03/02/2006 Flow Routing Reading: 8.1, 8.4, 9.1, 9.2.

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03/02/2006 Flow Routing Reading: 8.1, 8.4, 9.1, 9.2

Flow Routing Q t Procedure to determine the flow hydrograph at a point on a watershed from a known hydrograph upstream As the hydrograph travels, it attenuates gets delayed Q t Q t Q t

Why route flows? Q t Account for changes in flow hydrograph as a flood wave passes downstream This helps in Accounting for storages Studying the attenuation of flood peaks

Types of flow routing Lumped/hydrologic Distributed/hydraulic Flow is calculated as a function of time alone at a particular location Governed by continuity equation and flow/storage relationship Distributed/hydraulic Flow is calculated as a function of space and time throughout the system Governed by continuity and momentum equations

Downstream hydrograph Hydrologic Routing Discharge Inflow Discharge Outflow Transfer Function Upstream hydrograph Downstream hydrograph Input, output, and storage are related by continuity equation: Q and S are unknown Storage can be expressed as a function of I(t) or Q(t) or both For a linear reservoir, S=kQ

Lumped flow routing Three types Level pool method (Modified Puls) Storage is nonlinear function of Q Muskingum method Storage is linear function of I and Q Series of reservoir models Storage is linear function of Q and its time derivatives

S and Q relationships

Level pool routing Procedure for calculating outflow hydrograph Q(t) from a reservoir with horizontal water surface, given its inflow hydrograph I(t) and storage-outflow relationship

Hydrologic river routing (Muskingum Method) Wedge storage in reach Advancing Flood Wave I > Q K = travel time of peak through the reach X = weight on inflow versus outflow (0 ≤ X ≤ 0.5) X = 0  Reservoir, storage depends on outflow, no wedge X = 0.0 - 0.3  Natural stream Receding Flood Wave Q > I

Muskingum Method (Cont.) Recall: Combine: If I(t), K and X are known, Q(t) can be calculated using above equations

Muskingum - Example Given: Find: Inflow hydrograph K = 2.3 hr, X = 0.15, Dt = 1 hour, Initial Q = 85 cfs Find: Outflow hydrograph using Muskingum routing method

Muskingum – Example (Cont.) C1 = 0.0631, C2 = 0.3442, C3 = 0.5927