Male-driven evolution

Slides:



Advertisements
Similar presentations
Genetica per Scienze Naturali a.a prof S. Presciuttini Homologous genes Genes with similar functions can be found in a diverse range of living things.
Advertisements

R ATES OF P OINT M UTATION. The rate of mutation = the number of new sequence variants arising in a predefined target region per unit time. Target region.
Number of mitoses in females = 22 Number of mitoses in males is age dependent.
Molecular Clock I. Evolutionary rate Xuhua Xia
Xuhua Xia Mutation Xuhua Xia
Introduction to the Cell Cycle and Inheritance
Unit Animal Science. Problem Area Animal Genetics and Biotechnology.
Molecular Clocks, Base Substitutions, & Phylogenetic Distances.
Sources of variation. Mutation produces variation at multiple scales:
TGCAAACTCAAACTCTTTTGTTGTTCTTACTGTATCATTGCCCAGAATAT TCTGCCTGTCTTTAGAGGCTAATACATTGATTAGTGAATTCCAATGGGCA GAATCGTGATGCATTAAAGAGATGCTAATATTTTCACTGCTCCTCAATTT.
- any detectable change in DNA sequence eg. errors in DNA replication/repair - inherited ones of interest in evolutionary studies Deleterious - will be.
Molecular Clock. Rate of evolution of DNA is constant over time and across lineages Resolve history of species –Timing of events –Relationship of species.
Genes  A gene is the entire sequence of DNA bases responsible for the synthesis of a protein.  A mutation occurs when the sequence of bases in a gene.
The Molecular Clock? By: T. Michael Dodson. Hypothesis For any given macromolecule (a protein or DNA sequence) the rate of evolution is approximately.
TGCAAACTCAAACTCTTTTGTTGTTCTTACTGTATCATTGCCCAGAATAT TCTGCCTGTCTTTAGAGGCTAATACATTGATTAGTGAATTCCAATGGGCA GAATCGTGATGCATTAAAGAGATGCTAATATTTTCACTGCTCCTCAATTT.
1 Genome Evolution Chapter Introduction Genomes contain the raw material for evolution; Comparing whole genomes enhances – Our ability to understand.
GENETIC CONTINUITY. A METHOD OF REPRODUCTION IN WHICH ALL THE GENES ARE PASSED ON TO THE OFFSPRING COME FROM A SINGLE PARENT AND ARE GENETICALLY IDENTICAL.
What is the difference between mitosis and meiosis?
1 Male-Driven Evolution:. 2 The Rate of Substitution is Positively Correlated with the Rate of Mutation and Negatively Correlated with the Degree of Purifying.
Bellringer How many chromosomes do we get from our mom? How many chromosomes do we get from our dad? How many total chromosomes do we have in our bodies?
NEW TOPIC: MOLECULAR EVOLUTION.
You have body cells and gametes.
In populations of finite size, sampling of gametes from the gene pool can cause evolution. Incorporating Genetic Drift.
Published primate genome sequences - I Published primate genome sequences - II.
Monkey Business Bioinformatics Research Center University of Aarhus Thomas Mailund Joint work with Asger Hobolth, Ole F. Christiansen and Mikkel H. Schierup.
5.4 Cladistics Essential idea: The ancestry of groups of species can be deduced by comparing their base or amino acid sequences. The images above are.
What is the difference between mitosis and meiosis?
5.4 Cladistics Essential idea: The ancestry of groups of species can be deduced by comparing their base or amino acid sequences. The images above are both.
SEX LINKED TRAITS.
Part 2: Genetics, monohybrid vs. Dihybrid crosses, Chi Square
Chapter 15 The Chromosomal Basis of Inheritance
Evolution of gene function
Neutrality Test First suggested by Kimura (1968) and King and Jukes (1969) Shift to using neutrality as a null hypothesis in positive selection and selection.
5.4 Cladistics Essential idea: The ancestry of groups of species can be deduced by comparing their base or amino acid sequences. The images above are both.
Unit 3.
Meiosis.
Chapter 6.
Molecular Clock: Lineage-specific evolutionary rate
Day one of Meiosis.
Biology Unit Three D – Asexual Reproduction and Cell Functions
Animal Science and The Industry
Notepack # 42 Please write these notes on Loose Leaf. You will receive a 7 instead of a 5 for your inconvenience. Aim: Why do some organisms evolve.
Genome Projects Maps Human Genome Mapping Human Genome Sequencing
What are the Patterns Of Nucleotide Substitution Within Coding and
Different mode and types of inheritance
The ‘V’ in the Tajima D equation is:
Gene duplications: evolutionary role
The student is expected to: 6A identify components of DNA, and describe how information for specifying the traits of an organism is carried in the DNA.
Meiosis & Mendel Chapter 6
The Evolution of Populations
Meiosis & Gamete Formation
What gender is XX female.
Mutations Section 6.2.
First Draft of Chimpanzee Genome
Coral Reef Conservation
Biology Chapter 6 Dr. Altstiel
Evolutionary genetics
Sources of Variation.
Meiosis and Sexual Life Cycles
Meiosis & Sexual Reproduction
Chapter 6 Clusters and Repeats.
5.4 Cladistics Essential idea: The ancestry of groups of species can be deduced by comparing their base or amino acid sequences. The images above are both.
Tuesday January 29th, 2019 Interphase Prophase Metaphase Anaphase
Evolution Part Two.
Unit Genomic sequencing
Unit 2: Organisms and Evolution Advanced Higher Biology Miss A Aitken
Chromosomes And Inheritance
Jeopardy Final Jeopardy Genetics Meiosis Versus Punnett Squares Random
2d. Know new combinations of alleles may be generated in a zygote through the fusion of male & female gametes (fertilization)‏ 1.
Creating gametes (sex cells)
Presentation transcript:

Male-driven evolution Xuhua Xia xxia@uottawa.ca http://dambe.bio.uottawa.ca

Number of replications in the production of sperm and egg in human Females take ~25 cell replications to produce eggs. Males: 1 replication of stem cells every 16 days: Add 365/16  22.8 replications per year. Age Male M/F 15 36 1.4 18 104 4.2 21 173 6.9 24 241 9.7 27 310 12.4 30 378 15.1 33 447 17.9 515 20.6 39 584 23.3 42 652 26.1 45 720 28.8 48 789 31.6 51 857 34.3 54 926 37.0 57 994 39.8 60 1063 42.5 63 1131 45.2 66 1199 48.0 69 1268 50.7  “Thus the mutation rate in the X-chromosome of females is probably less than one-tenth of that in males, …… The primordial oocytes are mostly if not all formed at birth, whereas spermatogonia go on dividing throughout the sexual life of a male. So if mutation is due to faulty copying of genes at a nuclear division, we might expect it to be commoner in males than females.” J. B. S. Haldane. 1946. The mutation rate of the gene for haemophilia and its segregation ratios in males and females. Annals of Eugenics 13:262-271. Annals of Eugenics changed its name to the current Annals of Human Genetics in 1954. "One-tenth" is approximate. If all children are fathered by 15-year-olds, then the ratio would be close to 1:1; if all fathers are 30 years old, then ratio would be closer to 1:10. To get a proper ratio, one needs to have the number of children sired by father of different ages. What is the ratio of sperm mutation rate versus egg mutation rate (or male mutation rate versus female mutation rate)? Some places have younger fathers than other places. Does this affect propensity of genetic diseases? Could be a good research questions.

Y-linked sequences (Y) are only carried by males. Autosomal sequences (A) are carried one half of the time by females and one half of the time by males. X-linked sequences (X) are carried two-thirds of the time by females and one third of the time by males. Y-linked sequences (Y) are only carried by males. Qualitative prediction: RY > RA > RX Quantitative prediction: µm: mutation rate in male µf: mutation rate in female How to estimate We can't directly measure µm and µf, can we express  in something measurable? We can measure mutation rates on autosomes (µA) and X chromosome (µX). Solve the equations for µm and µf, we have Gene KS PLP 0.166 HPRT 0.309 PGK1 0.329 OTC 0.509 NGFb 0.431 b-actin 0.339 Hox-1 0.469 SST 0.479 GCR 0.5 PKC-II 0.53 c-myc 0.54 ALDOA 0.55 DHFR 0.56 Renin 0.57 c-ras 0.58 a-actin 0.59 PAH 0.6 c-myb 0.61 Amy-2 0.63 TGFb 0.65 X-linked Why did Miyata et al. (1987) take KS for µ? Autosome given µf  0 a = M_m/M_f M_Y=M_m M_A = (M_m+M_f)/2 M_X = 2*M_f/3 + M_m/3 A/Y = M_A/M_Y = (M_m+M_f)/(2*M_m) = ½ + M_f/(2M_m) = ½ + 1/(2a) = (a + 1)/(2a) The statement that X chromosome is carried 2/3 of the time in female and 1/3 in male may not be obvious to some students. A randomly sampled X chromosome in the current generation has 2/3 of chance being found in female and 1/3 of chance being found in male Digitized from Fig. 3 of Miyata et al. (1987) So can't get a meaningful estimate of µf (it would be negative), but µA > µX is statistically significant by t-test (p = 0.00075) Miyata T et al. (1987). Male-driven molecular evolution: a model and nucleotide sequence analysis. Cold Spring Harbor Symp Quant Biol 52:863-867.

