Calculus II SI Exam 1 review

Slides:



Advertisements
Similar presentations
Section Volumes by Slicing
Advertisements

Volumes by Slicing: Disks and Washers
- Volumes of a Solid The volumes of solid that can be cut into thin slices, where the volumes can be interpreted as a definite integral.
DO NOW: Find the volume of the solid generated when the
Volume By Slicing AP Calculus.
Disks, Washers, and Cross Sections Review
Section Volumes by Slicing
Applications of Integration
More on Volumes & Average Function Value. Average On the last test (2), the average of the test was: FYI - there were 35 who scored a 9 or 10, which means.
 A k = area of k th rectangle,  f(c k ) – g(c k ) = height,  x k = width. 6.1 Area between two curves.
7.1 Area Between 2 Curves Objective: To calculate the area between 2 curves. Type 1: The top to bottom curve does not change. a b f(x) g(x) *Vertical.
SECTION 7.3 Volume. VOLUMES OF AN OBJECT WITH A KNOWN CROSS-SECTION  Think of the formula for the volume of a prism: V = Bh.  The base is a cross-section.
7.3 Volumes Quick Review What you’ll learn about Volumes As an Integral Square Cross Sections Circular Cross Sections Cylindrical Shells Other Cross.
Finding Volumes.
Review: Volumes of Revolution. x y A 45 o wedge is cut from a cylinder of radius 3 as shown. Find the volume of the wedge. You could slice this wedge.
6.4 Arc Length. Length of a Curve in the Plane If y=f(x) s a continuous first derivative on [a,b], the length of the curve from a to b is.
Applications of the Definite Integral
Applications of Integration In this chapter we explore some of the applications of the definite integral by using it for 1.Computing the area between curves.
The Area Between Two Curves Lesson 6.1. When f(x) < 0 Consider taking the definite integral for the function shown below. The integral gives a ___________.
Chapter 7 AP Calculus BC. 7.1 Integral as Net Change Models a particle moving along the x- axis for t from 0 to 5. What is its initial velocity? When.
Chapter 7-Applications of the Integral Calculus, 2ed, by Blank & Krantz, Copyright 2011 by John Wiley & Sons, Inc, All Rights Reserved.
Let R be the region bounded by the curve y = e x/2, the y-axis and the line y = e. 1)Sketch the region R. Include points of intersection. 2) Find the.
Finding Volumes Chapter 6.2 February 22, In General: Vertical Cut:Horizontal Cut:
Volumes Lesson 6.2.
Section 6.4 Work. In physics the word “work” is used to describe the work a force has done on an object to move it some distance. Work done = Force ·
Volumes by Slicing. disk Find the Volume of revolution using the disk method washer Find the volume of revolution using the washer method shell Find the.
Volumes of Solids with Known Cross Sections
Calculus 6-R Unit 6 Applications of Integration Review Problems.
Section 7.3: Volume The Last One!!! Objective: Students will be able to… Find the volume of an object using one of the following methods: slicing, disk,
Chapter Six Overview Applications of the Definite Integral in Geometry, Science, and Engineering.
Copyright © Cengage Learning. All rights reserved.
The Disk Method (7.2) February 14th, 2017.
Lecture 1 – Volumes Area – the entire 2-D region was sliced into strips Before width(x) was introduced, only dealing with length f(x) a b Volume – same.
Volume: The Shell Method
Work and Fluid Pressure
Solids of Revolution Shell Method
Solids of Revolution Shell Method
Copyright © Cengage Learning. All rights reserved.
In this section, we will learn about: Using integration to find out
8-5 Applications from science
Finding Volumes.
The Shell Method Section 7.3.
Finding Volumes Chapter 6.2 February 22, 2007.
Finding Volumes Disk/Washer/Shell
Review of Area: Measuring a length.
Volumes – The Disk Method
Cross Sections Section 7.2.
Solids not generated by Revolution
Volume by Cross Sections
Finding Volumes Disk/Washer/Shell
Work Lesson 7.5.
Review: Area betweens two curves
Find the volume of the solid obtained by rotating about the x-axis the region under the curve {image} from x = 2 to x = 3. Select the correct answer. {image}
3. Volumes.
Warm up Find the area of surface formed by revolving the graph of f(x) = 6x3 on the interval [0, 4] about the x-axis.
Volume of Solids with Known Cross Sections
Applications Of The Definite Integral
7 Applications of Integration
Area & Volume Chapter 6.1 & 6.2 February 20, 2007.
8-3 Day 2 volumes.
Chapter 6 Cross Sectional Volume
6.1 Areas Between Curves To find the area:
Work and Fluid Pressure
Calculus 5.9: Volume of a Solid by Plane Slicing
Section Volumes by Slicing
Volume of Disks & Washers
AP problem back ch 7: skip # 7
6.3 – Volumes By Cylindrical Shells
Presentation transcript:

