Matter and Energy Jeopardy

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Presentation transcript:

Matter and Energy Jeopardy Types of Matter Properties and Changes Kinetic Energy Potential Energy Fun With Calorimetry 100 100 100 100 100 200 200 200 200 200 300 300 300 300 300 400 400 400 400 400 500 500 500 500 500

Help (1) Save a duplicate of this template. (2) Enter all answers and questions in the outline view. (3) View as a slideshow. (4) Use the home red button after each question. ©Norman Herr, 2000

A-100 ANSWER: I can be decomposed only by chemical change. What am I? QUESTION: Compound

A-200 ANSWER: I can be decomposed by physical change. What am I? QUESTION: Mixture

A-300 ANSWER: I cannot be decomposed by physical or chemical change. What am I? QUESTION: An element

A-400 ANSWER: How would you classify a solution of sodium chloride in water (NaCl (aq)) ? QUESTION: Homogeneous Mixture

A-500 ANSWER: I am a solution of iodine mixed with alcohol. I am not an aqueous solution, what am I? QUESTION: Tincture

B-100 ANSWER: List three physical properties QUESTION:

B-200 ANSWER: List three physical changes QUESTION:

B-300 ANSWER: List three chemical changes QUESTION:

B-400 ANSWER: List three chemical properties. QUESTION:

B-500 ANSWER: Is this a physical or chemical property or change: Gold is a soft metal that can be drawn out into extremely thin wires than are excellent conductors of electricity. QUESTION: Physical properties

C-100 ANSWER: What measuring tool can be used to measure the average kinetic energy of a substance? QUESTION: Thermometer

C-200 ANSWER: Convert 10oC to K, show your work. QUESTION: 10oC + 273 = 283 K

C-300 ANSWER: Convert 50 K to Celsius, showing your work. QUESTION: 50 K - 273 = -223 oC

C-400 ANSWER: Which substance has higher average kinetic energy: 10.0 g of water at 50oC or 40.0 g of water at 310 K? QUESTION: 50oC is the higher temperature.

C-500 ANSWER: Your house is at a toasty 27oC and you open the front door. Outside the temperature is 277 K. Will heat flow into or out of the house? Explain. QUESTION:

D-100 ANSWER: Define potential energy. QUESTION: Stored energy

D-200 ANSWER: Where is chemical energy stored? QUESTION: Chemical bonds

D-300 ANSWER: Dissolving sodium hydroxide in water makes the temperature increase. What kind of change is this (and I don’t mean physical or chemical)? QUESTION: Exothermic

D-400 ANSWER: Burning a macadamia nut in a bomb calorimeter filled with water causes the temperature of the water to increase. Is PE being lost or gained, and what is doing the losing or gaining of the PE? QUESTION: The macadamia nut is losing PE.

D-500 ANSWER: Placing an ice cube in water in a calorimeter makes the temperature decrease. Explain the changes in PE and KE that are taking place. Who is losing what? Who is gaining what? QUESTION: The ice is gaining PE as the water loses KE.

E-100 ANSWER: How many joules are needed to heat 100.0 g of water in a calorimeter by 10oC? Show your work. QUESTION: q =mcDT = 100.0 g X 4.2j/g.oC X 10oC = 4200 J

E-200 ANSWER: The addition of 1000. J to a sample of water changed the temperature from 20.0oC to 30.0oC. What is the mass of the water? Show you work. QUESTION: m = q/cDT = 1000. J / (4.2 J/g-oC X 10.0oC) = 23.8 g

E-300 ANSWER: If 1000. J of energy are added to 20.0 grams of water, how much would the temperature change by? QUESTION: q=mcDT, so DT = q/mc, = 1000. J / (4.2 J/g-oC X 20.0 g) = 12oC

E-400 ANSWER: If 500.0 J are added to 100.0 g of water at 25.0oC, what will the final temperature be? QUESTION: q=mcDT, so DT = q/mc, = 500.0 J / (100.0 g X 4.2 J/g-oC) =1.2oC. Since we added this to 25.0, the final temperature is 26.2oC.

E-500 ANSWER: If 500.0 J are removed from 100.0 g of water at 25.0oC, what will the final temperature be? QUESTION: q=mcDT, so DT = q/mc, = 500.0 J / (100.0 g X 4.2 J/g-oC) =1.2oC. Since we removed this from 25.0, the final temperature is 23.8oC.