7 INVERSE FUNCTIONS.

Slides:



Advertisements
Similar presentations
3.2 Inverse Functions and Logarithms 3.3 Derivatives of Logarithmic and Exponential functions.
Advertisements

The inverse of f (x), denoted f −1(x), is the function that reverses the effect of f (x).
The Derivative as a Function
3 DERIVATIVES.
FUNCTIONS AND MODELS Chapter 1. Preparation for calculus :  The basic ideas concerning functions  Their graphs  Ways of transforming and combining.
LIMITS Continuity LIMITS In this section, we will: See that the mathematical definition of continuity corresponds closely with the meaning of the.
1 Chapter 7 Transcendental Functions Inverse Functions and Their Derivatives.
7 INVERSE FUNCTIONS.
FURTHER APPLICATIONS OF INTEGRATION 9. In chapter 6, we looked at some applications of integrals:  Areas  Volumes  Work  Average values.
7 INVERSE FUNCTIONS. The common theme that links the functions of this chapter is:  They occur as pairs of inverse functions. INVERSE FUNCTIONS.
Logarithmic, Exponential, and Other Transcendental Functions 5 Copyright © Cengage Learning. All rights reserved.
LIMITS AND DERIVATIVES 2. We noticed in Section 2.3 that the limit of a function as x approaches a can often be found simply by calculating the value.
 We noticed in Section 2.3 that the limit of a function as x approaches a can often be found simply by calculating the value of the function at a.  Functions.
DERIVATIVES The Derivative as a Function DERIVATIVES In this section, we will learn about: The derivative of a function f.
DERIVATIVES The Derivative as a Function DERIVATIVES In this section, we will learn about: The derivative of a function f.
Copyright © Cengage Learning. All rights reserved.
 The functions that we have met so far can be described by expressing one variable explicitly in terms of another variable.  For example,, or y = x sin.
3 DIFFERENTIATION RULES. The functions that we have met so far can be described by expressing one variable explicitly in terms of another variable. 
3 DERIVATIVES. In this section, we will learn about: Differentiating composite functions using the Chain Rule. DERIVATIVES 3.5 The Chain Rule.
INTEGRALS The Fundamental Theorem of Calculus INTEGRALS In this section, we will learn about: The Fundamental Theorem of Calculus and its significance.
Copyright © Cengage Learning. All rights reserved. 1 Functions and Models.
1 FUNCTIONS AND MODELS.
FUNCTIONS AND MODELS 1. The fundamental objects that we deal with in calculus are functions.
Copyright © Cengage Learning. All rights reserved. 6 Inverse Functions.
3 DERIVATIVES.  Remember, they are valid only when x is measured in radians.  For more details see Chapter 3, Section 4 or the PowerPoint file Chapter3_Sec4.ppt.
1 Copyright © Cengage Learning. All rights reserved. Functions 3.
College Algebra Fifth Edition James Stewart Lothar Redlin Saleem Watson.
INTEGRALS 5. INTEGRALS In Chapter 3, we used the tangent and velocity problems to introduce the derivative—the central idea in differential calculus.
Copyright © Cengage Learning. All rights reserved. Functions.
Copyright © 2013, 2009, 2005 Pearson Education, Inc. 1 4 Inverse, Exponential, and Logarithmic Functions Copyright © 2013, 2009, 2005 Pearson Education,
Functions 2 Copyright © Cengage Learning. All rights reserved.
APPLICATIONS OF DIFFERENTIATION Antiderivatives In this section, we will learn about: Antiderivatives and how they are useful in solving certain.
5.3 Trigonometric Graphs.
Trigonometric Identities
Logarithmic, Exponential, and Other Transcendental Functions
3 DERIVATIVES.
Copyright © Cengage Learning. All rights reserved.
7 INVERSE FUNCTIONS.
Copyright © Cengage Learning. All rights reserved.
5.3 The Fundamental Theorem of Calculus
Copyright © Cengage Learning. All rights reserved.
7 INVERSE FUNCTIONS.
2.7 Combining Functions.
DIFFERENTIATION RULES
Transcendental Functions
Copyright © Cengage Learning. All rights reserved.
CHAPTER 5: Exponential and Logarithmic Functions
Copyright © Cengage Learning. All rights reserved.
Copyright © Cengage Learning. All rights reserved.
Logarithmic, Exponential, and Other Transcendental Functions
Transformations of Functions
CHAPTER 5: Exponential and Logarithmic Functions
5 Logarithmic, Exponential, and Other Transcendental Functions
1 FUNCTIONS AND MODELS.
Copyright © Cengage Learning. All rights reserved.
5.3 Trigonometric Graphs.
1.6 Inverse Functions and Logarithms
5 INTEGRALS.
5 Logarithmic, Exponential, and Other Transcendental Functions
Copyright © Cengage Learning. All rights reserved.
The Derivative as a Function
2.5 Continuity In this section, we will:
College Algebra Fifth Edition
1.6 Inverse Functions and Logarithms
Section 11.2 Inverse Functions.
CHAPTER 5: Exponential and Logarithmic Functions
Derivatives of Inverse Functions
Copyright © Cengage Learning. All rights reserved.
Derivatives of Logarithmic and Exponential functions
Presentation transcript:

