3174 The total area of the roof is 3174 square feet.