Mrs. Rivas Ch 4 Test Review 1. 𝑦=2(𝑥+2)²−3 𝒊𝒇𝒙=−𝟏, 𝒚=𝟐 −𝟏+𝟐 𝟐 −𝟑=−𝟏 Ida S. Baker H.S. Ch 4 Test Review (4-1) Graph the following functions; and identify the vertex, the axis of symmetry, the maximum or minimum value and the domain and range and describe the transformation of the graph of 𝑦=𝑥² to your graph. 𝒊𝒇𝒙=−𝟏, 𝒚=𝟐 −𝟏+𝟐 𝟐 −𝟑=−𝟏 (-1, -1) 1. 𝑦=2(𝑥+2)²−3 Vertex: (-2, -3) Axis: x = -2 Min: y = -3 Domain: all real numbers Range: all real numbers ≥−𝟑 Transformation: moved 2 units left and 3 units down.

Mrs. Rivas Ch 4 Test Review 2. 𝑦=−2(𝑥−2)²−4 𝒊𝒇𝒙=𝟏, 𝒚=−𝟐 𝟏−𝟐 𝟐 −𝟒=−𝟔 Ida S. Baker H.S. Ch 4 Test Review (4-1) Graph the following functions; and identify the vertex, the axis of symmetry, the maximum or minimum value and the domain and range and describe the transformation of the graph of 𝑦=𝑥² to your graph. 𝒊𝒇𝒙=𝟏, 𝒚=−𝟐 𝟏−𝟐 𝟐 −𝟒=−𝟔 (1, - 6) 2. 𝑦=−2(𝑥−2)²−4 Vertex: (2, -4) Axis: x = 2 Max: y = -4 Domain: all real numbers Range: all real numbers ≤−𝟒 Transformation: Reflected over the x-axis, and moved 2 units right and 4 units down.

Mrs. Rivas Ch 4 Test Review 𝒙= −𝒃 𝟐𝒂 𝒚=𝒙²−𝟐𝒙+𝟖 𝒚=(𝟏)²−𝟐(𝟏)+𝟖 Ida S. Baker H.S. Ch 4 Test Review (4-2)What is the vertex form of the equation? 𝑥= −𝑏 2𝑎 3. 𝑦=𝑥²−2𝑥+8 𝒙= −𝒃 𝟐𝒂 𝒚=𝒙²−𝟐𝒙+𝟖 a: 1 b: -2 𝒚=(𝟏)²−𝟐(𝟏)+𝟖 𝒙= −(−𝟐) 𝟐(𝟏) 𝒚=𝟏−𝟐+𝟖 𝒚=𝟕 𝒙= 𝟐 𝟐 𝒚= 𝒙−𝟏 +𝟕 𝒙=𝟏

Mrs. Rivas Ch 4 Test Review 𝒙= −𝒃 𝟐𝒂 𝒚=−𝒙²−𝟐𝒙+𝟖 𝒚=−(𝟏)²−𝟐(𝟏)+𝟖 Ida S. Baker H.S. Ch 4 Test Review (4-2)What is the vertex form of the equation? 𝑥= −𝑏 2𝑎 4. 𝑦=− 𝑥 2 +2𝑥−8 𝒙= −𝒃 𝟐𝒂 𝒚=−𝒙²−𝟐𝒙+𝟖 a: -1 b: 2 𝒚=−(𝟏)²−𝟐(𝟏)+𝟖 𝒙= −(𝟐) 𝟐(−𝟏) 𝒚=−𝟏−𝟐+𝟖 𝒙= −𝟐 −𝟐 𝒚=𝟓 𝒚= 𝒙−𝟏 +𝟓 𝒙=𝟏

Mrs. Rivas Ch 4 Test Review 𝟔𝒙 𝒙 +𝟖 𝟖𝒙 𝒙 + 𝟔 𝟔𝒙+𝟖𝒙=𝟏𝟒𝒙 𝒙+𝟖 𝒙+𝟔 Ida S. Baker H.S. Ch 4 Test Review (4-4)What is the expression in factored form? 5. 𝑥²+14𝑥+48 𝒙 𝟐 +𝟏𝟒𝒙+𝟒𝟖 𝟔𝒙 𝒙 +𝟖 𝟖𝒙 𝒙 + 𝟔 𝟔𝒙+𝟖𝒙=𝟏𝟒𝒙 𝒙+𝟖 𝒙+𝟔