7 INVERSE FUNCTIONS

The common theme that links the functions of this chapter is: INVERSE FUNCTIONS The common theme that links the functions of this chapter is: They occur as pairs of inverse functions.

INVERSE FUNCTIONS In particular, two among the most important functions that occur in mathematics and its applications are: The exponential function f(x) = ax. The logarithmic function g(x) = logax, the inverse of the exponential function.

In this chapter, we: Investigate their properties. INVERSE FUNCTIONS In this chapter, we: Investigate their properties. Compute their derivatives. Use them to describe exponential growth and decay in biology, physics, chemistry, and other sciences.

We also study the inverses of trigonometric and hyperbolic functions. INVERSE FUNCTIONS We also study the inverses of trigonometric and hyperbolic functions. Finally, we look at a method (l’Hospital’s Rule) for computing difficult limits and apply it to sketching curves.

INVERSE FUNCTIONS There are two possible ways of defining the exponential and logarithmic functions and developing their properties and derivatives. You need only read one of these two approaches—whichever your instructor recommends.

INVERSE FUNCTIONS One is to start with the exponential function (defined as in algebra or precalculus courses) and then define the logarithm as its inverse. This approach is taken in Sections 7.2, 7.3, and 7.4. This is probably the most intuitive method.

INVERSE FUNCTIONS The other way is to start by defining the logarithm as an integral and then define the exponential function as its inverse. This approach is followed in Sections 7.2*, 7.3*, and 7.4*. Although it is less intuitive, many instructors prefer it because it is more rigorous and the properties follow more easily.

7.1 Inverse Functions In this section, we will learn about: Inverse functions and their calculus.

The table gives data from an experiment INVERSE FUNCTIONS The table gives data from an experiment in which a bacteria culture started with 100 bacteria in a limited nutrient medium. The size of the bacteria population was recorded at hourly intervals. The number of bacteria N is a function of the time t: N = f(t).

However, suppose that the biologist changes INVERSE FUNCTIONS However, suppose that the biologist changes her point of view and becomes interested in the time required for the population to reach various levels. In other words, she is thinking of t as a function of N.

This function is called the inverse function of f. INVERSE FUNCTIONS This function is called the inverse function of f. It is denoted by f -1 and read “f inverse.”

Thus, t = f -1(N) is the time required for INVERSE FUNCTIONS Thus, t = f -1(N) is the time required for the population level to reach N.

The values of f -1can be found by reading INVERSE FUNCTIONS The values of f -1can be found by reading the first table from right to left or by consulting the second table. For instance, f -1(550) = 6, because f(6) = 550.

Not all functions possess inverses. INVERSE FUNCTIONS Not all functions possess inverses. Let’s compare the functions f and g whose arrow diagrams are shown.

Note that f never takes on the same value twice. INVERSE FUNCTIONS Note that f never takes on the same value twice. Any two inputs in A have different outputs.

However, g does take on the same value twice. INVERSE FUNCTIONS However, g does take on the same value twice. Both 2 and 3 have the same output, 4.

but f(x1) ≠ f(x2) whenever x1 ≠ x2 INVERSE FUNCTIONS In symbols, g(2) = g(3) but f(x1) ≠ f(x2) whenever x1 ≠ x2

Functions that share this property INVERSE FUNCTIONS Functions that share this property with f are called one-to-one functions.

