o Problem Qoven Obtain the closed loop control diagram. Gc(s)=Kp

Slides:



Advertisements
Similar presentations
Dynamic Behavior of Closed-Loop Control Systems
Advertisements

Closed-Loop Transfer Functions
Dynamic Behavior of Closed-Loop Control Systems
The First Law of Thermodynamics
CHAPTER V CONTROL SYSTEMS
ENERGY CONVERSION ES 832a Eric Savory Lecture 11 – A small-scale power plant worked example Department of Mechanical.
1 Dept. of Energy Technology, Div. of Applied Thermodynamics and Refrigeration Tube diameter influence on heat exchanger performance and design. Single.
Chapter 11 1 Closed-Loop Responses of Simple Control Systems In this section we consider the dynamic behavior of several elementary control problems for.
Control System Instrumentation
Specific Heat. Names Specific Heat Capacity Specific Heat Heat Capacity.
Heather Instasi Tulio Borel. Objectives Design a radiant heating system for a greenhouse located in Atascadero, CA Hot ethylene-glycol solution flowing.
DIFFERENTIAL MANOMETER
Assignment No. 1 [Grup 8] Figure below shows a portion of a hydraulic circuit. The pressure point B must be 200 psig when the volume flow rate is 60 gal/min.
Density and Air Pressure Demonstrations. Demonstration 1 (pg. 7): The air is made up of: 78% Nitrogen 21% Oxygen 1% Other Gases.
Water piping design.
FEASIBILITY OF COMPONENTS CLARA ECHAVARRIA & JONATHON LOCKE.
For Cardinal Newman Hall Randall Lessard ET Fall 2013 Dr. Cris Koutsougeras Advisors: Dr. Rana Mitra Mr. Byron Patterson.
Heat transfer in turbulent flow CL Aim To determine the overall heat transfer coefficient & the individual film transfer coefficient and verify.
Rates in Fluid Systems Volume Flow Rate = Δ in volume / time interval V = ΔV / Δt = cross sectional area x fluid speed V = Aν – Units of measurement: m.
INTRODUCTION TO CONTROL SYSTEMS
The oven given in the figure is heated with a heat source having the heat flow rate Q. The total heat capacity of all objects in the oven is C and the.
Bernoulli’s Principle. Usually, liquids are considered “incompressible”, meaning that the density of the liquid remains nearly constant. Gases are easily.
M4 -Group 9 Teoh Jie Shun Dominic Cheong Johnny Yeung.
Control System Instrumentation
CHAPTER 5: Mass and Energy Analysis of Control Volumes
HOMEWORK 08D Block diagrams Problem 1: Problem 2:
ME421 Heat Exchanger Design

