Warm Up 11/6 What is the difference between prophase of mitosis and prophase 1 of meiosis? What is the definition of meiosis? How many cells are produced.

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Warm Up 11/6 What is the difference between prophase of mitosis and prophase 1 of meiosis? What is the definition of meiosis? How many cells are produced from meiosis? Are they haploid or diploid? What are these cells called?

THE PROCESS OF GETTING US HOW WE ARE. GENETICS THE PROCESS OF GETTING US HOW WE ARE.

Mendel stated that physical traits are inherited as “particles” Who is Gregor Mendel? Mendel stated that physical traits are inherited as “particles” Mendel did not know the “particles” were actually chromosomes and DNA “Father of Genetics”

Traits Genetics – study of how traits are passed from parent to offspring

Traits are determined by the genes on the chromosomes Traits are determined by the genes on the chromosomes. A gene is a segment of DNA that determines a trait.

One pair of Homologous Chromosomes: Gene for eye color (blue eyes) Homologous pair of chromosomes Gene for eye color (brown eyes) Alleles – different genes (possibilities) for the same trait – ex: blue eyes or brown eyes

Gene Linkage Genes located on same chromosome – gene linkage Genes located on same chromosome cannot go through-- independent assortment Independent Assortment: Chromosomes are distributed to gametes randomly or independently Package of genes inherited together

Law of Independent Assortment Principle of Independent Assortment – genes for different traits can segregate independently during the formation of gametes. Therefore, the inheritance of one trait has no effect on the inheritance of another. Example: Hair color and Eye color These genes segregate independently and do not influence each other’s inheritance (i.e. not all people with blonde hair will have blue eyes).

Dominant and Recessive Genes Gene that prevents the other gene from “showing” – dominant Gene that does NOT “show” even through it is present – recessive Symbols – Dominant gene – upper case letter – T Recessive gene – lower case letter – t Recessive color Dominant color

(Always use the same letter for the same alleles— Example: Straight thumb is dominant to hitchhiker thumb T = straight thumb t = hitchhikers thumb (Always use the same letter for the same alleles— No S = straight, h = hitchhiker’s) Straight thumb = TT Straight thumb = Tt Hitchhikers thumb = tt * Must have 2 recessive alleles for a recessive trait to “show”

Both genes of a pair are the same – homozygous or purebred TT – homozygous dominant tt – homozygous recessive One dominant and one recessive gene – heterozygous or hybrid Tt – heterozygous BB – Black Bb – Black w/ white gene bb – White

Law of Segregation During the formation of gametes (eggs or sperm), the two alleles responsible for a trait separate from each other (during MEIOSIS) Alleles for a trait are then “recombined” at fertilization, producing the genotype for the traits of the offspring.

Genotype and Phenotype Combination of genes an organism has (actual gene makeup) – genotype Examples: TT, Tt, tt Physical appearance resulting from gene make-up – phenotype Ex: hitchhiker’s thumb or straight thumb

Law of Dominance In a cross of parents that are homozygous dominant and homozygous recessive, only one form of the trait will appear in the next generation. All the offspring will be heterozygous and express only the dominant trait. RR x rr yields all Rr (Round Seeds)

Generation “Gap” Parental P1 Generation = the parental generation in a breeding experiment. F1 generation = the first – generation offspring in a breeding. (1st filial generation) From breeding individuals from the P1 generation F2 generation = the second – generation offspring in a breeding experiment 2nd filial generation From breeding individuals in the F1 generation

Punnett Square and Probability Used to predict the possible gene makeup of offspring – Punnett Square Cross involving one trait -- monohybrid Example: Black fur (B) is dominant to white fur (b) in mice Cross a heterozygous male with a homozygous recessive female. Black fur (B) White fur (b) Heterozygous male Homozygous recessive female White fur (b) White fur (b)

Male = Bb X Female = bb Bb b B bb Female gametes – N (One gene in egg) Possible offspring – 2N Male gametes - N (One gene in sperm) Write the ratios in the following orders: Genotypic ratio homozygous : heterozygous : homozygous dominant recessive Phenotypic ratio dominant : recessive Genotypic ratio = 2 Bb : 2 bb 50% Bb : 50% bb Phenotypic ratio = 2 black : 2 white 50% black : 50% white