Calculus II SI Exam 1 review Si Leader: Rosalie Dubberke

Part I Volumes by shapes and revolutions

General Procedure 1) Graph any functions 2) Draw a 3D picture of object 3) Partition the graph (x = 1, x=2, x=k-1, x=k…) 4) Find the volume of one “slice” 5) Sum the volume of all of the slices 6) Send the partition to 0 7) Form the integral 8) Solve the integral if necissary

Problem 1 A solid lies between planes perpendicular to the x-axis at x = -1 and x = 1. The cross-sections perpendicular to the x-axis are circular disks whose diameters run from the parabola y = 𝑥 2 to the parabola y = 2- 𝑥 2 Solve for the volume of the solid

Problem 2 The base of the solid is the disk 𝑥 2 + 𝑦 2 =1 the cross-sections by planes perpendicular to the y-axis between y = -1 and y = 1 are isosceles right triangle with one leg in the disk.

Problem 3 Find the volume of the region in the first quadrant bound by 𝑦=(𝑥−1) (𝑥−3) 2 and the x-axis revolved around the y - axis

Problem 4 Find an equation for (but do not solve) the volume of the region in the first quadrant bound by 𝑦= (𝑥−1) (𝑥−3) 2 and the x-axis revolved around x = -7

Problem 5 Write an equation for (but do not solve) the volume of the area below 𝑦= 3 𝑥 from 0 < x < 8 using: Shell method Washer/disk method

Problem 6 Write an equation for the volume of the area between 𝑦=2 𝑥−1 and 𝑦=𝑥−1 revolved around the line x = 6 using: Shell method Washer/disk method Solve one

Part II Surface area and arc length

General Procedure for arc length 1) Use pythagorians theorem for the length of a line 2) Sum the lengths of each individual line 3) Use the definition of a derivative to substitute for ∆𝑦 4) Pull out the ∆𝑥 5) Change the summation to an integral 6) Solve if necissary

General Procedure for Surface area 1) Use what you know about arc length 2) Multiply the arc length by the radius (we are essentially finding and summing many small circumferences) 3) Change to an integral 4) Solve if necissary

Problem 7 Find the length of the curve 𝑦= 4 2 3 𝑥 3 2 from 0 < x < 1

Problem 8 Find the surface area of the equation 𝑦=2 𝑥 revolved around the x-axis from x = 1 to x = 2

Problem 9 Find the surface area of the equation x = 1 - y revolved around the y-axis from 0 to 1

Part III Work

General Procedure For spring/lifting problems: W = 𝐹 𝑥 𝑑𝑥 For water pump problems: 1) Draw a diagram 2) Partition 3) Find an equation for the work needed to lift one “slice” 4) Sum the work for all slices 5) Write the integral 6) Solve if necissary

Problem 10 A cable that weighs 2lbs/ft is attached to a bucket filled with coal that weighs 800 lbs. The bucket is initially at the bottom of a 500 ft mine shaft. Answer each of the following questions: Determine the amount of work required to lift the bucket to the midpoint of the shaft. Determine the amount of work required to lift the bucket from the midpoint of the shaft to the top. Determine the amount of work required to life the bucket all the way to the top of the shaft.

Problem 11 A cylindrical; reservoir diameter 4 ft and height 6 ft is half full of water weighing 10 𝑙𝑏 𝑓𝑡 3 . Find the work done in emptying the water over the top.

Problem 12 A cylindrical; reservoir diameter 4 ft and height 6 ft is half full of water weighing 10 𝑙𝑏 𝑓𝑡 3 . Write an equation for the work done in emptying the water 3 feet over the top.

Problem 13 A force of 1200 N compresses a spring from its natural length of 18 cm to a length of 16 cm. How much work is done in compressing it from 16 cm to 14 cm?

Problem 14 A leaky bucket weighing 5N is lifted 20 m into the air at a constant speed. The rope weighs 0.08 Nm-1. The bucket starts with 2 N of water and leaks at a constant rate. It finishes draining just as it reaches the top. How much work was done lifting the bucket, the water, and the rope?

Part IV Old Exam Questions

Problem 15

Problem 16