Module 15-2 Objectives Determine a line of best fit for a set of linear data. Determine and interpret the correlation coefficient.

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Module 15-2 Objectives Determine a line of best fit for a set of linear data. Determine and interpret the correlation coefficient.

A residual is the signed vertical distance between a data point and a line of fit. Vocabulary The least-squares line for a data set is the line of fit for which the sum of the squares of the residuals is as small as possible. A line of best fit is the line that comes closest to all of the points in the data set, using a given process. Linear regression is a process of finding the least-squares line.

Vocabulary The correlation coefficient is a number r, where -1 ≤ r ≤ 1, that describes how closely the points in a scatter plot cluster around a line of best fit.

Example1: Calculating Residuals Two lines of fit for this data are y = 2x + 2 and y = x + 4. For each line, find the sum of the squares of the residuals. Which line is a better fit? X 1 2 3 4 Y 7 5 6 9

Example1: Continued Find the residuals y = x + 4: Sum of squared residuals: (2)2 + (–1)2 + (–1)2 + (1)2 4 + 1 + 1 + 1 = 7

Example1: Continued Find the residuals y = 2x + 2: Sum of squared residuals: (3)2 + (–1)2 + (–2)2 + (-1)2 9 + 1 + 4 + 1 = 15 The line y = x + 4 is a better fit.

Check It Out! Example 1 Two lines of fit for this data are For each line, find the sum of the squares of the residuals. Which line is a better fit? Y = - 2 1 x + 6 and y = -x + 8

Check It Out! Example 1 Continued Find the residuals. 2 1 y = – x + 6 : Sum of squared residuals: (–2)2 + (2)2 + (–2)2 + (2)2 4 + 4 + 4 + 4 = 16

Check It Out! Example 1 Continued Find the residuals. y = –x + 8: Sum of squared residuals: (–3)2 + (2)2 + (–1)2 + (4)2 9 + 4 + 1 + 16 = 30 y = - 2 1 The line x + 6 is a better fit

Example 2: Finding the Least-Squares Line The table shows populations and numbers of U.S. Representatives for several states in the year 2000. State Population (millions) Representatives AL 4.5 7 AK 0.6 1 AZ 5.1 8 AR 2.7 4 CA 33.9 53 CO 4.3

Example 2 Continued A. Find an equation for a line of best fit. Use your calculator. To enter the data, press STAT and select 1:Edit. Enter the population in the L1 column and the number of representatives in the L2 column. Then press STAT and choose CALC. Choose 4:LinReg(ax+b) and press ENTER. An equation for a line of best fit is y ≈ 1.56x + 0.02. y = 1.56x + 0.02

Example 2 Continued B. Interpret the meaning of the slope and y-intercept. Slope: for each 1 million increase in population, the number of Representatives increases by 1.56 million y-intercept: a state with a population of 0 (or less than a million) has 0.02 Representatives (or 1 Representative). C. Michigan had a population of approximately 10.0 million in 2000. Use your equation to predict Michigan’s number of Representatives. 16

r-values close to 1 or –1 indicate a very strong correlation r-values close to 1 or –1 indicate a very strong correlation. The closer r is to 0, the weaker the correlation. Helpful Hint

Additional Example 3: Correlation Coefficient The table shows a relationship between points allowed and games won by a football team over eight seasons. Year Points Allowed Games Won 1 285 3 2 310 4 301 186 6 5 146 7 159 170 8 190

Additional Example 3 Continued Find an equation for a line of best fit. How well does the line represent the data? Use your calculator. Enter the data into the lists L1 and L2. Then press STAT and choose CALC. Choose 4:LinReg(ax+b) and press ENTER. An equation for a line of best fit is y ≈ –0.02x + 9.91. The value of r is about –0.91, which represents the data very well.

Additional Example 4: Correlation and Causation Additional Example 4: Malik is a contractor, installing windows for a builder. The table shows data for his first eight weeks on the job. The equation of the least-squares line for the data is y ≈ -10.36x + 53, and r ≈ -0.88. Discuss correlation and causation for the data set.

Example 4 Continued Week Average Time per Window (hr) Net Profit per Hour ($) 1 3.5 19 2 2.8 25 3 2.5 24 4 2.1 26 5 2.3 30 6 1.9 37 7 1.7 35 8 1.8 39 There is a strong negative correlation. There is likely a cause-and-effect relationship (likely that less installation time contributes to a greater profit per hour).

Check It Out! Example 4 Eight adults were surveyed about their education and earnings. The table shows the survey results. The equation of the least-squares line for the data is y ≈ 5.59x - 30.28 and r ≈ 0.86. Discuss correlation and causation for the data set. There is a strong positive correlation. There is a likely cause-and-effect relationship (more education often contributes to higher earnings).

Turn to p. 431 – we’re going to now do an exponential example w/ graphing calcs! Now try #2 on your own! Quiz is Wednesday! Tonight’s HW: p. 434 #1-9 & p. 435 #1-4 all