Practice Prob #2: Cross 2 hybrid mice and give the genotypic ratio and phenotypic ratio. Bb X Bb B b BB Bb bb B b Genotypic ratio = 1 BB : 2 Bb : 1 bb 25% BB : 50% Bb : 25% bb Phenotypic ratio = 3 black : 1 white 75% black : 25% white

Bb X Bb Man = Bb Woman = Bb B b BB Bb bb B b Problem #3: A man and woman, both with brown eyes (B) marry and have a blue eyed (b) child. What are the genotypes of the man, woman and child? What is the probability of them having a blue eyed child? Bb X Bb Man = Bb Woman = Bb B b BB Bb bb B 3 brown : 1 blue (2 carriers) ¼ or 25% blue b

DIHYBRID CROSSES: Cross involving 2 traits HOW TO: AABB x AABB 1st : Find Gametes 2nd: Reduce (if possible) 3rd: Produce Punnett Square

Gamete Formation Practice: Black fur (B) in guinea pigs is dominant to White Fur (b), and rough fur (R) in guinea pigs is dominant to smooth (r). Cross a heterozygous parent (BbRr) with a heterozygous parent (BbRr). Possible Gametes: Brown eyes (B) are dominant to blue eyes (b), and brown hair (H) is dominant to blonde hair (h). Cross a blued eyed, homozygous brown haired parent with a blue eyed, blonde haired parent. BbRr BbRr BR Br bR br Parent 1: BR, Br, bR, br BR Br bR br Parent 2: BR, Br, bR, br bbHH bbhh Parent 1: bH bH bh Parent 2: bh

BH Bh bH bh BBHH BBHh BbHH BbHh BBhh Bbhh bbHH bbHh bbhh Practice Problem #1: In rabbits black coat (B) is dominant over brown (b) and straight hair (H) is dominant to curly (h). Cross 2 hybrid rabbits and give the phenotypic ratio for the first generation of offspring. Possible gametes: BbHh X BbHh BH BH Bh Bh bH bH bh bh Gametes BH Bh bH bh BBHH BBHh BbHH BbHh BBhh Bbhh bbHH bbHh bbhh Phenotypes - 9:3:3:1 9 black and straight 3 black and curly 3 brown and straight 1 brown and curly

BBHH X BBHh BH Bh BBHH BBHh Practice Problem #2: In rabbits black coat (B) is dominant over brown (b) and straight hair (H) is dominant to curly (h). Cross a rabbit that is homozygous dominant for both traits with a rabbit that is homozygous dominant for black coat and heterozygous for straight hair. Then give the phenotypic ratio for the first generation of offspring. BBHH X BBHh Possible gametes: BH BH Bh BH Bh Gametes Phenotypes: BBHH BBHh 100% black and straight Gametes (Hint: Only design Punnett squares to suit the number of possible gametes-- Reduce.)

Sex Determination X X XX XY X Y What is the probability of a husband and wife having a boy or girl baby? Chance of having female baby? 50% male baby? 50% X X XX XY X Y Who determines the sex of the child? father

R r RR Rr rr R r Incomplete dominance and Codominance When one allele is NOT completely dominant over another (they blend) – incomplete dominance Example 1: In carnations the color red (R) is incompletely dominant over white (r). The hybrid color is pink. Give the genotypic and phenotypic ratio from a cross between 2 pink flowers. Rr X Rr R r RR Rr rr R r Genotypic = 1 RR : 2 Rr : 1 rr Phenotypic = 1 red : 2 pink : 1 white

When both alleles are expressed – Codominance Example 1: In certain species of chickens black feathers (FB) are codominant with white feathers (FW). Heterozygous chickens have black and white speckled feathers. Show the F1 from crossing 2 hybrid chickens. Give the genotypic and phenotypic ratio.

FB FW FBFW X FBFW FBFB FBFW FB FW FBFW FWFW FBFB = black FWFW = white FBFW = speckled FB FW FBFW X FBFW FBFB FBFW FB FW FBFW FWFW Genotypic = 1 FBFB : 2 FBFW : 1 FWFW Phenotypic = 1 black : 2 speckled: 1 white

Sex – linked Traits Genes for these traits are located only on the X chromosome (NOT on the Y chromosome) X linked alleles always show up in males whether dominant or recessive because males have only one X chromosome

Examples of recessive sex-linked disorders: colorblindness – inability to distinguish between certain colors (most common red/green) You should see 58 (upper left), 18 (upper right), E (lower left) and 17 (lower right). Color blindness is the inability to distinguish the differences between certain colors. The most common type is red-green color blindness, where red and green are seen as the same color.

