Logarithmic Properties Exponential Function y = bx Logarithmic Function x = by y = logbx Exponential Form Logarithmic Form
Exponential Form Logarithmic Form The logarithm is the exponent to which a base must be raised to give a power. Exponential Form Logarithmic Form 53 = 125 72 = 49 5-2 = 1/25 3-4 = 1/81 9½ = 3 36½ = 6 be = P
Exponential Form Logarithmic Form The logarithm is the exponent to which a base must be raised to give a power. Exponential Form Logarithmic Form 53 = 125 72 = 49 5-2 = 1/25 3-4 = 1/81 9½ = 3 36½ = 6 be = P 3 = log5125 2 = log749 -2 = log5(1/25) -4 = log3 (1/81) ½ = log93 ½= log366 e = logbP
Exponential Form Logarithmic Form The logarithm is the exponent to which a base must be raised to give a power. Exponential Form Logarithmic Form 4 = log381 2 = log864 -2 = log7(1/49) -4 = log2 (1/16) ¼ = log813 1/5 = log322 y = logax
Exponential Form Logarithmic Form The logarithm is the exponent to which a base must be raised to give a power. Exponential Form Logarithmic Form 4 = log381 2 = log864 -2 = log7(1/49) -4 = log2 (1/16) ¼ = log813 1/5 = log322 y = logax 34 = 81 82 = 64 7-2 = 1/49 2-4 = 1/16 81¼ = 3 321/5 = 2 ay = x
Method #1 Method #2
Let 𝑦= 𝑙𝑜𝑔 2 32 𝑙𝑜𝑔 2 32= 𝑙𝑜𝑔 2 2 5 ∴ 𝑙𝑜𝑔 2 32=5 2 𝑦 =32 2 𝑦 = 2 5 𝑦=5 Method #1 Method #2 Write the Argument as a Power of the base of the log Let 𝑦= 𝑙𝑜𝑔 2 32 𝑙𝑜𝑔 2 32= 𝑙𝑜𝑔 2 2 5 Change to Exponential Form The Logarithm is the Exponent ∴ 𝑙𝑜𝑔 2 32=5 2 𝑦 =32 2 𝑦 = 2 5 Equate Exponents 𝑦=5 ∴ 𝑙𝑜𝑔 2 32=5
Ex #2] Evaluate. a) 𝑙𝑜𝑔 3 1 81 b) 𝑙𝑜𝑔 5 1 c) 𝑙𝑜𝑔 1 000 000
Ex #2] Evaluate. = 𝑙𝑜𝑔 5 5 0 = 𝑙𝑜𝑔 3 3 −4 = 𝑙𝑜𝑔 10 10 6 = 0 = - 4 = 6 Ex #2] Evaluate. a) 𝑙𝑜𝑔 3 1 81 b) 𝑙𝑜𝑔 5 1 c) 𝑙𝑜𝑔 1 000 000 = 𝑙𝑜𝑔 10 1 000 000 = 𝑙𝑜𝑔 3 3 −4 = 𝑙𝑜𝑔 5 5 0 = 𝑙𝑜𝑔 10 10 6 = 0 = - 4 = 6
Method #1 Method #2
Let 𝑦= 𝑙𝑜𝑔 3 81 = 3 𝑙𝑜𝑔 3 3 4 3 𝑙𝑜𝑔 3 81 = 3 4 3 𝑦 =81 =81 3 𝑦 = 3 4 Method #1 Method #2 Let 𝑦= 𝑙𝑜𝑔 3 81 Write the argument of the Log as a Power 3 𝑙𝑜𝑔 3 81 = 3 𝑙𝑜𝑔 3 3 4 Change to Exponential Form = 3 4 3 𝑦 =81 =81 3 𝑦 = 3 4 Equate Exponents 𝑦=4 ∴ 3 𝑙𝑜𝑔 3 81 = 3 4 ∴ 3 𝑙𝑜𝑔 3 81 =81
Ex#4] Evaluate. a) 4 𝑙𝑜𝑔 4 64 b) 7 𝑙𝑜𝑔 7 125 c) 6 𝑙𝑜𝑔 4 16
Ex#4] Evaluate. a) 4 𝑙𝑜𝑔 4 64 b) 7 𝑙𝑜𝑔 7 125 c) 6 𝑙𝑜𝑔 4 16 =64 =125 Ex#4] Evaluate. a) 4 𝑙𝑜𝑔 4 64 b) 7 𝑙𝑜𝑔 7 125 c) 6 𝑙𝑜𝑔 4 16 =64 =125 = 6 𝑙𝑜𝑔 4 4 2 = 6 2 =36
Your Turn… Read: “Example#2” on p.461-462 “In Summary” on p.465 Do: p.466-468 #1cdf,2bde,3,4,5aef,6,9,10,19,20a Corrections: #4d)approx 1.40