LECTURE 6.3 –GAY – LUSSAC’S LAW

Today’s Learning Targets LT 5.8 – I can explain Charles Law, how it relates to temperature and volume, and I can calculate temperature and volume values for a given problem LT 5.9 – I can explain Gay-Lussac’s Law, how it relates to temperature and pressure, and I can calculate temperature and pressure values for a given problem.

What does Gay – Lussac’s Law state?

I. Pressure and Temperature Relationship Gas molecules move quicker the more we heat them up. This means that they will be hitting the sides of the container more often. Therefore, the pressure will also increase as the temperature increases. If we keep volume constant, then pressure and temperature are directly related.

Gay-Lussac’s Law

This is an direct relationship! As one goes up the other goes up! Gay-Lussac’s Law Absolute Zero This is an direct relationship! As one goes up the other goes up!

Using what you Know now, Why did the Pop Can Get Crushed?

How do you calculate using Gay – Lussac’s Law?

Gay-Lussac’s Law Gay-Lussac’s Law relates pressure and temperature through the expression:

Class Example An aerosol can containing gas at 101 kPa and 22 oC is heated to 55 oC. Calculate the pressure in the heated can.

Table Talk The gas in a balloon begins at 122 oC and 2 atm. If the gas is decreased to 1 atm, then what is the temperature?

Stop and Jot You have a gas that is 111 kPa and a temperature of 273 K. What is the new pressure you increase the temperature to 373 K.