2. hemophilia – blood won’t clot (blood clotting factor VIII defective)

3. Duchenne muscular dystrophy – wasting away of skeletal muscles

XN Xn XNXN XNXn XNY XnY XN Y Example 1: A female that has normal vision but is a carrier for colorblindness marries a male with normal vision. Give the expected phenotypes of their children. N = normal vision n = colorblindness XN Xn X XN Y XN Xn XNXN XNXn XNY XnY XN Phenotype: 1normal vision female 1 normal vision female (carrier) 1 normal vision male 1 colorblind male Y

Pedigrees Graphic representation of how a trait is passed from parents to offspring Tips for making a pedigree Circles are for females Squares are for males Horizontal lines connecting a male and a female represent a marriage Vertical line and brackets connect parent to offspring A shaded circle or square indicates a person has the trait A circle or square NOT shaded represents an individual who does NOT have the trait Partial shade indicates a carrier – someone who is heterozygous for the trait

Can pass trait to offspring Example 1: Make a pedigree chart for the following couple. Dana is color blind; her husband Jeff is not. They have two boys and two girls. HINT: Colorblindness is a recessive sex-linked trait. XnXn XNY Has trait Can pass trait to offspring

Multiple Alleles 3 or more alleles of the same gene that code for a single trait In humans, blood type is determined by 3 alleles – IA, IB, and iO BUT genes come in pairs, so each human can only inherit 2 alleles Codominant – IA, IB Recessive – iO 2. Blood type – A = IAIA or IAiO B = IBIB or IBiO AB = IAIB O = iOiO

IBIB X IA iO IB IB IA IAIB IAIB iO IBiO IBiO Example 1: A woman homozygous for type B blood marries a man who is heterozygous type A. What will be the possible genotypes and phenotypes of their children? IBIB X IA iO IB IB IA IAIB IAIB iO IBiO IBiO Genotypic = 2 IAIB : 2 IBiO Phenotypic = 2 AB : 2 B

Polygenic Inheritance Effect of 2 or more genes on a single phenotypic characteristic Examples: eye color, skin color, height, body mass

Skin color: dark is dominant to light, genes are not linked Ex: aabbcc = very light AABBCC = very dark   AaBbCc = medium color – 3 dominant, 3 recessive AABbcc = medium color – 3 dominant, 3 recessive Disorders that are polygenic: autism, diabetes, cancer

Gel Electrophoresis

Mutations Mutation – sudden genetic change (change in base pair sequence of DNA) Can be : Harmful mutations – organism less able to survive: genetic disorders, cancer, death 5 – 8 genes in humans results in death – lethal mutation Beneficial mutations – allows organism to better survive: provides genetic variation Neutral mutations – neither harmful nor helpful to organism Mutations can occur in 2 ways: chromosomal mutation or gene/point mutation Only mutations in sex cells are passed from parent to offspring

Chromosomal mutation: less common than a gene mutation more drastic – affects entire chromosome, so affects many genes rather than just one caused by failure of the homologous chromosomes to separate normally during meiosis (nondisjunction) chromosome pairs no longer look the same – too few or too many genes, different shape

Gene or Point Mutation most common and least drastic usually only one gene is altered

Examples: Recessive gene mutations: Sickle cell anemia – red blood cells are sickle shaped instead of round and get stuck in the blood vessels – can cut off blood supply to organs – heterozygous condition protects people from malaria

Cystic fibrosis – mucus clogs lungs, liver and pancreas Tay-Sachs Disease – deterioration of the nervous system – early death

Phenylketonuria (PKU) – an amino acid common in milk cannot be broken down and as it builds up it causes mental retardation – newborns are tested for this Dominant gene mutations: Huntington’s disease – gradual deterioration of brain tissue, shows up in middle age and is fatal Dwarfism – variety of skeletal abnormalities