Mrs. Rivas Ch 4 Test Review − 𝒙 𝟐 +𝒙−𝟒𝟐 𝟑𝒙 𝒙 +𝟕 −𝟔𝒙 𝒙 −𝟔 −𝟔𝒙+𝟕𝒙=𝒙 Ida S. Baker H.S. Ch 4 Test Review (4-4)What is the expression in factored form? 6. − 𝑥 2 −𝑥+42 − 𝒙 𝟐 +𝒙−𝟒𝟐 𝟑𝒙 𝒙 +𝟕 −𝟔𝒙 𝒙 −𝟔 −𝟔𝒙+𝟕𝒙=𝒙 − 𝒙+𝟕 𝒙−𝟔

Mrs. Rivas Ch 4 Test Review 𝟖𝒙(𝟐𝒙+𝟏) 7. 16𝑥²+8𝑥 Ida S. Baker H.S. Ch 4 Test Review (4-4)What is the expression in factored form? 7. 16𝑥²+8𝑥 Since c = 0 we have to factor out. 𝟖𝒙(𝟐𝒙+𝟏)

Mrs. Rivas Ch 4 Test Review 𝟏𝟎𝒙 𝟔𝒙 𝟐𝒙 +𝟔 𝒙 + 𝟓 𝟏𝟎𝒙+𝟔𝒙=𝟏𝟔𝒙 𝟐𝒙+𝟔 𝒙+𝟓 Ida S. Baker H.S. Ch 4 Test Review (4-4)What is the expression in factored form? 8. 2𝑥²+16𝑥+30 𝟐𝒙 𝟐 +𝟏𝟔𝒙+𝟑𝟎 𝟏𝟎𝒙 𝟐𝒙 +𝟔 𝟔𝒙 𝒙 + 𝟓 𝟏𝟎𝒙+𝟔𝒙=𝟏𝟔𝒙 𝟐𝒙+𝟔 𝒙+𝟓

Mrs. Rivas Ch 4 Test Review − 𝟒𝒙 𝟐 −𝟏𝟔𝒙−𝟒𝟖 −𝟐𝟒𝒙 𝟒𝒙 +𝟖 𝟖𝒙 𝒙 −𝟔 Ida S. Baker H.S. Ch 4 Test Review (4-4)What is the expression in factored form? 9. −4𝑥²+16𝑥+48 − 𝟒𝒙 𝟐 −𝟏𝟔𝒙−𝟒𝟖 −𝟐𝟒𝒙 𝟒𝒙 +𝟖 𝟖𝒙 𝒙 −𝟔 −𝟐𝟒𝒙+𝟖𝒙=−𝟏𝟔𝒙 − 𝟒𝒙+𝟖 𝒙−𝟔

Mrs. Rivas Ch 4 Test Review 𝑨𝒏𝒔𝒘𝒆𝒓: (𝒙+𝟖)(𝒙−𝟖) 10. 𝑥²−64 Ida S. Baker H.S. Ch 4 Test Review (4-4)What is the expression in factored form? 𝒙 𝟐 =𝒙 𝟒 =𝟐 10. 𝑥²−64 𝑨 𝟐 − 𝑩 𝟐 = 𝑨−𝑩 𝑨+𝑩 𝑨𝒏𝒔𝒘𝒆𝒓: (𝒙+𝟖)(𝒙−𝟖)

Mrs. Rivas Ch 4 Test Review 𝒙²+𝟏𝟏𝒙+𝟐𝟖=𝟎 (𝒙+𝟕)(𝒙+𝟒)=𝟎 𝒙+𝟕=𝟎 𝒙+𝟒=𝟎 𝒙=−𝟕 Ida S. Baker H.S. Ch 4 Test Review (4-5)What are the solutions of the quadratic equation? 11. 𝑥²+11𝑥=−28 𝒙²+𝟏𝟏𝒙+𝟐𝟖=𝟎 Step # 1: Write the equation in standard form. Step # 2: Factor the quadratic equation. (𝒙+𝟕)(𝒙+𝟒)=𝟎 𝒙+𝟕=𝟎 𝒙+𝟒=𝟎 Step # 3: Set each answer equal to Zero. 𝒙=−𝟕 𝒙=−𝟒 Step # 4: Solve for x. The solutions are 𝒙=−𝟕 and 𝒙=−𝟒.

