Inheritance & Polymorphism

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Copyright © 2012 Pearson Education, Inc. Chapter 15: Inheritance, Polymorphism, and Virtual Functions.
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Presentation transcript:

Inheritance & Polymorphism Visit for more Learning Resources

OOP Concepts Objects and Classes / Data Encapsulation Inheritance Polymorphism Operator overloading is a kind of polymorphism

Polymorphism A function/operator can behave differently depending on the context in which it is called We have already seen operator overloading in which a single ‘+’ operator behaves differently when used with floats, ints or strings Polymorphism refers to the ability of similar objects to respond differently to the same message i.e., the same type of function call Selecting the correct function is deferred until runtime and is based on the object

Upcasting Inheritance represents an “is-a” relationship The new class is a type of the existing class enum note { middleC, Csharp, Cflat }; class Instrument { public: void play(note) const {} }; // Wind objects are also Instruments class Wind : public Instrument {}; void tune(Instrument& i) { // ... i.play(middleC); } int main() { Wind flute; tune(flute); // Upcasting

Upcasting (contd..) A Wind object is also an Instrument object, and there’s no function that tune( ) could call for an Instrument that isn’t also in Wind Inside tune( ), the code works for Instrument and anything derived from Instrument, and the act of converting a Wind object, reference, or pointer into an Instrument object, reference, or pointer is called upcasting

Pointer and Reference Upcasting Wind w; Instrument* ip = &w; // Upcast Instrument& ir = w; // Upcast Of course, any upcast loses type information about an object. If you say Instrument* ip = &w; the compiler can deal with ip only as an Instrument pointer and nothing else i.e., it cannot know that ip actually points to a Wind object So when you call the play( ) member function by saying ip->play(middleC); the compiler can know only that it’s calling play( ) for an Instrument pointer, and call the base-class version of Instrument::play( ) instead of what it should do, which is call Wind::play( )

Problem with upcasting enum note { middleC, Csharp, Cflat }; class Instrument { public: void play(note) const { cout << "Instrument::play" << endl; } }; class Wind : public Instrument { cout << "Wind::play" << endl; void tune(Instrument& i) { // ... i.play(middleC); int main() { Wind flute; tune(flute); // Upcasting }

Problem with upcasting The output of the previous program is Instrument::play This is clearly not the desired output, because you know that the object is actually a Wind and not just an Instrument The call should resolve to Wind::play The above discussion also applies if you use a pointer to an Instrument in the function tune

Function call binding Connecting a function call to a function body is called binding When binding is performed before the program is run (by the compiler and linker), it’s called early binding or static binding The problem in the above program is caused by early binding because the compiler cannot know the correct function to call when it has only an Instrument address

Dynamic Binding The solution to the above problem is called late binding or dynamic binding which means the binding occurs at runtime, based on the type of the object When a language implements late binding, there must be some mechanism to determine the type of the object at runtime and call the appropriate member function The compiler still doesn’t know the actual object type, but it inserts code that finds out and calls the correct function body Implemented in C++ using virtual functions

Virtual Functions Virtual Functions enable run time object determination Keyword virtual instructs the compiler to use late binding and delay the object interpretation How ? Define a virtual function in the base class. The word virtual appears only in the base class If a base class declares a virtual function, it must implement that function, even if the body is empty Virtual function in base class stays virtual in all the derived classes It can be overridden in the derived classes But, a derived class is not required to re-implement a virtual function. If it does not, the base class version is used

Virtual Functions enum note { middleC, Csharp, Cflat }; class Instrument { public: virtual void play(note) const { cout << "Instrument::play" << endl; } }; class Wind : public Instrument { void play(note) const { cout << "Wind::play" << endl; void tune(Instrument& i) { // ... i.play(middleC); int main() { Wind flute; tune(flute); // prints Wind::play

Extensibility With play( ) defined as virtual in the base class, you can add as many new types as you want to the system without changing the tune( ) function Such a program is extensible because you can add new functionality by inheriting new data types from the common base class The functions that manipulate the base-class interface will not need to be changed at all to accommodate the new classes