Specify domain’s starting fluid temperature on the Initial pane Porewater temperature is 40 °C.
AGUS HARYANTO 01 March  Examine the moving boundary work or P.dV work.  Identify the first law of thermodynamics for closed (fixed mass) systems.
Interacting vs. Noninteracting Systems
o Problem Reconsider Problem
Industrial Electronic Department Copyright of German Malaysian Institute. All rights reserved.
Solar Heating/Cooling/Dehumidifier Systems
O o Problem HOMEWORK-01 Establish the closed loop block diagram. G c (s)=K p Answer: The oven shown in the figure is heated with a source having.
Lecture Objectives: Answer question related to Project 1 Finish with thermal storage systems Learn about plumbing systems.
Porewater temperature is 40°C Specify domain’s starting fluid temperature on the Initial pane.
Lecture 6: Thermal and Fluid System. Heat Flow.
Date of download: 6/23/2016 Copyright © ASME. All rights reserved. From: Heat Transfer and Pressure Drop Analysis of Chilled Water and Ice Slurry in a.
Date of download: 6/28/2016 Copyright © ASME. All rights reserved. From: Convective Heat Transfer and Contact Resistances Effects on Performance of Conventional.
Solution to Homework 1 qi h1 h2 q1 qo a1 a2 v1 v2
Control System Instrumentation
Design of the thermosiphon Test Facilities 2nd Thermosiphon Workshop
CHAPTER V CONTROL SYSTEMS
Controllers and Positioners
Date of download: 10/22/2017 Copyright © ASME. All rights reserved.
Date of download: 11/8/2017 Copyright © ASME. All rights reserved.
Do Now A raft is made of a plastic block with a density of 650 kg/m3, and its dimensions are 2.00 m × 3.00 m × 5.00 m. What is the force of buoyancy on.
Date of download: 11/12/2017 Copyright © ASME. All rights reserved.
Energy Systems An energy system is a method by which energy is transferred and work is done. There are four basic types of energy systems: Mechanical Fluid.
Date of download: 12/19/2017 Copyright © ASME. All rights reserved.
Chapter 5 The First Law of Thermodynamics for Opened Systems
Exergy analysis of geothermal Energy
Control System Instrumentation
Comparison between Serrated & Notched Serrated Heat Exchanger Fin Performance Presented by NABILA RUBAIYA.
Control System Instrumentation
Mass and Energy Analysis of Control Volumes (Open Systems)
1st Law of Thermodynamics
LECTURE #5 System Modeling& Responses
HW-03 Problem Kuo-95 (p. 377) Find the steady-state errors for step, ramp and parabolic inputs. Determine the type of the system. ) s ( R Problem.
50 m EML3015C Thermal-Fluid I Fall 2000 Homework 4
Internal Flow: General Considerations
Introduction to Control Systems
ENERGY CONVERSION ES 832a Eric Savory
Interacting vs. Noninteracting Systems
o Problem Reconsider Problem
Exercise 2-1 For the level controlled process, h2 is selected as its controlled variable, and Qin is the main input of the process. Suppose the sectional.
HOMEWORK-01 Problem The oven shown in the figure is heated with a source having thermal flow of Q. Total thermal capacitance in the oven is C, thermal.
12. Heat Exchangers Chemical engineering 170.
HOMEWORK-03 Problem Kuo-95 (p. 377)
Presentation transcript:

o Problem 01-01 Qoven Obtain the closed loop control diagram. Gc(s)=Kp HOMEWORK-01 Problem 01-01 o The oven given in the figure is heated with a heat source having the heat flow rate Q. The total heat capacity of all objects in the oven is C and the thermal isolation between the oven and its environment is R. To is the temparature of the medium around the oven (air). The temperature in the oven is T. The heat flow rate can be controlled electrically as Q=K1V1 , where V1 is the applied voltage and K1 is the control coefficient. The temperature of the oven is measured by a thermistor as the voltage V2 and V2=K2T , where K2 is the sensor constant. The heat loss between the oven and its environment is 0.5 kJ/s for the difference of 1 ̊C. The heat required to increase the temperature of the objects of 1 ̊C in the oven is 2 kJ. The heat flow rate is obtained as Q=30 kJ/s when 4 volts are applied to the heat source. The thermistor gives 4 volts for 80 oC temperature in th eoven. Qoven Obtain the closed loop control diagram. Gc(s)=Kp Q Heat transfer to environment Heat transfer to objects in the oven Qwall Answer: QWatt HJoule

Electro-pneumatic member Problem 01-02 (Kuo, p.195) Hot water source Electro-pneumatic member Controller Heat exchanger Aspirator Air inlet, TAi Heated air, TAo Temperature sensor, Ts Tw: Water temperature Sensor Heat Exchanger Fill the missing blocks for the closed loop control diagram of the air heating system: Answer:

Transfer function from Q=Q1+Qd to h1 C (Q1+Qd) The water tank shown in the figure is filled with a source having the flow rate Q1. The capacity of the tank is C=A/ρg. A is the cross section area of the tank, ρ is the density of the fluid and g is the gravity. The output flow rate is Q2 . The pressure drop at the outlet is ∆p2=RQ2 and the water level in the tank is h1 . The open loop control diagram is given below as the V1 is input and V2 is the output. V1 is the input voltage (command signal) and V2 is the measured voltage (sensor output). Qd is the uncontrolled input (disturbance). Obtain the closed loop control diagram of the fluid-level control system. Problem 01-03 h1 Area A Pa (Disturbance) (atmospheric pressure) (pressure difference) Answer: Transfer function from Q=Q1+Qd to h1 C (Q1+Qd) (input flow) (level measurement) (error signal) (command signal) (controller) (water tank) (disturbance, rain etc.) (actuator/vane) (sensor) (water level) (sensor output) (reference signal)