Graphing exercise Phet Simulation

Using the Phet Simulation x

A person is moving at a constant rate of 2 m/s from a 0 position with no acceleration. Draw the following graphs for the first 7 seconds Time Displacement   1 2 3 4 5 6 7

To fill in the displacement column, we need to use the d = v To fill in the displacement column, we need to use the d = v*t equation. d = 2 m/s * 1 s = 2 meters d = 2 m/s * 2 s = 4 meters d = 2 m/s * 3 s = 6 meters d = 2 m/s * 4 s = 8 meters d = 2 m/s * 5 s = 10 meters d = 2 m/s * 6 s = 12 meters d = 2 m/s * 7 s = 14 meters Time Displacement 1  2 2  4 3  6 4  8 5  10 6  12 7  14

Using excel, connected scattered

For the velocity vs. time graph,  2 1 2 3 4 5 6 7

For the acceleration vs. time graph  0 1 2 3 4 5 6 7

2. A person is moving with an initial 2 m/s from a 0 position with constant 1 m/s2 acceleration. For this problem you have to use the equation d = d0 + vit + ½ at2 Our d0 is the starting point which is 0.

d = vit + ½ at2 d = 2(0) + ½ (1)(0)2 = 0 d = 2(1) + ½ (1)(1)2 = 2.5 Repeating the process d = 6 d = 10.5 d = 16 d = 22.5 d = 30 d = 38.5 Time Displacement  0 1  2.5 2  6 3  10.5 4  16 5  22.5 6  30 7  38.5

Using vf = vi + at vf = 2 + (1)(0) = 2 vf = 2 + (1)(1) = 3 vf = 2 + (1)(2) = 4 vf = 2 + (1)(3) = 5 vf = 2 + (1)(4) = 6 vf = 2 + (1)(5) = 7 vf = 2 + (1)(6) = 8 vf = 2 + (1)(7) = 9

Time Velocity  2 1  3 2  4 3  5 4  6 5  7 6  8 7  9

Time Acceleration  1 1 2 3 4 5 6 7

A person is moving from an initial position of -5 m with a constant velocity of 3 m/s and an acceleration of -0.25 m/s2. Draw the following graphs for the first 7 seconds. Using the earlier methods, complete this problem.

Displacement vs. time -5 1 -2.125 2 0.5 3 2.875 4 5 6.875 6 8.5 7 -5 1 -2.125 2 0.5 3 2.875 4 5 6.875 6 8.5 7 9.875