5.6 Complex Numbers.

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Presentation transcript:

5.6 Complex Numbers

Complex number: a + bi where a is the real number part and bi is the imaginary number part

imaginary number (i)

Ex 1

Ex 2 Write in a + bi form

Ex 3 Find the additive inverse of -7 – 9i

Ex 4 (6 – 2i) + (-5 + i) (3 + 6i) – (4 – 8i)

Ex 5 (3i)(8i) (3i)(-5 + 2i) (4 + 3i)(-1 – 2i)

MEMORIZE!!!!!!!!!!

Simplify i47

Solve: 9x2 + 54 = 0 Factor: x2 + 81 Factor: 2x2 + 32

(a + bi) and (a – bi) are called complex conjugates The product of complex conjugates is a REAL number. (2 + 3i)(2 – 3i) Why can you not have ‘i’ in the denominator of a fraction?

Simplify:

Think: Explain the difference between the additive inverse of a complex number and a complex conjugate.