Upper and Lower Bounds.

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Presentation transcript:

Upper and Lower Bounds

A number has been rounded to the nearest whole number, what could it have been? If it was rounded up, it could have been- If it was rounded down, it could have been- 4.9 5 5.1 4.87 5.34 4.61 5.48 What’s the smallest number it could have been? 4.5 What’s the biggest number it could have been? 5.499999999999999999999999999999999999999999999999999999999999999999999...........

If 5 has been rounded to the nearest whole number we say The lower bound is 4.5 (the smallest it could have been) The upper bound is 5.5 (it’s easier than writing 4.4999999999999999999999... , even though technically it would round to give 6!)

Try these.. These numbers have been rounded to the nearest whole number, write the upper and lower bounds: 7 11 15 17 23 100 6.5 and 7.5 10.5 and 11.5 14.5 and 15.5 16.5 and 17.5 22.5 and 23.5 99.5 and 100.5

A general rule To find the upper bound we have to add half of the unit we rounded to for example: If we rounded to the nearest 10, we add on 5 (half of 10) If we rounded to the nearest 1 (whole number), we add on 0.5 (half of 1) If we rounded to the nearest 0.1 (1 dp), we add on 0.05 (half of 0.1) If we rounded to the nearest 0.01 (2 dp), we add on 0.005 (half of 0.01) And if we want the lower bound, we subtract have of the unit

Limits 4) A field is 100m wide and 120m long, both lengths have been rounded to the nearest metre. a) Find the perimeter and area of the field if these measurements are accurate b) Find the largest and smallest possible perimeter c) Find the largest and smallest possible area. 5) A rectangle has it’s area rounded to the nearest whole number, it becomes 40cm2. One side of the rectangle is exactly 10cm; find the maximum and minimum lengths the other length could have. 6) Two lengths of wood are stuck together and their combined length is rounded to the nearest mm and it is 14.9cm, one length is rounded to the nearest mm and is 7.1cm. Find the minimum and maximum length of the other length. Answers 45 and 54.9999999.. 75 and 84.999.... 105 and 114.9999... 2.5 and 3.4999... 16.5 and 17.4999... 22.5 and 23.49999... 99.5 and 100.4999.. -3.499999 and -2.5 12.45 and 12.55 21.65 and 21.75 35.75 and 38.5 52.05 and 52.15 80.35 and 80.45 p=44om and area= 12000m2 largest= 442m smallest=438m largest= 12110.25m2 smallest=11890.25m2 smallest- 3.95cm largest- 4.05cm 6. largest- 7.9cm smallest- 7.7cm These numbers have been rounded to the nearest 10, write down the largest and smallest values they could be: 50 80 110 These numbers have been rounded to the nearest whole number, write down the upper and lower limits: 3 17 23 100 -3 These lengths have been rounded to the nearest 10th of a cm, write the upper and lower limits: 12.5cm 21.7cm 35.8cm 52.1cm 80.4cm