A function f is called a one-to-one ONE-TO-ONE FUNCTIONS Definition 1 A function f is called a one-to-one function if it never takes on the same value twice. That is, f(x1) ≠ f(x2) whenever x1 ≠ x2

If a horizontal line intersects the graph of f ONE-TO-ONE FUNCTIONS If a horizontal line intersects the graph of f in more than one point, then we see from the figure that there are numbers x1and x2 such that f(x1) = f(x2). This means f is not one-to-one.

So, we have the following geometric method for determining ONE-TO-ONE FUNCTIONS So, we have the following geometric method for determining whether a function is one-to-one.

A function is one-to-one if and only if HORIZONTAL LINE TEST A function is one-to-one if and only if no horizontal line intersects its graph more than once.

Is the function f(x) = x3 one-to-one? ONE-TO-ONE FUNCTIONS Example 1 Is the function f(x) = x3 one-to-one?

If x1 ≠ x2, then x13 ≠ x23. ONE-TO-ONE FUNCTIONS E. g. 1—Solution 1 Two different numbers can’t have the same cube. So, by Definition 1, f(x) = x3 is one-to-one.

From the figure, we see that no horizontal ONE-TO-ONE FUNCTIONS E. g. 1—Solution 2 From the figure, we see that no horizontal line intersects the graph of f(x) = x3 more than once. So, by the Horizontal Line Test, f is one-to-one.

Is the function g(x) = x2 one-to-one? ONE-TO-ONE FUNCTIONS Example 2 Is the function g(x) = x2 one-to-one?

The function is not one-to-one. ONE-TO-ONE FUNCTIONS E. g. 2—Solution 1 The function is not one-to-one. This is because, for instance, g(1) = 1 = g(-1) and so 1 and -1 have the same output.

From the figure, we see that there are ONE-TO-ONE FUNCTIONS E. g. 2—Solution 2 From the figure, we see that there are horizontal lines that intersect the graph of g more than once. So, by the Horizontal Line Test, g is not one-to-one.

One-to-one functions are important because: They are precisely the functions that possess inverse functions according to the following definition.

Let f be a one-to-one function with domain A and range B. ONE-TO-ONE FUNCTIONS Definition 2 Let f be a one-to-one function with domain A and range B. Then, its inverse function f -1 has domain B and range A and is defined by for any y in B.

The definition states that, if f maps x ONE-TO-ONE FUNCTIONS The definition states that, if f maps x into y, then f -1 maps y back into x. If f were not one-to-one, then f -1 would not be uniquely defined.

The arrow diagram in the figure ONE-TO-ONE FUNCTIONS The arrow diagram in the figure indicates that f -1 reverses the effect of f.

Note that: domain of f -1 = range of f range of f -1 = domain of f ONE-TO-ONE FUNCTIONS Note that: domain of f -1 = range of f range of f -1 = domain of f

For example, the inverse function of f(x) = x3 is f -1(x) = x1/3. ONE-TO-ONE FUNCTIONS For example, the inverse function of f(x) = x3 is f -1(x) = x1/3. This is because, if y = x3, then f -1(y) = f -1(x3) = (x3)1/3 = x

Do not mistake the -1 in f -1 for an exponent. ONE-TO-ONE FUNCTIONS Caution Do not mistake the -1 in f -1 for an exponent. Thus, f -1(x) does not mean . However, the reciprocal could be written as [f(x)]-1.

find f -1(7), f -1(5), and f -1(-10). ONE-TO-ONE FUNCTIONS Example 3 If f(1) = 5, f(3) = 7, and f(8) = -10, find f -1(7), f -1(5), and f -1(-10). From the definition of f -1, we have: f -1(7) = 3 because f(3) = 7 f -1(5) = 1 because f(1) = 5 f -1(-10) = 8 because f(8) = -10

This diagram makes it clear how f -1 ONE-TO-ONE FUNCTIONS Example 3 This diagram makes it clear how f -1 reverses the effect of f in this case.