Extensibility enum note { middleC, Csharp, Cflat }; class Instrument { public: virtual void play(note) const { cout << "Instrument::play" << endl; } virtual char* what() const { return "Instrument"; virtual void adjust(int) {} }; class Wind : public Instrument { void play(note) const { cout << "Wind::play" << endl; char* what() const { return "Wind"; } void adjust(int) {}

class Percussion : public Instrument { public: void play(note) const { cout << "Percussion::play" << endl; } char* what() const { return "Percussion"; } void adjust(int) {} }; class Stringed : public Instrument { cout << "Stringed::play" << endl; char* what() const { return "Stringed"; } class Brass : public Wind { cout << "Brass::play" << endl; char* what() const { return "Brass"; } };

class Woodwind : public Wind { public: void play(note) const { cout << "Woodwind::play" << endl; } char* what() const { return "Woodwind"; } }; void tune(Instrument& i) { // ... i.play(middleC); int main() { Wind flute; Percussion drum; Stringed violin; Brass flugelhorn; Woodwind recorder; tune(flute); tune(drum); tune(violin); tune(flugelhorn); tune(recorder);

Virtual functions work only with addresses (references / pointers) class Base { public: virtual int f() const { return 1; } void g()const { cout<<“Base”; } };  class Derived : public Base { int f() const { return 2; } void show(){ cout<<“derived only”; } void g() { cout<<“derived”; } };

Virtual functions work only with addresses (references / pointers) void main() { Derived d; Base* b1 = &d; Base& b2 = d; Base b3; // Late binding: cout << "b1->f() = " << b1->f() << endl; cout << "b2.f() = " << b2.f() << endl; // Early binding: cout << "b3.f() = " << b3.f() << endl; cout<<“b1->g() = ” ; b1->g(); cout<<endl; cout<<“b1->show()=”; b1->show(); }

Arrays of Pointers to Objects class Base { public: virtual void show() { cout<<"base“; } }; class Derv1 : public Base { void show() { cout<<"derv1“; }; class Derv2 : public Base { cout<<"derv2“; } void main() { Base* array[2]; Derv1 d1; Derv2 d2; array[0] = &d1; array[1] = &d2; for(int i=0;i<2;i++) array[i]->show(); getch(); }

Object Slicing If you use an object instead of a pointer or reference as the recipient of your upcast, the object is “sliced” class Base { int i; public: Base(int ii = 0) : i(ii) {} virtual int sum() const { return i; } }; class Derived : public Base { int j; Derived(int ii = 0, int jj = 0): Base(ii),j(jj) {} int sum() const { return Base::sum() + j; }}; void call(Base b) { cout << "sum = " << b.sum() << endl; } int main() { Base b(10); Derived d(10, 47); call(b); call(d);

Polymorphism Summary When you use virtual functions, compiler stores additional information about the types of object available and created Polymorphism is supported at this additional overhead Important : virtual functions work only with pointers/references Not with objects even if the function is virtual

Abstract Classes & Pure Virtual Functions Some classes exist logically but not physically. Example : Shape Shape s; // Legal but silly..!! : “Shapeless shape” Shape makes sense only as a base of some classes derived from it. Serves as a “category” Hence instantiation of such a class must be prevented A class with one or more pure virtual functions is an Abstract Class Objects of abstract class can’t be created class Shape //Abstract { public : //Pure virtual Function virtual void draw() = 0; } Shape s; // error : variable of an abstract class

Example Shape virtual void draw() Circle Triangle public void draw()

Abstract Classes & Pure Virtual Functions A pure virtual function not defined in the derived class remains a pure virtual function. Hence derived class also becomes abstract class Circle : public Shape { //No draw() - Abstract public : void print(){ cout << “I am a circle” << endl; } class Rectangle : public Shape { public : void draw(){ // Override Shape::draw() cout << “Drawing Rectangle” << endl; } Rectangle r; // Valid Circle c; // error : variable of an abstract class

Abstract classes If a method is to be over-ridden by each child class, we can enforce this policy through the use of abstract classes You can’t create an object of an abstract class ( a class with at least one pure virtual function) You can also not pass or return an object of an abstract class by value

Abstract classes It is still possible to provide definition of a pure virtual function in the base class The class still remains abstract and functions must be redefined in the derived classes, but a common piece of code can be kept there to facilitate reuse class Shape { //Abstract public : virtual void draw() = 0; }; Shape::draw(){ cout << “Shape" << endl; } class Rectangle : public Shape { public : void draw(){ Shape::draw(); //Reuse cout <<“Rectangle”<< endl; }