Mrs. Rivas Ch 4 Test Review 𝒙²−𝟏𝟐𝒙+𝟑𝟐=𝟎 (𝒙−𝟖)(𝒙−𝟒)=𝟎 𝒙−𝟖=𝟎 𝒙−𝟒=𝟎 𝒙=𝟖 Ida S. Baker H.S. Ch 4 Test Review (4-5)What are the solutions of the quadratic equation? 12. 𝑥²−12𝑥+32=0 𝒙²−𝟏𝟐𝒙+𝟑𝟐=𝟎 Step # 1: Write the equation in standard form. Step # 2: Factor the quadratic equation. (𝒙−𝟖)(𝒙−𝟒)=𝟎 𝒙−𝟖=𝟎 𝒙−𝟒=𝟎 Step # 3: Set each answer equal to Zero. 𝒙=𝟖 𝒙=𝟒 Step # 4: Solve for x. The solutions are 𝒙=𝟖 and 𝒙=𝟒.

Mrs. Rivas Ch 4 Test Review 𝟑𝒙²−𝟓𝒙+𝟐=𝟎 (𝟑𝒙−𝟐)(𝒙−𝟏)=𝟎 𝟑𝒙−𝟐=𝟎 𝒙−𝟏=𝟎 Ida S. Baker H.S. Ch 4 Test Review (4-5)What are the solutions of the quadratic equation? 13. 3 𝑥 2 −5𝑥+2=0 𝟑𝒙²−𝟓𝒙+𝟐=𝟎 Step # 1: Write the equation in standard form. Step # 2: Factor the quadratic equation. (𝟑𝒙−𝟐)(𝒙−𝟏)=𝟎 𝟑𝒙−𝟐=𝟎 𝒙−𝟏=𝟎 Step # 3: Set each answer equal to Zero. 𝒙= 𝟐 𝟑 𝒙=𝟏 Step # 4: Solve for x. The solutions are 𝒙= 𝟐 𝟑 and 𝒙=𝟏.

Mrs. Rivas Ch 4 Test Review 𝟐 𝒙 2 +𝟓𝒙−𝟏𝟐=𝟎 (𝟐𝒙−𝟑)(𝒙+𝟒)=𝟎 𝟐𝒙−𝟑=𝟎 𝒙+𝟒=𝟎 Ida S. Baker H.S. Ch 4 Test Review (4-5)What are the solutions of the quadratic equation? 14. 2 𝑥 2 =−5𝑥+12 𝟐 𝒙 2 +𝟓𝒙−𝟏𝟐=𝟎 Step # 1: Write the equation in standard form. Step # 2: Factor the quadratic equation. (𝟐𝒙−𝟑)(𝒙+𝟒)=𝟎 𝟐𝒙−𝟑=𝟎 𝒙+𝟒=𝟎 Step # 3: Set each answer equal to Zero. 𝒙= 𝟑 𝟐 𝒙=−𝟒 Step # 4: Solve for x. The solutions are 𝒙= 𝟑 𝟐 and 𝒙=−𝟒.

Mrs. Rivas Ch 4 Test Review 15. 𝑥 2 +10𝑥=1 Ida S. Baker H.S. Ch 4 Test Review (4-6) Solve each quadratic equation by completing the square. 15. 𝑥 2 +10𝑥=1 𝑥 2 +10𝑥+ 𝒃 𝟐 𝟐 =1+ 𝒃 𝟐 𝟐 𝑥 2 +10𝑥+ 10 2 2 =1+ 10 2 2 𝑥 2 +10𝑥+25=1+25 𝑥+5 2 =26 𝑥+5 2 =± 26 𝑥+5=± 26 𝑥=−𝟓± 𝟐𝟔

Mrs. Rivas Ch 4 Test Review 16. 𝑥 2 −12𝑥+32=0 Ida S. Baker H.S. Ch 4 Test Review (4-6) Solve each quadratic equation by completing the square. 16. 𝑥 2 −12𝑥+32=0 𝑥 2 −12𝑥+ 𝒃 𝟐 𝟐 =−32+ 𝒃 𝟐 𝟐 𝑥 2 −12𝑥+ −12 2 2 =−32+ −12 2 2 𝑥 2 −12𝑥+36=−32+36 𝑥−6 2 =4 𝑥−6 2 =± 4 𝑥−6=±2 𝑥=6+2 𝑥=6−2 𝒙=𝟒 𝒙=𝟖

