Do Now (Lab Review) What is the specific heat of a metal that has a mass of 60 g and a temp. of 100°C, and when placed into 150 g of water at 23°C, raises.

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Do Now (Lab Review) What is the specific heat of a metal that has a mass of 60 g and a temp. of 100°C, and when placed into 150 g of water at 23°C, raises the water’s temp. to 29°C (meaning the metal cooled to 29°C).

Molecular Structure: Liquids and Solids Matter and Changes of State Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Melting and Freezing A substance Is melting while it changes from a solid to a liquid. Is freezing while it changes from a liquid to a solid. Such as water has a freezing (melting) point of 0°C.

Calculations Using Heat of Fusion The heat of fusion Is the amount of heat released when 1 gram liquid freezes (at its freezing point). Is the amount of heat needed to melt 1 gram solid (at its melting point). For water (at 0°C) is 80 cal 1 g water Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Calculation Using Heat of Fusion The heat to freeze (or melt) a specific mass of water (or ice) is calculated using the heat of fusion. Heat = g water x 80 cal 1 g water Problem: How much heat in CALORIES is needed to melt 15.0 g of ice? 15.0 g ice x 80 cal = 1200 cal 1 g ice

Learning Check A. How many calories are needed to melt 5.00 g ice at 0°C? 1) 50 cal 2) 400 cal 3) 0 cal Answer = 400 (80 x 5) B. How many calories are released when 25.0 g water at 0°C freezes? 1) 2000 cal 2) 0 cal 3) 8000 cal 25g x 80cal = 2000 cal

Solution A. How many calories are needed to melt 5.00 g ice at 0°C? 2) 400 cal 5.00 g x 80 cal 1 g B. How many calories are released when 25.0 g water at 0°C freezes? 1) 2000 cal 25 g x 80 cal

Sublimation Sublimation Occurs when particles absorb heat to change directly from solid to a gas. Is typical of dry ice, which sublimes at -78C. Takes place in frost-free refrigerators. Is used to prepare freeze-dried foods for long-term storage. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Evaporation and Condensation Water Evaporates when molecules on the surface gain sufficient energy to form a gas. Condenses when gas molecules lose energy and form a liquid. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Boiling At boiling, All the water molecules acquire enough energy to form a gas. Bubbles appear throughout the liquid. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Heat of Vaporization The heat of vaporization is the amount of heat Absorbed to vaporize 1 g of a liquid to gas at the boiling point. Released when 1 g of a gas condenses to liquid at the boiling point. Boiling Point of Water = 100°C Heat of Vaporization (water) = 540 cal 1 g water Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Learning Check How many calories are released when 50.0 g steam from a volcano condenses at 100°C? 1) 540 cal 2) 27,000 cal 3) 113,000 cal

Solution How many calories (or kcal) are released when 50.0 g steam in a volcano condenses at 100°C? 2) 27,000 cal 50.0 g steam x 540 cal = 27,000 cal 1 g steam or 27 kcal

Summary of Changes of State Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Heating Curve A heating curve Illustrates the changes of state as a solid is heated. Uses sloped lines to show an increase in temperature. Uses plateaus (flat lines) to indicate a change of state. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Learning Check A. A flat line on a heating curve represents 1) a temperature change 2) a constant temperature 3) a change of state B. A sloped line on a heating curve represents

Solution A. A flat line on a heating curve represents 2) a constant temperature 3) a change of state B. A sloped line on a heating curve represents 1) a temperature change

Cooling Curve A cooling curve Illustrates the changes of state as a gas is cooled. Uses sloped lines to indicate a decrease in temperature. Uses plateaus (flat lines) to indicate a change of state. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

Learning Check Use the cooling curve for water to answer each. A. Water condenses at a temperature of 1) 0°C 2) 50°C 3) 100°C B. At a temperature of 0°C, liquid water 1) freezes 2) melts 3) changes to a gas C. At 40 °C, water is a 1) solid 2) liquid 3) gas D. When water freezes, heat is 1) removed 2) added

Solution Use the cooling curve for water to answer each. A. Water condenses at a temperature of 3) 100°C B. At a temperature of 0°C, liquid water 1) freezes C. At 40 °C, water is a 2) liquid D. When water freezes, heat is 1) removed

Combined Heat Calculations To reduce a fever, an infant is packed in 250. g ice. If the ice (at 0°C) melts and warms to body temperature (37.0°C), how many calories of heat are removed? STEP 1 Diagram the changes. 37°C T = 37.0°C - 0°C = 37.0°C temperature increase 0°C S L melting

Combined Heat Calculations (continued.) STEP 2 Calculate the heat to melt ice (fusion) 250. g ice x 80 cal = 20,000 cal 1 g ice STEP 3 Calculate the heat to warm the water from 0°C to 37.0°C 250. g x 37.0°C x 1 cal = 9250 cal g °C Total: Step 2 + Step 3 = 29,250 cal

Learning Check When a volcano erupts, 175 g steam at 100°C is released. How many kilojoules are lost when the steam condenses and cools to 25°C? 1) 94,500 cal 2) 13,125 cal 3) 107,625 cal

Solution (3) 107,625 cal Steam condenses at 100 C 175 g x 540 cal = 94,500 cal 1 g Water cools 100C to 25C 175 g x 75°C x 1 cal = 13,125 cal g °C 107,625 calories total or 107.6 kcal