DO NOW Get out Review of Basic Skills packet

Slides:



Advertisements
Similar presentations
“Stoichiometry” Mr. Mole u First… –A bit of review.
Advertisements

Section Percent Composition and Chemical Formulas
1 Chapter 6 Chemical Quantities. 2 How you measure how much? How you measure how much? n You can measure mass, n or volume, n or you can count pieces.
1 Chapter 8 Chemical Quantities. 2 How you measure how much? How you measure how much? n You can measure mass, n or volume, n or you can count pieces.
Chapter 7 – The Mole and Chemical Composition
Q3U2 :Theoretical Yield, Mass Percents, and Empirical Formulas.
Chapter 6 Chemical Quantities. How you measure how much?  You can measure mass, or volume, or you can count pieces.  We measure mass in grams.  We.
 The Mole Chemists have adopted the mole concept as a convenient way to deal with the enormous numbers of atoms, molecules or ions in the samples they.
Chapter 7 Chemical Quantities or How do you measure how much? You can measure mass, volume, or you can count pieces of a substance. We measure mass in.
Chemical Quantities and The Mole
CHAPTER 7: The Mole.
Chapter 11. Mole SI base unit for measuring the amount of substance The number of representative particles in exactly 12 grams of pure carbon-12 1 mole.
Unit 10 – The Mole Essential Questions:
Unit 5: The Mole.
Unit 6 Moles Conversions Formulas. Mole SI base unit for measuring the amount of substance The number of representative particles in exactly 12 grams.
Counting Large Quantities Many chemical calculations require counting atoms and molecules Many chemical calculations require counting atoms and molecules.
Stoichiometry Chemistry 11 Chapter 2 Pg The Mole A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000.
Chapter 7.3.  How do we use these?  These indicate which of the elements make up a substance.  These also indicate the number of ions or atoms that.
Stoichiometry Chemistry I: Chapter 9 Molar Mass of Compounds The molar mass (MM) of a compound is determined the same way, except now you add up all.
1 Chapter 10 “Chemical Quantities” Yes, you will need a calculator for this chapter!
The mole (abbreviation: mol) is the amount of substance equal to 6.02 x particles These particles can be atoms, ions, formula units,molecules, electrons,
Mole Calculations. The Mole Mole – measurement of the amount of a substance. –We know the amount of different substances in one mole of that substance.
IIIIIIIV Chapter 10 – Chemical Quantities What is the Mole? n A unit of measurement used in chemistry. n A counting number like – a dozen eggs, a ream.
Stoichiometry The Mole A counting unit A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000 Similar to a dozen,
It’s time to learn about.... Stoichiometry Stoichiometry : Mole Ratios to Determining Grams of Product At the conclusion of our time together, you should.
Counting by weighing Calculate the amount of pennies in the cup by weighing them. You may take 10 pennies out of the cup to weigh them, but do not count.
Chapter 7 Chemical Quantities or How you measure how much? You can measure mass, volume, or you can count pieces of a substance. We measure mass in grams.
STOICHOMETRY MATH REVIEW. DO NOW 4/22/16 Water H 2 0  How many hydrogen molecules are there in one molecule of water?  How many oxygen molecules are.
…Chemical Composition. Why it’s important? Everything is either chemically or physically combined with other things. Cookie=physically combined The atom.
Using Chemical Formulas
Formulas and the Mole.
Chapter 11 The Mole.
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
The MOLE It’s a beauty mark… It’s a small furry garden pest…
Stoichiometry.
Chapter 7 “Chemical Formulas and Chemical Compounds”
Stoichiometry.
AHS CHEMISTRY GUTIERREZ
Formula & Equation Stoichiometry
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
The Mole To play the movies and simulations included, view the presentation in Slide Show Mode X 1023.
Chapter 4: Chemical Composition
Stoichiometry Chemistry I: Chapter 11
Chemical Quantities Part I
Using Chemical Formulas
Chapter 10 “Chemical Quantities”
The Mole To play the movies and simulations included, view the presentation in Slide Show Mode X 1023.
Chapter 10 The Mole Molar Mass
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
Moles.
The Mole Chapter 10.1.
10.1 Chemical Measurement.
Measurements of Matter
Introduction to Chemical Principles
STOICHIOMETRY BASICS Chemistry.
Unit 6 Mole Calculations
Stoichiometry Molar mass, Percent composition, Moles, Conversions, Empirical formulas, Molecular formulas.
Introduction to Chemical Principles
Stoichiometry Chemistry I: Chapter 11
The Mole through Percent Yield
Stoichiometry.
Stoichiometry.
The Mole: A Shortcut for Chemists
The Mole.
Vocabulary Percent Composition -
The Mole To play the movies and simulations included, view the presentation in Slide Show Mode X 1023.
The Mole.
Chapter 7- Sec. 3 and 4 “Chemical Formulas and Chemical Compounds”
The Mole To play the movies and simulations included, view the presentation in Slide Show Mode X 1023.
Stoichiometry Chemistry I: Chapter 12 Chemistry I HD: Chapter 9
Presentation transcript:

DO NOW Get out Review of Basic Skills packet Pick up notes and get out a calculator. Pick up small piece of paper and put your name on it Look at the jar of M & Ms. Guess how many candies are in the jar. YOU MAY NOT TOUCH THE JAR! Write your guess on the paper and place it in the basket– please do NOT fold the paper.

