Bell Ringer Solve. 1. 6x – 8 = -4x + 22

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Presentation transcript:

Bell Ringer Solve. 1. 6x – 8 = -4x + 22 + 8 + 8 2x = 30 2 2 x = 15 2. -3(x – 6)= 3 -3x + 18 = 3 – 18 – 18 -3x = -15 -3 -3 x = 5

Homework 1296 -1296 1/27 4096 1 1/125 -128 16 80 512 3/16 x3 y4 15x12 1/c9 n4 4x6y5 7y2/x3 3 1728 2x 2x2 -4/y2 5y/x2 2y2/x5 3x7/y2 6x2/y3z3

Solve the problem in pieces. Review Solve the problem in pieces. 8 x3 y5 z4 4 x5 y6 z 2z3 x2y = (2x3y2)3 (6xy3)2 8x9y6 36x2y6 x7 4 = =

Power of a Power Power of a Product Power of a Quotient Laws of Exponents, Pt. II Power of a Power Power of a Product Power of a Quotient

Power of a Power (63)4 = 63•63•63•63 = 612 (x5)3 = x5•x5•x5 = x15 This property is used to write an exponential expression as a single power of the base. (63)4 = 63•63•63•63 = 612 (x5)3 = x5•x5•x5 = x15 When you have an exponent raised to an exponent, multiply the exponents!

Multiply the exponents! Power of a Power (54)8 = 532 Multiply the exponents! (n3)4 = n12 (3-2)-3 = 36 1 x15 (x5)-3 = x-15 =

Power of a Product (xy)3 (2x)5 = x3y3 = 25 ∙ x5 = 32x5 (xyz)4 Power of a Product – Distribute the exponent on the outside of the parentheses to all of the terms inside of the parentheses. (xy)3 (2x)5 = x3y3 = 25 ∙ x5 = 32x5 (xyz)4 = x4 y4 z4

Power of a Product (x3y2)3 (3x2)4 = x9y6 = 34 ∙ x8 = 81x8 (3xy)2 More examples… (x3y2)3 (3x2)4 = x9y6 = 34 ∙ x8 = 81x8 (3xy)2 = 32 ∙ x2 ∙ y2 = 9x2y2

( ) ( ) x x5 = y y5 Power of a Quotient Power of a Quotient – Distribute the exponent on the outside of the parentheses to the numerator and the denominator of the fraction. ( ) ( ) x y 5 x5 y5 =

( ) ( ) ( ) ( ) 2 x 23 x3 8 x3 = = 3 x2y 34 x8y4 81 x8y4 = = Power of a Quotient More examples… ( ) ( ) 2 x 3 23 x3 8 x3 = = ( ) ( 3 x2y ) 4 34 x8y4 81 x8y4 = =

Examples

Examples Examples

Examples

( ) ( ) ( ) ( ) 16x4 x4y4 16 y4 2x xy = = 2yz2 4y2z 4y2z4 16y4z2 z2 More Examples ( ) ( 16x4 x4y4 ) 16 y4 2x xy 4 = = ( ) ( 2yz2 4y2z ) 2 4y2z4 16y4z2 z2 4y2 = =