Properties of Parallelograms

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Properties of Parallelograms 6-2 Properties of Parallelograms Warm Up Lesson Presentation Lesson Quiz Holt Geometry

Find the value of each variable. 6.2 Properties of Parallelograms Warm Up Find the value of each variable. 1. x 2. y 3. z 2 4 18

Objectives Prove and apply properties of parallelograms. Use properties of parallelograms to solve problems.

6.2 Properties of Parallelograms Vocabulary parallelogram

6.2 Properties of Parallelograms Any polygon with four sides is a quadrilateral. However, some quadrilaterals have special properties. These special quadrilaterals are given their own names.

6.2 Properties of Parallelograms Opposite sides of a quadrilateral do not share a vertex. Opposite angles do not share a side. Helpful Hint

6.2 Properties of Parallelograms A quadrilateral with two pairs of parallel sides is a parallelogram. To write the name of a parallelogram, you use the symbol .

6.2 Properties of Parallelograms

6.2 Properties of Parallelograms

Example 1A: Properties of Parallelograms In CDEF, DE = 74 mm, DG = 31 mm, and mFCD = 42°. Find CF.  opp. sides  CF = DE Def. of  segs. CF = 74 mm Substitute 74 for DE.

Example 1B: Properties of Parallelograms In CDEF, DE = 74 mm, DG = 31 mm, and mFCD = 42°. Find mEFC. mEFC + mFCD = 180°  cons. s supp. mEFC + 42 = 180 Substitute 42 for mFCD. mEFC = 138° Subtract 42 from both sides.

Example 1C: Properties of Parallelograms In CDEF, DE = 74 mm, DG = 31 mm, and mFCD = 42°. Find DF. DF = 2DG  diags. bisect each other. DF = 2(31) Substitute 31 for DG. DF = 62 Simplify.

6.2 Properties of Parallelograms Check It Out! Example 1a In KLMN, LM = 28 in., LN = 26 in., and mLKN = 74°. Find KN.  opp. sides  LM = KN Def. of  segs. LM = 28 in. Substitute 28 for DE.

6.2 Properties of Parallelograms Check It Out! Example 1b In KLMN, LM = 28 in., LN = 26 in., and mLKN = 74°. Find mNML. NML  LKN  opp. s  mNML = mLKN Def. of  s. mNML = 74° Substitute 74° for mLKN. Def. of angles.

6.2 Properties of Parallelograms Check It Out! Example 1c In KLMN, LM = 28 in., LN = 26 in., and mLKN = 74°. Find LO. LN = 2LO  diags. bisect each other. 26 = 2LO Substitute 26 for LN. LO = 13 in. Simplify.

Example 2A: Using Properties of Parallelograms to Find Measures WXYZ is a parallelogram. Find YZ.  opp. s  YZ = XW Def. of  segs. 8a – 4 = 6a + 10 Substitute the given values. Subtract 6a from both sides and add 4 to both sides. 2a = 14 a = 7 Divide both sides by 2. YZ = 8a – 4 = 8(7) – 4 = 52

Example 2B: Using Properties of Parallelograms to Find Measures WXYZ is a parallelogram. Find mZ . mZ + mW = 180°  cons. s supp. (9b + 2) + (18b – 11) = 180 Substitute the given values. 27b – 9 = 180 Combine like terms. 27b = 189 Add 9 to both sides. b = 7 Divide by 27. mZ = (9b + 2)° = [9(7) + 2]° = 65°

6.2 Properties of Parallelograms Check It Out! Example 2a EFGH is a parallelogram. Find JG.  diags. bisect each other. EJ = JG Def. of  segs. 3w = w + 8 Substitute. 2w = 8 Simplify. w = 4 Divide both sides by 2. JG = w + 8 = 4 + 8 = 12

6.2 Properties of Parallelograms Check It Out! Example 2b EFGH is a parallelogram. Find FH.  diags. bisect each other. FJ = JH Def. of  segs. 4z – 9 = 2z Substitute. 2z = 9 Simplify. z = 4.5 Divide both sides by 2. FH = (4z – 9) + (2z) = 4(4.5) – 9 + 2(4.5) = 18

6.2 Properties of Parallelograms When you are drawing a figure in the coordinate plane, the name ABCD gives the order of the vertices. Remember!

Example 4A: Using Properties of Parallelograms in a Proof Write a two-column proof. Given: ABCD is a parallelogram. Prove: ∆AEB  ∆CED

6.2 Properties of Parallelograms Example 4A Continued Proof: Statements Reasons 1. ABCD is a parallelogram 1. Given 2.  opp. sides  3.  diags. bisect each other 4. SSS Steps 2, 3

Example 4B: Using Properties of Parallelograms in a Proof Write a two-column proof. Given: GHJN and JKLM are parallelograms. H and M are collinear. N and K are collinear. Prove: H M

6.2 Properties of Parallelograms Example 4B Continued Proof: Statements Reasons 1. GHJN and JKLM are parallelograms. 1. Given 2. H and HJN are supp. M and MJK are supp. 2.  cons. s supp. 3. HJN  MJK 3. Vert. s Thm. 4. H  M 4.  Supps. Thm.

6.2 Properties of Parallelograms Check It Out! Example 4 Write a two-column proof. Given: GHJN and JKLM are parallelograms. H and M are collinear. N and K are collinear. Prove: N  K

Check It Out! Example 4 Continued 6.2 Properties of Parallelograms Check It Out! Example 4 Continued Proof: Statements Reasons 1. GHJN and JKLM are parallelograms. 1. Given 2. N and HJN are supp. K and MJK are supp. 2.  cons. s supp. 3. HJN  MJK 3. Vert. s Thm. 4. N  K 4.  Supps. Thm.

6.2 Properties of Parallelograms Lesson Quiz: Part I In PNWL, NW = 12, PM = 9, and mWLP = 144°. Find each measure. 1. PW 2. mPNW 18 144°

6.2 Properties of Parallelograms Lesson Quiz: Part II QRST is a parallelogram. Find each measure. 2. TQ 3. mT 71° 28

6.2 Properties of Parallelograms Lesson Quiz: Part III 6. Write a two-column proof. Given: RSTU is a parallelogram. Prove: ∆RSU  ∆TUS Statements Reasons 1. RSTU is a parallelogram. 1. Given 4. SAS 4. ∆RSU  ∆TUS 3. R  T 2.  cons. s  3.  opp. s 