Mrs. Rivas Ch 4 Test Review 17. 9 𝑥 2 −12𝑥+4=49 Ida S. Baker H.S. Ch 4 Test Review (4-6) Solve each quadratic equation by completing the square. 17. 9 𝑥 2 −12𝑥+4=49 9𝑥 2 −12𝑥=49−4 9𝑥 2 −12𝑥=45 Find the real b. 9𝑥 2 −12𝑥+ 𝟒 2 2 =45+ 𝟒 2 2 3 3𝑥 2 −𝟒𝑥 9𝑥 2 −12𝑥+4=45+4 3𝑥+2 2 =49 3𝑥+2 2 =± 49 3𝑥+2=±7 3𝑥+2=7 3𝑥+2=−7 3𝑥=5 3𝑥=−9 𝑥=−𝟑 𝑥= 𝟓 𝟑

Mrs. Rivas Ch 4 Test Review 18. 3 𝑥 2 −42𝑥+78=0 Ida S. Baker H.S. Ch 4 Test Review (4-6) Solve each quadratic equation by completing the square. 18. 3 𝑥 2 −42𝑥+78=0 3 𝑥 2 −14𝑥+26 𝑥 2 −14𝑥=−26 𝑥 2 −14𝑥+ −14 2 2 =−26+ −14 2 2 𝑥 2 −14𝑥+49=−26+49 𝑥−7 2 =23 𝑥−7 2 =± 23 𝑥−7=± 23 𝒙=𝟕± 𝟐𝟑

Mrs. Rivas Ch 4 Test Review 19. 2 𝑥 2 +11𝑥−23=−𝑥+3 2 𝑥 2 +12𝑥−26=0 Ida S. Baker H.S. Ch 4 Test Review (4-6) Solve each quadratic equation by completing the square. 19. 2 𝑥 2 +11𝑥−23=−𝑥+3 Take out a. + 𝒙−𝟑 + 𝒙−𝟑 2 𝑥 2 +6𝑥−13 2 𝑥 2 +12𝑥−26=0 𝑥 2 +6𝑥−13=0 𝑥 2 +6𝑥+ 6 2 2 =13+ 6 2 2 𝑥 2 +6𝑥+9=13+9 𝑥+3 2 =22 𝑥+3 2 =± 22 𝑥+3=± 22 𝒙=−𝟑± 𝟐𝟐

Mrs. Rivas Ch 4 Test Review 𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂 Ida S. Baker H.S. Ch 4 Test Review (4-7)Use the Quadratic Formula to solve the equation. 20. −2 𝑥 2 −5𝑥+5=0 𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂 − 𝟐 𝒙 𝟐 +𝟓𝒙−𝟓=𝟎 𝒂=𝟐 𝒙= −(𝟓)± (𝟓)²−𝟒(𝟐)(−𝟓) 𝟐(𝟐) 𝒃=𝟓 𝒄=−𝟓 𝒙=− 𝟓± 𝟐𝟓+𝟒𝟎 𝟒 𝒙= −𝟓± 𝟔𝟓 𝟒

Mrs. Rivas Ch 4 Test Review 21. −16 𝑥 2 −56𝑥=−49 Ida S. Baker H.S. Ch 4 Test Review (4-7)Use the Quadratic Formula to solve the equation. 21. −16 𝑥 2 −56𝑥=−49 𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂 − 𝟏𝟔 𝒙 𝟐 +𝟓𝟔𝒙−𝟒𝟗=𝟎 𝒂=𝟏𝟔 𝒙= −(𝟓𝟔)± (𝟓𝟔)²−𝟒(𝟏𝟔)(−𝟒𝟗) 𝟐(𝟏𝟔) 𝒃=𝟓𝟔 𝒄=−𝟒𝟗 𝒙= −𝟓𝟔± 𝟑𝟏𝟑𝟔+𝟑𝟏𝟑𝟔 𝟑𝟐 𝒙= −𝟓𝟔±𝟓𝟔 𝟐 𝟑𝟐 = −𝟓𝟔 𝟏± 𝟐 𝟑𝟐 = −𝟓𝟔 𝟏± 𝟐 𝟑𝟐 = −𝟕 𝟏± 𝟐 𝟒

Mrs. Rivas Ch 4 Test Review 22. 6 𝑥 2 =𝑥+2 Ida S. Baker H.S. Ch 4 Test Review (4-7)Use the Quadratic Formula to solve the equation. 22. 6 𝑥 2 =𝑥+2 𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂 𝟔 𝒙 𝟐 −𝒙−𝟐=𝟎 𝒂=𝟔 𝒙= −(−𝟏)± (−𝟏)²−𝟒(𝟔)(−𝟐) 𝟐(𝟔) 𝒃=−𝟏 𝒄=−𝟐 𝒙= 𝟏± 𝟏+𝟒𝟖 𝟏𝟐 = 𝟏± 𝟒𝟗 𝟏𝟐 𝒙= 𝟏+𝟕 𝟏𝟐 𝒙= 𝟏−𝟕 𝟏𝟐 𝒙= 𝟐 𝟑 𝒙=− 𝟏 𝟐