The letter x is traditionally used as the independent variable. ONE-TO-ONE FUNCTIONS Definition 3 The letter x is traditionally used as the independent variable. So, when we concentrate on f -1 rather than on f, we usually reverse the roles of x and y in Definition 2 and write:

By substituting for y in Definition 2 and CANCELLATION EQUATIONS Definition 4 By substituting for y in Definition 2 and substituting for x in Definition 3, we get the following cancellation equations: f -1(f(x)) = x for every x in A f(f -1(x)) = x for every x in B

The first cancellation equation states that, if we start with x, apply f, and then apply f -1, we arrive back at x, where we started. Thus, f -1 undoes what f does.

The second equation states that f undoes what f -1 does. CANCELLATION EQUATION 2 The second equation states that f undoes what f -1 does.

For example, if f(x) = x3, then f -1(x) = x1/3. CANCELLATION EQUATIONS For example, if f(x) = x3, then f -1(x) = x1/3. So, the cancellation equations become: f -1(f(x)) = (x3)1/3 = x f(f -1(x)) = (x1/3)3 = x These equations simply states that the cube function and the cube root function cancel each other when applied in succession.

Now, let’s see how to compute inverse functions. If we have a function y = f(x) and are able to solve this equation for x in terms of y, then, according to Definition 2, we must have x = f -1(y). If we want to call the independent variable x, we then interchange x and y and arrive at the equation y = f -1(x).

Now, let’s see how to find the inverse INVERSE FUNCTIONS Method 5 Now, let’s see how to find the inverse function of a one-to-one function f. Write y = f(x). Solve this equation for x in terms of y (if possible). To express f -1 as a function of x, interchange x and y. The resulting equation is y = f -1(x).

Find the inverse function of f(x) = x3 + 2. INVERSE FUNCTIONS Example 4 Find the inverse function of f(x) = x3 + 2. By Definition 5, we first write: y = x3 + 2. Then, we solve this equation for x : Finally, we interchange x and y : So, the inverse function is:

The principle of interchanging x and y INVERSE FUNCTIONS The principle of interchanging x and y to find the inverse function also gives us the method for obtaining the graph of f -1 from the graph of f. As f(a) = b if and only if f -1(b) = a, the point (a, b) is on the graph of f if and only if the point (b, a) is on the graph of f -1.

However, we get the point (b, a) from INVERSE FUNCTIONS However, we get the point (b, a) from (a, b) by reflecting about the line y = x.

Thus, the graph of f -1 is obtained by INVERSE FUNCTIONS Thus, the graph of f -1 is obtained by reflecting the graph of f about the line y = x.

and its inverse function using the same coordinate axes. INVERSE FUNCTIONS Example 5 Sketch the graphs of and its inverse function using the same coordinate axes.

First, we sketch the curve (the top half of the parabola y2 = -1 -x, INVERSE FUNCTIONS Example 5 First, we sketch the curve (the top half of the parabola y2 = -1 -x, or x = -y2 - 1). Then, we reflect about the line y = x to get the graph of f -1.

As a check on our graph, notice that the INVERSE FUNCTIONS Example 5 As a check on our graph, notice that the expression for f -1 is f -1(x) = - x2 - 1, x ≥ 0. So, the graph of f -1 is the right half of the parabola y = - x2 - 1. This seems reasonable from the figure.

CALCULUS OF INVERSE FUNCTIONS Now, let’s look at inverse functions from the point of view of calculus.

Suppose that f is both one-to-one and continuous. CALCULUS OF INVERSE FUNCTIONS Suppose that f is both one-to-one and continuous. We think of a continuous function as one whose graph has no break in it. It consists of just one piece.

So, the graph of f -1 has no break in it either. CALCULUS OF INVERSE FUNCTIONS The graph of f -1 is obtained from the graph of f by reflecting about the line y = x. So, the graph of f -1 has no break in it either. Hence we might expect that f -1 is also a continuous function. © Thomson Higher Education

This geometrical argument does not prove the following theorem. CALCULUS OF INVERSE FUNCTIONS This geometrical argument does not prove the following theorem. However, at least, it makes the theorem plausible. A proof can be found in Appendix F.

CALCULUS OF INV. FUNCTIONS Theorem 6 If f is a one-to-one continuous function defined on an interval, then its inverse function f -1 is also continuous.

