MOTION IN ONE DIMENSION

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Presentation transcript:

MOTION IN ONE DIMENSION Velocity and Acceleration

Graphing Motion: Velocity How would you describe the motion shown by this graph? Answer: Constant speed (straight line) What is the slope of this line? Answer: 1 m/s What is the average velocity?

Graphing Motion: Velocity Describe the motion of each object. Answers Object 1: constant velocity to the right or upward Object 2: constant velocity of zero (at rest) Object 3: constant velocity to the left or downward

Instantaneous Velocity Velocity at a single instant of time Speedometers in cars measure instantaneous speed. Determined by finding the slope at a single point (the slope of the tangent) What is the slope of the tangent line at t = 3.0 s? Answer: approximately 12 m/s What is the instantaneous velocity at t = 3.0 s?

What do you think? Which of the following cars is accelerating? a. A car shortly after a stoplight turns green b. A car approaching a red light c. A car with the cruise control set at 80 km/h d. A car turning a curve at a constant speed Based on your answers, what is your definition of acceleration?

Acceleration Rate of change in velocity What are the units? SI Units: (m/s)/s or m/s2 Other Units: (km/h)/s or (mi/h)/s Acceleration = 0 implies a constant velocity (or rest)

Practice Problem Find the acceleration of an amusement park ride that falls from rest to a velocity of 28 m/s downward in 3.0 s. Answer: 9.3 m/s2 downward

Direction of Acceleration Describe the motion of an object with vi and a as shown to the left. Moving right as it speeds up Moving right as it slows down Moving left as it speeds up Moving left as it slows down Vi a + -

Graphing Velocity The slope (rise/run) of a velocity/time graph is the acceleration. Rise is change in v Run is change in t This graph shows a constant acceleration. Average speed is the midpoint. The equation for vavg is only valid if the velocity increases uniformly (a straight line in a velocity-time graph) or, in other words, if the acceleration is constant.

Graph of v vs. t for a train Describe the motion at points A, B, and C. Answers A: accelerating (increasing velocity/slope) to the right B: constant velocity to the right C: negative acceleration (decreasing velocity/slope) and still moving to the right Students may think “B” is at rest and “C” is moving backwards or to the left. If so, they are confusing position-time graphs with velocity-time graphs. Ask them to look at “B” and think about what it means if velocity stays the same or look at “C” and ask them what it means if velocity is decreasing. A good exercise for the students at this time would be the use of the Phet web site: http://phet-web.colorado.edu/web-pages/index.html NOTE: These simulations are downloadable so you can avoid the need for internet access after a onetime download. If you choose the “Motion” simulations and then choose the “Moving man” option, the students can observe the motion of a man (constant velocity, speeding up, slowing down, at rest) and see the graphs of position-time, velocity-time and acceleration-time. You might start with “at rest” and ask them to predict the shape of each graph before running the simulation. Then ask them how each would change if he moved forward with a constant speed. Follow this with other changes, such as changing the starting position or accelerating the walker.

Practice Problems A bicyclist accelerates from 5.0 m/s to 16 m/s in 8.0 s. Assuming uniform acceleration, what distance does the bicyclist travel during this time interval? Answer: 84 m An aircraft has a landing speed of 83.9 m/s. The landing area of an aircraft carrier is 195 m long. What is the minimum uniform acceleration required for safe landing? Answer: -18.0 m/s2

NOW YOU TRY IT! Do Practice B and C from chapter 2 (pages 49 and 53)