Instead of solving for µm and µf to get , Miyata et al Instead of solving for µm and µf to get , Miyata et al. derived ratios of mutation rates for  estimation: Minimum µX/µA is 2/3  0.67. Estimated µX/µA = 0.6 based on comparison between mouse and human, and are interpreted as consistent with a very large    ∞ a = M_m/M_f M_Y=M_m M_A = (M_m+M_f)/2 M_X = 2*M_f/3 + M_m/3 A/Y = M_A/M_Y = (M_m+M_f)/(2*M_m) = ½ + M_f/(2M_m) = ½ + 1/(2a) = (a + 1)/(2a) The statement that X chromosome is carried 2/3 of the time in female and 1/3 in male may not be obvious to some students. A randomly sampled X chromosome in the current generation has 2/3 of chance being found in female and 1/3 of chance being found in male However So can't estimate ; can say that  is very large Miyata T et al. (1987). Male-driven molecular evolution: a model and nucleotide sequence analysis. Cold Spring Harbor Symp. Quant. Biol. 52:863-867.

Fig. 3. in Miyata et al. 1987. PLP 0.166 HPRT 0.309 PGK1 0.329 OTC 0.509 NGF 0.431 -actin 0.339 Hox-1 0.469 SST 0.479 GCR 0.5 PKC-II 0.53 c-myc 0.54 ALDOA 0.55 DHFR 0.56 Renin 0.57 c-ras 0.58 -actin 0.59 PAH 0.6 c-myb 0.61 Amy-2 0.63 TGF 0.65

Problem 1: Apples and Oranges The genes on the X chromosomes are not homologous to those on the autosomes. Genes on the X chromosomes may happen to be functionally more important and strongly conserved than those on the autosomes. Two Solution: Use synonymous substitutions for comparison (done by Miyata et al. 1987) Find homologous genes on X and Y to make comparisons. Xuhua Xia

Shared homologous genes All known studied mammals have two homologous zinc-finger protein-coding genes, one X-linked (Zfx) and one Y-linked (Zfy). They contain introns which are largely free from functional constraints. For all pairwise comparisons done among human, orangutan, baboon, and squirrel monkey, Shimmin et al. (1993) found that the Y sequences were more divergent, i.e., have evolved faster, than their X-linked homologues. Max µY/ µX = 3 Shimmin, L. C., Chang, B.H.-J., Hewett-Emmett, D. & Li, W.-H. Potentialproblemsin estimating the male-to-female mutation rate ratio from DNA sequence data. J. Mol. Evol. 37, 160–166 (1993)

Problem 2: selection Alternative selection hypothesis: males have only one copy of X and genes on X are therefore more exposed to purifying selection, leading to greater conservation and lower evolutionary rate. (Does using silent substitution remove this problem?) Solution: Use the ZW system (ZW: female; ZZ: male) Predictions From the alternative hypothesis: genes on Z should be more conserved and evolve more slowly than autosomal genes because Z (just like X in mammals) is more exposed to selection than autosomal genes. From the male-driven hypothesis: genes on Z should evolve faster than autosomal genes because it spend more times in males. Miyata et al. presented this conceptual framework but did not have data on birds to test the predictions. 10 years later, the predictions were tested by Ellegren and Fridolfsson (1997. Nature Genetics 17:182-184) , and the male-drive hypothesis is supported (α: 3.9-6.5). Using silent substitution does not remove this problem. Imagine a sequence has accumulated 2 silent mutations. A deleterious mutation arrives and kills the individual carrying the sequence. This removes the two silent mutations from the population. The textbook (Grour and Li 2000) does not specify the ZW sex-determination system correctly.

Controversy on α Low α (<2): Bohossian, H. B., Skaletsky, H. & Page, D. C. Unexpectedly similar rates of nucleotide substitution found in male and female hominids. Nature 406, 622–625 (2000). International Human Genome Sequencing Consortium. Initial sequencing and analysis of the human genome. Nature 409, 860–921 (2000). High α related to male/female ratio of generations in gametogenesis: Kateryna D. Makova & Wen-Hsiung Li. Strong male-driven evolution of DNA sequences in humans and apes Nature 416:624-626 (2002) Why so different estimates of α?

Complications X is randomly inactivated with many epigenetic modifications that could increase or decrease its overall mutation rate. Solution: avoid using X and compare Y and autosomes Ancient polymorphism (next two slides) Xuhua Xia

Ancient polymorphism and small α X chromosome and autosomes are expected to have more polymorphism than Y chromosome: Greater effective population size Recombination X and autosomes are more likely to have ancient polymorphism to bias estimate of α Speciation X and autosome Y

After many papers in Nature, Science and PNAS, the field is effectively deserted and see no sign of revival in the near future.

Ancient polymorphism b1 b10 b3 b4 b5 b6 b7 b8 b9 b11 Mouse Rat Gibbon Orangutan Human Chimp Gorilla b2 a1 Mouse Rat Gibbon Orangutan Human Chimp Gorilla a9 a2 a8 a10 a3 b12 b12 a4 a5 a6 a11 a7 X Y Global α: α values close to the tip are smaller than those close to the root: consistent with ancient polymorphism Lineage-specific α: bi/ai