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Exam II Thursday, November 2, 7:00-9:00 pm; rooms are on the website. Conflict: (11/2) 4:30-6:30pm in 101 Transportation Building; sign up in 1026 CA Conflict with conflict? Email me right away. Review sessions: Monday (10/30): 161 Noyes Lab; 7-9 pm Tuesday (10/31): 1024 Chem Annex; 7-9 pm

Exam II Practice exam now posted.. Take when you feel ready for the exam. Take as an actual exam (not just more practice problems). See the front of the exam for information that you are given and the number of problems.

Clicker Question SO2(g) and O2(g) react to form SO3(g). The partial pressures at equilibrium are as follows: P(SO2) = 0.559 atm, P(O2) = 0.101 atm, and P(SO3) = 0.331 atm at 1000.0 K . Calculate ΔG° at 1000.0 K for the reaction 2SO2(g) + O2(g) 2SO3(g). a) 0 b) 14.7 kJ/mol c) –14.7 kJ/mol d) –10.3 kJ/mol e) 10.3 kJ/mol

Clicker Question For the reaction 2HF(g) H2(g) + F2(g), G° = 38.3 kJ, at 1000 K. If, at this temperature, 5.00 mol of HF(g), 0.500 mol of H2(g), and 0.75 mol of F2(g) are mixed in a 1.00-L container: a) Some HF will decompose (to yield H2 and F2). b) Some HF will be formed (from H2 and F2). c) The system is at equilibrium. d) Not enough data are given to answer this question. e) I do not know.

Clicker Question (1/2) Given that for H2O(l), Gf = ‒237.0 kJ/mol, determine the value of the equilibrium constant at 25.0C for the reaction: 2H2(g) + O2(g) 2H2O(l). a) 1.10 b) 6.83 x 1024 c) 3.50 x 1041 d) 1.22 x 1083 e) I do not know.

Clicker Question (2/2) How would the value of K change if the reaction was carried out at 90.0C? The value of K90 would be _______ than the value of K25 because the reaction is ______. 2H2(g) + O2(g) 2H2O(l). a) greater, exothermic b) greater, endothermic c) less, exothermic d) less, endothermic e) The value of K would not change (it is, after all, called the equilibrium constant).