Mrs. Rivas Ch 4 Test Review 23. −5 𝑥 2 =3𝑥−2 Ida S. Baker H.S. Ch 4 Test Review (4-7)Use the Quadratic Formula to solve the equation. 23. −5 𝑥 2 =3𝑥−2 𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂 −𝟓 𝒙 𝟐 −𝟑𝒙+𝟐=𝟎 − 𝟓 𝒙 𝟐 +𝟑𝒙−𝟐=𝟎 𝒙= −(𝟑)± (𝟑)²−𝟒(𝟓)(−𝟐) 𝟐(𝟓) 𝒂=𝟓 𝒃=𝟑 𝒙= −𝟑± 𝟗+𝟒𝟎 𝟏𝟎 = −𝟑± 𝟒𝟗 𝟏𝟎 𝒄=−𝟐 𝒙= −𝟑+𝟕 𝟏𝟎 𝒙= −𝟑−𝟕 𝟏𝟎 𝒙= 𝟐 𝟓 𝒙=−𝟏

Mrs. Rivas Ch 4 Test Review −𝟑𝟔𝟎 = −𝟏 ∙ 𝟑𝟔𝟎 =𝒊∙ 𝟑𝟔 ∙ 𝟏𝟎 =𝒊∙𝟔∙ 𝟏𝟎 Ida S. Baker H.S. Ch 4 Test Review (4-8)Simplify the expression. 24. −360 −𝟑𝟔𝟎 = −𝟏 ∙ 𝟑𝟔𝟎 =𝒊∙ 𝟑𝟔 ∙ 𝟏𝟎 =𝒊∙𝟔∙ 𝟏𝟎 =𝟔𝒊 𝟏𝟎

Mrs. Rivas Ch 4 Test Review −𝟏−𝟒+𝟔𝒊+𝟐𝒊 −𝟓+𝟖𝒊 25. −1+6𝑖 +(−4+2𝑖) Ida S. Baker H.S. Ch 4 Test Review (4-8)Simplify the expression. 25. −1+6𝑖 +(−4+2𝑖) −𝟏−𝟒+𝟔𝒊+𝟐𝒊 −𝟓+𝟖𝒊

Mrs. Rivas Ch 4 Test Review 𝟐−𝟓𝒊−𝟑−𝟒𝒊 𝟐−𝟑−𝟓𝒊−𝟒𝒊 −𝟏−𝟗𝒊 26. 2−5𝑖 −(3+4𝑖) Ida S. Baker H.S. Ch 4 Test Review (4-8)Simplify the expression. 26. 2−5𝑖 −(3+4𝑖) 𝟐−𝟓𝒊−𝟑−𝟒𝒊 𝟐−𝟑−𝟓𝒊−𝟒𝒊 −𝟏−𝟗𝒊

Mrs. Rivas Ch 4 Test Review −𝟓+𝟖+𝟑𝒊−𝟐𝒊 𝟑+𝒊 27. −5+3𝑖 −(−8+2𝑖) Ida S. Baker H.S. Ch 4 Test Review (4-8)Simplify the expression. 27. −5+3𝑖 −(−8+2𝑖) −𝟓+𝟖+𝟑𝒊−𝟐𝒊 𝟑+𝒊

Mrs. Rivas Ch 4 Test Review −𝟔+𝟑𝟔𝒊 + 𝟒𝒊−𝟐𝟒𝒊² −𝟔+𝟒𝟎𝒊−𝟐𝟒(−𝟏) −𝟔+𝟒𝟎𝒊+𝟐𝟒 Ida S. Baker H.S. Ch 4 Test Review (4-8)Simplify the expression. 28. (6−4𝑖)(−1+6𝑖) −𝟔+𝟑𝟔𝒊 + 𝟒𝒊−𝟐𝟒𝒊² −𝟔+𝟒𝟎𝒊−𝟐𝟒(−𝟏) −𝟔+𝟒𝟎𝒊+𝟐𝟒 −𝟔+𝟐𝟒+𝟒𝟎𝒊 𝟏𝟖+𝟒𝟎𝒊

