Free Falling Objects: Acceleration Due to Gravity

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Presentation transcript:

Free Falling Objects: Acceleration Due to Gravity Kinematics Unit

Galileo discovered that objects fall to earth with a uniform, (constant), acceleration. This constant acceleration is called the acceleration due to gravity. This constant is written as g = 9.81 m/s2 or a = 9.81 m/s2.

YOU DO NOT USE ANY NEW ACCLERATION FORMULAE to solve these problems. For all the problems a = 9.81 m/s2. All of the previously mentioned formulae can be used because the object in question is accelerating uniformly.

RECALL:

Since acceleration is a vector, then the acceleration due to gravity must also be a vector, (have magnitude and direction). If the object is dropped or falling a = + 9.81 m/s2 . If the object is thrown upwards a = - 9.81 m/s2.

+ Example 1: An object falls to the ground in 3.0s . a. What is the object’s final velocity? b. How far does the object fall? +

Example 2: A stone is dropped from a cliff 400m high Example 2: A stone is dropped from a cliff 400m high. What is displacement of the stone after falling for 5.0 s?

Example 3: A ball is thrown vertically downwards at 30. 0m/s Example 3: A ball is thrown vertically downwards at 30.0m/s. Determine the instantaneous velocity of the ball at 4.00 s.

Example 4: A stone is dropped from rest into a gorge Example 4: A stone is dropped from rest into a gorge. Determine the distance that the stone falls during the third second of the fall.

Assignment: Read Text p. 54 – 62 Do p. 58 # 1-3 p.60 #1 Do Workbook p. 45 #25 – 33 (omit the question that requires you to use the CD that came with the book) NOTE: No class: Monday Sept. 28 (River Watch) Quiz on Accelerated Motion and Graphing: Wednesday, Sept. 30 Accelerated Motion Lab due Wednesday, Sept. 30