Dalton’s, Boyle’s and Charles’s Laws

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Boyle’s and Charles’s Laws
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Presentation transcript:

Dalton’s, Boyle’s and Charles’s Laws Day 2 – Notes Unit: Gas Laws Dalton’s, Boyle’s and Charles’s Laws

After today you will be able to… Describe Dalton’s law of partial pressures and calculate Ptotal or a partial pressure Explain the effect on gas properties using Boyle’s and Charles’s laws Calculate an unknown pressure, temperature, or volume by solving algebraically

Recall, gas pressure results from collisions of gas particles. Gas pressure depends on the amount of gas and the KE of its particles. Since particles in a mixture of gases at the same temperature contain the same average KE, the kind of particle is unimportant.

Example: Composition of Dry Air Component Volume Partial Pressure Nitrogen 78.08% 79.11 kPa Oxygen 20.95% 21.22 kPa Carbon dioxide 0.04% 0.04 kPa MISC gases 0.93% 0.95 kPa Total 100.00% 101.32 kPa

“The total pressure of a mixture of gases is equal to the sum of the individual (partial) pressures.”

Dalton’s Law of Partial Pressures Units of pressure must match! Ptotal= P1 + P2 + P3…

Example: Dalton’s Law What is the total pressure for a mixture of O2 and CO2 if PO2= 0.719 atm and PCO2= 423mmHg. PO2= 0.719atm PCO2= 423mmHg 760mmHg x = 546mmHg 1atm Ptotal=546mmHg + 423mmHg Ptotal=969mmHg

Boyle’s Law: Pressure and Volume Robert Boyle was the first person to study the pressure-volume relationship of gases. In 1662 Boyle proposed a law to describe this relationship.

“For a given mass of a gas at constant temperature, the volume of a gas varies inversely with pressure.”

Boyle’s Law: Pressure and Volume We can simplify this relationship by the formula: Where, P1, P2 = pressure in any unit (atm, kPa, mmHg), BUT they must match! V1, V2 = volume in any unit (usually, L or mL), BUT they must match! P1 V1 = P2 V2

Boyle’s Law: Example P1 V1=P2 V2 V2 180L = A gas has a volume of 30.0L at 150 kPa. What is the volume of the gas at 0.252 atm? P1= V1= P2= V2= 1 atm 150 kPa x P1 V1=P2 V2 = 1.5 atm 101.3 kPa 30.0L 0.252 atm ? (1.5 atm) (30.0L) = (0.252 atm) (V2) V2 = 180L

Charles’s Law: Temperature and Volume Jacques Charles studied the effect of temperature on volume of a gas at constant pressure. In 1787 Charles proposed a law to describe his observations.

“For a given mass of a gas, at constant pressure, the volume of the gas is directly proportional to its temperature in Kelvin.”

Charles’s Law: Temperature and Volume We can simplify this relationship by the formula: Where, V1, V2 = volume in any unit (L or mL), BUT they must match! T1, T2 = temperature is always in Kelvin! (Recall, just add 273 + °C) V1 V2 T1 T2 =

Charles’s Law: Example A gas has a volume of 4.0L at 27°C. What is its volume at 153°C? V1= T1= V2= T2= V1 V2 T1 T2 4.0L = 27°C +273= 300K ? 153°C+273= 426K (4.0L) (V2) = (300K) (426K) V2 = 5.7L

Questions? Complete WS 2