Chapter 6: Normal Distribution Review

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Presentation transcript:

Chapter 6: Normal Distribution Review 2006 Unit 11 Day 11 Last Man Standing.ppt Chapter 6: Normal Distribution Review Last Man Standing

Directions Choose any “Man” to pick a problem. Do the problem on your answer sheet. This will be collected for participation points! Check answers on the screen. Fix your work! Prizes are ELIMINATED as we go. The “Last Man Standing” will be your prize!

2006 Unit 11 Day 11 Last Man Standing.ppt MILDLY SOMEWHAT TOTALLY COSTUMED MAN Round Of Applause Piece of Gum No Prize! WEIRD Candy High Five ANGRY Extra Credit Pt Fist Bump Click on the “Home” symbol on each slide to return to this main page during the viewing of the slide show.

Mrs. Green’s daughter is weighed at the pediatrician and compared to all other babies that are the same age. The doctor gives her weight with a z-score of 0.71. What percent of all babies are HEAVIER than Mrs Green’s baby?

.2389 or 23.89%

The number of pieces of candy kids get on halloween is normally distributed with a mean of 35 pieces of candy and a standard deviation of 8.4. What percent of kids will get less than 20 pieces of candy?

.0367 or 3.67%

The amount of water that a high school student drinks during the day is normally distributed with a mean of 2.25L and a standard deviation of 1.3 L. What percent of students drink between 2 and 3 liters of water each day?

Z-Scores: -0.19 & 0.58 Percentages: 0.4247 & 0.7190 Answer: .2943 or 29.43%

In a Normal Distribution with a mean of 15 and a standard deviation of 4.1, what z-scores would represent the most extreme 8%?

Z < -1.75 or Z > 1.75

On a college chemistry exam, the scores are normally distributed with a mean of 74 and a standard deviation of 9.5. The professor has decided that the middle 40% of the scores will receive a C. Between what two scores is the range for a C?

Answer: 69.06 < x < 78.94

NO CALCULATOR!! After polling a group of 8th graders, it was determined that the amount of sleep they got each night was a normal distribution with parameters N(7.8, 1.1). What percent of students got less than 6.7 hours of sleep?

Draw the 68-95-99.7 Rule!! Answer: 100 – 68 = 32 32/2 = 16%

Blood tests often detect potential problems by measuring different components in your blood. These measurements are compared to normal measurements to determine if a problem exists. In one study of glucose levels, a mean of 89.3 and standard deviation of 6.2 was observed in study participant. What glucose level would be more alarming, a reading of 105 or a reading of 75.2?

Z-score of 105: 2.53 Z-score of 75.2: -2.27 While both are very far from the mean, the reading of 105 would be more concerning.

An ELL teacher is trying to identify students who have become proficient enough in English to be phased out of the program. Each year they take a test that is normally distributed with the following parameters: N(85, 7.2). She feels that the top 10% of students would be considered proficient. What test score would a student have to get to be considered proficient?

 

2006 Unit 11 Day 11 Last Man Standing.ppt  

2006 Unit 11 Day 11 Last Man Standing.ppt -0.7 < z < 0.7 Percentiles: 0.2420 & 0.7580 Answer: 0.516 or 51.6%