Virtual Destructor If any of the functions in your class are virtual, the destructor should be virtual as well class Base { public: virtual ~Base() { cout << "~Base()" << endl; } }; class Derived : public Base { ~Derived() { cout << "~Derived()" << endl; int main() { Base* bp = new Derived; // Upcast delete bp; // Virtual destructor call

Things to remember Beginning a class method declaration with the keyword virtual in a base class makes the function virtual for the base class and all derived classes, classes further derived from derived classes, and so on… dynamic binding is possible only for a base class pointer or reference to an object of the derived class All those functions of the base class that need to be over-ridden in the derived classes should be made virtual Constructors cannot be virtual Destructors can be virtual You should provide a base class which has virtual functions with a virtual destructor even if the class does not need a destructor (i.e., it does not contain dynamic data)

Things to remember friends can’t be virtual since they are not member functions If a derived class does not redefine a virtual function, the base class version is used. If there is a chain of derived classes, then the most recently defined version of the virtual function is used An abstract class demands that its pure virtual functions must be over-ridden in each derived class, otherwise the derived class also becomes abstract

Inheritance and Dynamic Memory Allocation If a base class uses dynamic memory allocation and redefines assignment operator and copy constructor, how does it affect the implementation of the derived class? If the derived class does not itself use dynamic memory allocation, no special steps need to be taken If the derived class uses dynamic memory allocation, then the assignment operator and copy constructor need to be defined for the derived class as well

If the derived class does not use new class base { private: char* label; int rating; public: base(const char* l = "null",int r = 0); base(const base& rs); virtual ~base(); base& operator = (const base& rs); }; class lacksDMA : public base char color[40]; ...

If the derived class does not use new There’s no need for defining a destructor. The default destructor will automatically call the base class destructor which will free the memory allocated in the base part of the object There’s no need for defining a copy constructor since the default copy constructor will automatically call the base class copy constructor for copying the base part of the object Assignment operator overloading is also not required for the same reason

If the derived class does use new class hasDMA : public base { private: char* style; //to point to dynamic memory public: ... }; For this class, you will have to define destructor, copy constructor and assignment operator

If the derived class uses new Destructor base::~base() { delete [] label; } hasDMA::~hasDMA() delete[] style;

If the derived class uses new Copy Constructor base::base(const base& rs) { label = new char[strlen(rs.label)+1]; strcpy(label,rs.label); rating = rs.rating; } hasDMA::hasDMA(const hasDMA& hs) : base(hs) style = new char[strlen(hs.style)+1]; strcpy(style,hs.style);

If the derived class uses new Assignment Operator base& base::operator=(const base& rs) { if(this==&rs) return *this; delete [] label; label = new char[strlen(rs.label)+1]; strcpy(label,rs.label); rating = rs.rating; } hasDMA& hasDMA::operator=(const hasDMA& hs) if(this==&hs) base::operator=(hs); //copy base style = new char[strlen(hs.style)+1]; strcpy(style,hs.style);

stream operators ostream& operator<<(ostream& os,const base& rs) //declared friend in class base { os<<"Label: " <<rs.label << endl; os << "Rating: " << rs.rating << endl; return os; } ostream& operator<<(ostream& os,const lacksDMA& rs) //declared friend in lacksDMA os << (const base& )rs; //type casting //lacksDMA parameter to base argument os << "Color: " <<rs.color << endl;

stream operators ostream& operator<< (ostream& os, const hasDMA& rs) //declared friend in hasDMA { os << (const base& )rs; //type casting //hasDMA parameter to base argument os << "Style: " <<rs.style << endl; return os; }

Recommended Reading Bruce Eckel’s “Thinking in C++” available online at http://www.codeguru.com/cpp/tic/tic_c.shtml

How C++ implements virtual binding

How C++ implements virtual binding

Cost of Polymorphism VTABLE for every polymorphic class VPTR embedded in every polymorphic object Indirect function access

Another Example class Base { public: virtual void function1() {};    class D1: public Base     void function1() {}; class D2: public Base     void function2() {};

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