Nomenclature for Aliphatic Compounds

Slides:

Advertisements

Similar presentations

Basics of Organic Chemistry. explain that there are many organic compounds because carbon atoms can form four bonds recall the formulae of methane, ethane,

Advertisements

Chapter 11 Introduction to Organic Chemistry: Alkanes

Organic Chemistry Hydrocarbons Organic Chemistry The study of the compounds that contain the element carbon Are numerous due to the bonding capability.

To name an alkane you need to know the number of carbon atoms it contains.

Hydrocarbons *Compounds with just Hydrogen and Carbon.

Organic Chemistry Larry Scheffler Lincoln High School Portland, OR.

Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 17 Organic Chemistry 17.1 Alkanes Compounds in food contain many organic compounds.

Chemistry: An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Chapter 10 Introduction.

Rayat Shikshan Sanstha’s Maharaja Sayajirao Vidyalaya ,Satara

Organic Chemistry. Carbon Review Electron Configuration of Carbon: 1s 2 2s 2 2p 2 Valence Electrons: 4 Shape around a Carbon with all Single Bonds: Lewis.

Carbon Chemistry.

Alkanes and Aromatic Hydrocarbons Branched Alkanes Structural Formulas.

Organic means containing carbon. Originally, scientists believed that the only substances to contain organic compounds were living things as they were.

Naming Alkenes and Alkynes. Recall: Alkenes General Formula = C n H 2n Contain one or more double bonds Names will end in “–ene” Alkynes General Formula.

Unsaturated Hydrocarbons Alkenes CHEMISTRY 11 MS. MCGRATH.

Sample Problem 12.1 Properties of Organic Compounds

What is the difference between them?

Lesson 1: Organic Chemistry

SECTION 3 A: INTRODUCTION

Nomenclature of Organic Compounds

Organic Formulae… Cyclohexane has 6 carbons and 12 hydrogens.

Alkenes At least one double bond present in the main chain

Organic Chemistry = the study of carbon and most carbon compounds.

Topic 6 Organic Chemistry 1

Unit 2 Summery Nature’s Chemistry

Lesson 1: Organic Chemistry

Simple Organic Chemistry

Organic Chemistry.

12.3 Alkanes with Substituents

Naming Organic Compounds

Intro to organic chemistry

1.2 Hydrocarbons Naming Alkanes.

ORGANIC CHEMISTRY.

The following slides should help you with your revision, but should not be your only form of revision. Remember to use your notes, a textbook, websites.

Simple Organic Chemistry Basic Structure and Nomenclature

Organic Compounds (Part 1)

Carbon Chemistry Chapter 9.

Organic Geochemistry.

Naming & Drawing Alkanes

Naming Branched Chain Alkanes, Alkenes, and Alkynes

Organic Compounds (Part 2)

Intro to organic chemistry (orgo)

Intermediate 2 Chemistry

Structural Isomers Compounds that have the same molecular formula, but different structural formula (arrangement of atoms), are called structural isomers.

Organic Chemistry An Introduction.

The basis for organic chemistry

The Chemistry of Carbon A very brief introduction

Chemistry/Physical Setting

Organic Chemistry = the study of carbon and most carbon compounds.

Alkenes and Alkynes Learning Objectives: Keywords:

Some questions on Physical properties of alkanes

Naming Alkanes.

Naming Branched Chain Alkanes, Alkenes, and Alkynes

SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYL CH3 ETHYL

Alkene - Alkyne.

ORGANIC CHEMISTRY.

Organic Chemistry - Introduction

Naming Branched Chain Alkanes, Alkenes, and Alkynes

Chapter 2 Alkanes.

Introduction to Hydrocarbons Alkanes

Organic Chemistry.

Organic Chemistry - Introduction

Isomers C2.4 Organic Compounds.

LATE ABASAHEB KAKADE ART’S & SCIENCE COLLEGE , BODHEGAON

Naming Branched Chain Alkanes, Alkenes, and Alkynes

Simple Organic Chemistry

4.6 Isomerism in alkenes.

Structure of aliphatic hydrocarbons

Presentation transcript:

Nomenclature for Aliphatic Compounds Exercise No. 2 Give possible isomers of the following aliphatic compounds and give their correct structure and IUPAC name By: Dr Vipul B Kataria For F. Y. B. Sc. Semester-I US01CCHE01

H3 C – C – C - C H3 H2 H2 n-Butane H H3 C – C – C H3 – C H3 iso-Butane Always remember: Valency of carbon is 4 (a) C4H10 H3 C – C – C - C H3 H2 H2 1. The general formula for alkane is CnH2n+2 Where n = number of carbon atoms n-Butane 2. Now see the given molecular formula: C4H10 3. Comparing with general formula of alkane 4. Calculation 4 carbons Therefore C4H2(4)+2 = C4H10 H H3 C – C – C H3 – How many carbon atoms? 4 Carbons Arrange in possible chain: Continuous and branched C H3 2. Arrange hydrogens accordingly iso-Butane 3. Name the compounds

C5H12 H3 C – C – C – C - C H3 H2 H2 H2 H2 H C – C – C – C H3 H3 C H3 C Always remember: Valency of carbon is 4 (b) C5H12 H3 C – C – C – C - C H3 H2 H2 H2 1. The general formula for alkane is CnH2n+2 Where n = number of carbon atoms n-Pentane 2. Now see the given molecular formula: C5H12 H2 H 3. Comparing with general formula of alkane C – C – C – C H3 H3 4. Calculation 5 carbons Therefore C5H2(5)+2 = C5H12 C H3 iso-Pentane C H3 How many carbon atoms? 5 Carbons Arrange in possible chain: Continuous and branched C – C – C H3 2. Arrange hydrogens accordingly H3 3. Name the compounds C H3 neo-Pentane

C4H8 H2 C = C – C – C H3 H H H H H3 C – C = C – C H3 C H3 H2 C = C – C Always remember: Valency of carbon is 4 (c) C4H8 H2 C = C – C – C H3 H H 1. The general formula for alkene is CnH2n Where n = number of carbon atoms 1-Butene 2. Now see the given molecular formula: C4H8 3. Comparing with general formula of alkene H H 4. Calculation 4 carbons Therefore C4H2(4) = C4H8 H3 C – C = C – C H3 2-Butene How many carbon atoms? 4 Carbons Arrange in possible chain: Continuous and branched C H3 2. Arrange hydrogens accordingly H2 C = C – C H3 3. Name the compounds H iso-Butene or 2-Methyl-1-propene

C5H10 (d) H2 C = C – C – C - C H3 H H2 H2 1-Pentene C H3 H3 Always remember: Valency of carbon is 4 (d) C5H10 H2 C = C – C – C - C H3 H H2 H2 1-Pentene 1. The general formula for alkene is CnH2n Where n = number of carbon atoms C H3 2. Now see the given molecular formula: C5H10 3. Comparing with general formula of alkene H3 C = C - C – C H3 H3 C - C = C – C - C H3 H2 4. Calculation 5 carbons Therefore C5H2(5) = C5H10 H H H2 2-Methyl-1-Butene 2-Pentene C H3 C H3 1. How many carbon atoms? 5 Carbons Arrange in possible chain: Continuous and branched H2 C = C - C – C H3 H3 C - C = C – C H3 2. Arrange hydrogens accordingly H H 3. Name the compounds 2-Methyl-2-Butene 3-Methyl-1-Butene