Now, suppose that f is a one-to-one differentiable function. CALCULUS OF INV. FUNCTIONS Now, suppose that f is a one-to-one differentiable function. Geometrically, we can think of a differentiable function as one whose graph has no corner or kink in it. We get the graph of f -1 by reflecting the graph of f about the line y = x. So, the graph of f -1 has no corner or kink in it either.

CALCULUS OF INV. FUNCTIONS Therefore, we expect that f -1 is also differentiable—except where its tangents are vertical. In fact, we can predict the value of the derivative of f -1 at a given point by a geometric argument.

If f(b) = a, then Likewise, f’(b) = tan  f -1(a) = b. CALCULUS OF INV. FUNCTIONS If f(b) = a, then f -1(a) = b. (f -1)’(a) is the slope of the tangent to the graph of f -1 at (a, b), which is tan . Likewise, f’(b) = tan  © Thomson Higher Education

From the figure, we see that  +  = π/2 CALCULUS OF INV. FUNCTIONS From the figure, we see that  +  = π/2 © Thomson Higher Education

CALCULUS OF INV. FUNCTIONS Hence, That is,

CALCULUS OF INV. FUNCTIONS Theorem 7 If f is a one-to-one differentiable function with inverse function f -1 and f’(f -1(a)) ≠ 0, then the inverse function is differentiable at a and

Write the definition of derivative as in Equation 5 in Section 3.1: CALCULUS OF INV. FUNCTIONS Theorem 7—Proof Write the definition of derivative as in Equation 5 in Section 3.1: If f(b) = a, then f -1(a) = b. Also, if we let y = f -1(x), then f(y) = x.

Since f is differentiable, it is continuous. CALCULUS OF INV. FUNCTIONS Theorem 7—Proof Since f is differentiable, it is continuous. So f -1 is continuous by Theorem 6. Thus, if x → a, then f -1(x) → f -1(a), that is, y → b.

CALCULUS OF INV. FUNCTIONS Theorem 7—Proof Therefore,

NOTE 1 Equation 8 Replacing a by the general number x in the formula of Theorem 7, we get:

If we write y = f -1(x), then f(y) = x. NOTE 1 If we write y = f -1(x), then f(y) = x. So, Equation 8, when expressed in Leibniz notation, becomes:

NOTE 2 If it is known in advance that f -1 is differentiable, then its derivative can be computed more easily than in the proof of Theorem 7—by using implicit differentiation.

NOTE 2 If y = f -1(x), then f(y) = x. Differentiating f(y) = x implicitly with respect to x, remembering that y is a function of x, and using the Chain Rule, we get: Therefore,

CALCULUS OF INV. FUNCTIONS Example 6 The function y = x2, x  , is not one-to-one and, therefore, does not have an inverse function. Still, we can turn it into a one-to-one function by restricting its domain. © Thomson Higher Education

CALCULUS OF INV. FUNCTIONS Example 6 For instance, the function f(x) = x2, 0 ≤ x ≤ 2, is one-to-one (by the Horizontal Line Test) and has domain [0, 2] and range [0, 4]. Hence, it has an inverse function f -1 with domain [0, 4] and range [0, 2]. © Thomson Higher Education

CALCULUS OF INV. FUNCTIONS Example 6 Without computing a formula for (f -1)’, we can still calculate (f -1)’(1). Since f(1) = 1, we have f -1(1) = 1. Also, f’(x) = 2x. So, by Theorem 7, we have:

In this case, it is easy to find f -1 explicitly. CALCULUS OF INV. FUNCTIONS Example 6 In this case, it is easy to find f -1 explicitly. In fact, In general, we could use Method 5.

Then, So, This agrees with the preceding computation. CALCULUS OF INV. FUNCTIONS Example 6 Then, So, This agrees with the preceding computation.

The functions f and f -1 are graphed here. CALCULUS OF INV. FUNCTIONS Example 6 The functions f and f -1 are graphed here. © Thomson Higher Education

If f(x) = 2x + cos x, find (f -1)’(1) CALCULUS OF INV. FUNCTIONS Example 7 If f(x) = 2x + cos x, find (f -1)’(1) Notice that f is one-to-one because f ’(x) = 2 – sin x > 0 and so f is increasing.

To use Theorem 7, we need to know f -1(1). CALCULUS OF INV. FUNCTIONS Example 7 To use Theorem 7, we need to know f -1(1). We can find it by inspection: Hence,