Chapter 9 Electronic Structure and Periodic Trends

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Presentation transcript:

Chapter 9 Electronic Structure and Periodic Trends 9.5 Writing Electron Configurations by using your Periodic Table Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

You can either memorize this… Or, you can use your periodic table to write configurations! K: 1s22s22p63s23p64s1

Sublevel Blocks on the Periodic Table The periodic table consists of sublevel blocks arranged in order of increasing energy. = n - 1 = n - 2

Using Sublevel Blocks To write an electron configuration using sublevel blocks : Locate the element on the periodic table. Then determine the number of electrons. Write each sublevel block in order going left to right across each period starting with H until you reach your element. Write the number of electrons in each block as a superscript

Writing Electron Configurations Using the periodic table, write the electron configuration for silicon (Si has 14 electrons). Solution Period 1 1s block 1s2 Period 2 2s → 2p blocks 2s2 2p6 Period 3 3s → 3p blocks 3s2 3p2 (at Si) Writing all the sublevel blocks in order gives: 1s2 2s2 2p63s2 3p2

Electron Configurations d Sublevel Overlaps begin to occur, where higher sublevels like 4s get electrons before the lower d is filled Notice that when doing an EC for an element in the d block or when moving through the d block, the energy level is ONE LESS than the s and p for that period 1s 2s 2p 3s 3p 3d 4s Ar 1s2 2s2 2p6 3s2 3p6 K 1s2 2s2 2p6 3s2 3p6 4s1 Ca 1s2 2s2 2p6 3s2 3p6 4s2 Sc 1s2 2s2 2p6 3s2 3p6 3d1 4s2 Ti 1s2 2s2 2p6 3s2 3p6 3d2 4s2

Writing Electron Configurations Using the periodic table, write the electron configuration for manganese. Solution Period 1 1s block 1s2 Period 2 2s → 2p blocks 2s2 2p6 Period 3 3s → 3p blocks 3s2 3p6 Period 4 4s → 3d blocks 4s2 3d5 (at Mn) Writing all the sublevel blocks in order gives: 1s2 2s2 2p63s2 3p6 4s2 3d5

Sublevel Blocks on the Periodic Table Notice for the d block, the energy level is ONE LESS than for the s and p, and TWO LESS for the f block = n - 1 = n - 2

Writing Electron Configurations Using the periodic table, write the electron configuration for iodine: Solution Period 1 1s block 1s2 Period 2 2s → 2p blocks 2s2 2p6 Period 3 3s → 3p blocks 3s2 3p6 Period 4 4s → 3d → 3p blocks 4s2 3d10 4p6 Period 5 5s → 4d → 5p blocks 5s2 4d10 5p5 Writing all the sublevel blocks in order gives: 1s2 2s2 2p63s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5 (iodine)

Learning Check A. The last two sublevels blocks in the electron configuration for Co are 1) 3p64s2 2) 4s24d7 3) 4s23d7 B. The last three sublevel blocks in the electron configuration for Sn are 1) 5s25p24d10 2) 5s24d105p2 3) 5s25d105p2

Solutions A. The last two sublevels blocks in the electron configuration for Co are 3) 4s23d7 B. The last three sublevel blocks in the electron configuration for Sn are 2) 5s24d105p2

Abbreviated configurations: An abbreviated configuration shows The symbol of the noble gas [in brackets] that comes BEFORE the element you are working on Noble gases always have FULL energy sublevels, so that is why they are used for the abbreviation The remaining electrons in order of their sublevels. Example: Chlorine has a configuration of 1s2 2s2 2p6 3s2 3p5 [Ne] The abbreviated configuration for chlorine is [Ne] 3s2 3p5

Some examples:

Learning Check Using the periodic table, write the electron configuration and abbreviated configuration for each of the following elements: A. Zn B. Sr C. I

Solution A. Zn 1s2 2s2 2p6 3s2 3p6 4s2 3d10 [Ar] 4s2 3d10 B. Sr 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 [Kr] 5s2 C. I 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5 [Kr] 5s2 4d10 5p5

Learning Check Write the abbreviated configuration for each of the following elements: A. Cl B. S C. K

Solution A. Cl = [Ne] 3s23p5 B. S = [Ne] 3s2 3p4 C. K = [Ar]4s1

Learning Check Give the symbol of the element that has A. [Ar]4s2 3d6 B. Four 3p electrons C. Two electrons in the 4d sublevel D. The element that has the electron configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d2

Solution Give the symbol of the element that has A. [Ar]4s2 3d6 Fe B. Four 3p electrons S C. Two electrons in the 4d sublevel Zr D. Electron configuration Ti 1s2 2s2 2p6 3s2 3p6 4s2 3d2