Do Now: Kinematic Chart

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Presentation transcript:

Do Now: Kinematic Chart How long will it take an A380 airbus to take off if its take off speed is 280 km/hr? Assume a constant acceleration of 1.0 (m/s)/s. Kinematic Chart Vf Vi t a

Aim: How can we use kinematics Formulas to solve motion problems? HW: Kinematics WS

A380 Airbus Take-Off Distance Given the numbers we already have, how long a runway does it need? Why is this question a little tricky? How have we solved for distance up until now? Average V = (Vf + Vi)/2 ONLY for constant Acc. Now we can solve with V = d/t The velocity is not constant, but rather the plane accelerates up to 78m/s. Instead we first find the average velocity since the acceleration is constant.

Station Activity Read the question at your station and work together to solve it.

Sketch the Velocity Time graph of our Airbus Your sketch should be labeled with the slope, final velocity and time.

What does the Velocity Time graph of our Airbus look like? Remember what the slope for this type of graph is! Sketch the graph! Area under the line for a Velocity Time Graph is distance traveled. The distance is the same if we take it for the constant velocity! Physics works! Sketch the graph on white board… Straight line with slope of 1 m/s/s going to time 78 s and velocity 78 m/s Then draw straight line across cutting in half to show distance under the graph is same for both.

Summary What is the difference between a position vs. time graph and a velocity versus time graph. Hint: Sketch the two graphs for our planes motion. The plane from the Do Now!

Do Now: Calculate Instantaneous Velocity at t = 5 seconds Velocity at a given instant. Instantaneous velocity at a point is slope of the tangents line at that time. Consider writing this example on the board for clarity. Whole Do Now can just be done on the board.

Accelerating off an Aircraft Carrier The runway is about 80 meters long Take off speed for F-18 Hornet is about 260 km/hr. ***What is the required acceleration??? So far students know… Vf = Vi + at and V = dt

What do we know? Vi = 0 Vf = 260 km/hr d = 80 m Average V = d/t Average V = (Vf + Vi)/2 a = ΔV/Δt How can we make or derive an equation for acceleration? Plug average V equation into V = d/t and then plug Acceleration equation into V = d/t for time. Should get Vf2 = Vi2 + 2ad… we have everything except “a” now!