Mrs. Rivas Ch 4 Test Review 𝟏𝟔−𝟒𝒊 − 𝟒𝒊+𝒊² 𝟏𝟔−𝟖𝒊+(−𝟏) 𝟏𝟔−𝟏−𝟖𝒊 𝟏𝟓−𝟖𝒊 Ida S. Baker H.S. Ch 4 Test Review (4-8)Simplify the expression. 29. 4−𝑖 2 =(4−𝑖)(4−𝑖) 𝟏𝟔−𝟒𝒊 − 𝟒𝒊+𝒊² 𝟏𝟔−𝟖𝒊+(−𝟏) 𝟏𝟔−𝟏−𝟖𝒊 𝟏𝟓−𝟖𝒊

Mrs. Rivas Ch 4 Test Review ∙ 𝟒+𝒊 𝟒+𝒊 = (−𝟏+𝟑𝒊)(𝟒+𝒊) (𝟒−𝒊)(𝟒+𝒊) Ida S. Baker H.S. Ch 4 Test Review (4-8)Simplify the expression. 30. −1+3𝑖 4−𝑖 ∙ 𝟒+𝒊 𝟒+𝒊 = (−𝟏+𝟑𝒊)(𝟒+𝒊) (𝟒−𝒊)(𝟒+𝒊) = −𝟒−𝒊+𝟏𝟐𝒊+𝟑𝒊² 𝟏𝟔+𝟒𝒊−𝟒𝒊−𝒊² = −𝟒+𝟏𝟏𝒊+𝟑(−𝟏) 𝟏𝟔−(−𝟏) = −𝟒+𝟏𝟏𝒊−𝟑 𝟏𝟕 = −𝟒−𝟑+𝟏𝟏𝒊 𝟏𝟕 = −𝟕+𝟏𝟏𝒊 𝟏𝟕

Mrs. Rivas Ch 4 Test Review 𝒙²+𝟑𝟔=𝟎 −𝟑𝟔 −𝟑𝟔 𝒙²=−𝟑𝟔 𝒙=± −𝟑𝟔 𝒙=±𝟔𝒊 Ida S. Baker H.S. Ch 4 Test Review Find the factors of each expression. 34. 𝑥 2 +36 𝒙²+𝟑𝟔=𝟎 −𝟑𝟔 −𝟑𝟔 𝒙²=−𝟑𝟔 𝒙=± −𝟑𝟔 𝒙=±𝟔𝒊

Mrs. Rivas Ch 4 Test Review −𝟒𝒙 2 −𝟒𝟗=𝟎 +𝟒𝟗 +𝟒𝟗 −𝟒𝒙²=𝟒𝟗 −𝟒 −𝟒 Ida S. Baker H.S. Ch 4 Test Review Find the factors of each expression. 35. −4𝑥 2 −49 −𝟒𝒙 2 −𝟒𝟗=𝟎 +𝟒𝟗 +𝟒𝟗 −𝟒𝒙²=𝟒𝟗 −𝟒 −𝟒 𝒙 2 = 𝟒𝟗 −𝟒 𝒙= 𝟒𝟗 −𝟒 = 𝟒𝟗 −𝟒 =± 𝟕 𝟐𝒊

Mrs. Rivas Ch 4 Test Review Ida S. Baker H.S. Ch 4 Test Review Find all solutions to each quadratic equation. 36. 2 𝑥 2 −3𝑥+5 𝟐𝒙 𝟐 −𝟑𝒙+𝟓 𝟐𝒙 𝟐𝒙 −𝟓 −𝟓𝒙 𝒙 + 𝟏 𝟐𝒙−𝟓𝒙=−𝟑𝒙 2𝑥−5 𝑥+1 =0 2𝑥−5=0 𝑥+1=0 𝑥= 𝟓 𝟐 𝑥= −𝟏

Mrs. Rivas Ch 4 Test Review Ida S. Baker H.S. Ch 4 Test Review Find all solutions to each quadratic equation. 37. −𝑥 2 +2𝑥−10=0 𝒙= −𝒃± 𝒃²−𝟒𝒂𝒄 𝟐𝒂 − 𝒙 𝟐 −𝟐𝒙+𝟏𝟎=𝟎 𝒙= −(−𝟐)± (−𝟐)²−𝟒(𝟏)(𝟏𝟎) 𝟐(𝟏) 𝒂=𝟏 𝒃=−𝟐 𝒙= 𝟐± 𝟒−𝟒𝟎 𝟐 = 𝟐± −𝟑𝟔 𝟐 𝒄=𝟏𝟎 = 𝟐±𝟔𝒊 𝟐 = 𝟐 𝟐 ± 𝟔𝒊 𝟐 =𝟏±𝟑𝒊