SCIENTIFIC NOTATION 16. Make the following calculations, expressing your answer in scientific notation. a. (8.00 x 1015) • (8.00 x 1015) = b. (4.00 x 102) • (3.00 x 1012) = c. 8.00 x 1015  2.00 x 106 = d. 1.60 x 10-8  2.00 x 1014 =

THE MOLE Introduction Matter is made up of particles. A particle can be an atom, ion, molecule, or formula unit.   Individual (molecular) (ionic) atoms Molecules Formula units ions Fe H2O NaCl SO4-2 He N2 CaCl2 NH4+1

THE MOLE You should be able to tell how many atoms are in each chemical formula. Fe H2O CaCl2 Mg(OH) 2

Number of candies So, how many candies are there? How can we determine this without actually counting them?

NUMBER OF CANDIES Mass of 10 M&Ms = ____________ Mass of one M&M = ___________ Total mass of M&Ms = ______________ Number of M&Ms in jar = __________

Why count by massing? So why can’t we just count everything? The United States Mint counts money by massing, using well established averages to quickly count by mass millions of coins more accurately than any human or coin counting machine. We certainly cannot count all the atoms in a bottle of water.

ATOMIC MASS, FORMULA MASS, and MOLECULAR MASS These are all the same thing, calculated the same way. They are for atoms (atomic mass), ionic compounds (formula mass), and covalent compounds (molecular mass). Answers are always two places past the decimal point since that what all our masses are. Different atoms have different masses; THEREFORE different compounds have masses dependent upon the masses of the atoms that make them up.

ATOMIC MASS This is the mass of an atom in atomic mass units (amu). It is the same as the average mass of the atoms of an element found on the periodic table. Example: C - single atom – 12.01 amu Na – single atom – 22.99 amu Br – single atom – 79.90 amu

MOLECULAR MASS This is the mass found by adding the atomic masses of the elements found in the molecule (molecular compound). Example: H2O – molecular compound H (2 x 1.01amu) = 2.02 O (1x16.00amu) = 16.00 18.02 amu

FORMULA MASS This is mass found by adding up the atomic masses of the elements found in a formula unit (ionic compound).   Example: NaCl – ionic compound Na (1 x 22.99amu) = 22.99 Cl (1 x 35.45amu) = 35.45 58.44 amu

ATOMIC MASS, FORMULA MASS, and MOLECULAR MASS Let’s try some (show your work): H2SO4 C3H5N3O3 Al(NO3)3 Fe(C2H3O2)3

Practice H2SO4 H (2 x 1.01 amu) = 2.02 S (1 x 32.06 amu) = 32.06 C3H5N3O3 C (3 x 12.01 amu) = 36.03 H (5 x 1.01 amu) = 5.05 N (3 x 14.01 amu) = 42.03 O (3 x 16.00 amu) = 48.00 131.11 amu

practice Al(NO3)3 Al (1 x 26.98 amu) = 26.98 N (3 x 14.01 amu) = 42.03 O (9 x 16.00 amu) = 144.00 213.01 amu Fe(C2H3O2)3 Fe (1 x 55.85 amu) = 55.85 C (6 x 12.01 amu) = 72.06 H (9 x 1.01 amu) = 9.09 O (6 x 16.00 amu) = 96.00 233.00 amu

Percent composition We can use these masses to determine the percent by mass. Remember that percent means part divided by whole.

Total = 450.0g + 450.0g + 75.0g + 900.0g + 0.002g + 0.002g + 0.002g = Percent composition For Example: Chocolate Chip Cookies: 450.0g sugar 20.0mg salt 450.0g Crisco 20.0mg baking soda 2 eggs (75.0g) 20.0mg vanilla 900.0g flour To Calculate: 1. Get the total amount (add up all the ingredients). Total = 450.0g + 450.0g + 75.0g + 900.0g + 0.002g + 0.002g + 0.002g = 1875.006g = 1875.0g 2. Find the percentage of the total that is eggs. 75.0g x 100 = 4.00 % 1875.0 Looking at the ingredients, what percentage of the total composition is eggs? part x 100 total

Percent composition What is the mass percent of hydrogen in sulfuric acid? %H in H2SO4?

TO DO Do the 12 molar masses MY WAY Write the atoms, the numbers, the masses, and do the math. Unit = amu. Calculate the Percent Composition problems on the back. Lab tomorrow – need to know your lab partner by then.