Take out an APPROVED calculator and formula sheet.

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AP Biology Math Review 2013 Take out an APPROVED calculator and fomula sheet. 2) Pick a grid sheet. You will solve each problem and grid in the answer.
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AP Biology Math Review 2013 Take out an APPROVED calculator and fomula sheet. 2) Pick a grid sheet. You will solve each problem and grid in the answer.
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AP Biology Math Review 2013 Take out an APPROVED calculator and fomula sheet. 2) Pick a grid sheet. You will solve each problem and grid in the answer.
AP Biology Math Review 2013 Take out an APPROVED calculator and formula sheet. 2) Pick a grid sheet. You will solve each problem and grid in the answer.
Presentation transcript:

Take out an APPROVED calculator and formula sheet. AP Biology Math Review 2016 Take out an APPROVED calculator and formula sheet.

Tips Allowed 3 minutes per question – aim for half that Use the formula sheet Don’t round until the end Grid LEFT to right Look at HOW the answer should be given “round to nearest…” .123 The 1 is in the tenths place The 2 is in the hundreds place The 3 is in the thousandths place

Ready for #1

Q1: Chi Square A heterozygous red eyed female was crossed with a red eyed male. The results are shown below. Red eyes are sex-linked dominant to white, determine the chi square value. Round to the nearest hundredth. Phenotype # flies observed Red Eyes 134 White Eyes 66

Chi Square Strategy Observed – actual data Expected – complete a punnet square to determine the expected # Plug in +

Chi-Square Expected Observed—134 red eyes, 66 white eyes XR Xr 6.83 + XR XR XR Xr XR XR Xr Y Y Y (134-150)2 /150 (66-50)2 /50 + 3:1 ratio 134+ 66=200 150 red 50 white 1.70666 + 5.12 6.83

Ready for #2

Q2: Surface Area and Volume What is the SA/V for this cell? Round your answer to the nearest hundredths.

Q2 SA= 4 r2 =4(3.14) 52 =314 Volume of a sphere= 4/3 r3 =4/3 (3.14)53 =523.33 SA/V=314/523.33 =.60

Ready for #3

Q3: Water Potential and Solution Potential Solute potential= –iCRT i = The number of particles the molecule will make in water; for NaCl this would be 2; for sucrose or glucose, this number is 1 C = Molar concentration (from your experimental data) R = Pressure constant = 0.0831 liter bar/mole K T = Temperature in degrees Kelvin = 273 + °C of solution Sample Problem The molar concentration of a sugar solution in an open beaker has been determined to be 0.3M. Calculate the solute potential at 27 degrees celsius. Round your answer to the nearest tenths.

Q3 Solute potential= –iCRT -i= 1 (sugar is 1, salt is 2) C= 0.3 R = Pressure constant = 0.0831 T= 27 +273=300K Solute concentration= -7.5

Ready for #4

Q4: Hardy Weinberg A census of birds nesting on a Galapagos Island revealed that 24 of them show a rare recessive condition that affected beak formation. The other 63 birds in this population show no beak defect. If this population is in HW equilibrium, what is the frequency of the dominant allele? Give your answer to the nearest hundredth

Hardy Weinberg Strategy Figure out what you are given Allele (p or q) or Genotypes (p2, 2pq, q2) Figure out what you are solving for Manipulate formulas to go from given to solving for Always dealing with decimals A census of birds nesting on a Galapagos Island revealed that 24 of them show a rare recessive condition that affected beak formation. The other 63 birds in this population show no beak defect. If this population is in HW equilibrium, what is the frequency of the dominant allele? Give your answer to the nearest hundredth

Q4:Looking for p—dominant allele Homozygous Recessive=q2=24/87= .2758 q2= .2758 q= .5252 p+q=1 p=.47

Ready for #5

Q5: Laws of Probability Calculate the probability of tossing three coins simultaneously and obtaining three heads. Express in fraction form.

½ X ½ X ½ =1/8 Q5: Probability of a heads is ½ Probability of heads AND a heads AND a heads ½ X ½ X ½ =1/8

Ready for #6 Creating dilutions…

Q6: Dilution Joe has a 2 g/L solution. He dilutes it and creates 3 L of a 1 g/L solution. How much of the original solution did he dilute? Round to the nearest tenths.

We are looking for V1: CiVi = CfVf 2Vi = 1(3) Vi= 1.5

Ready for #7

Q7: Gibbs Free Energy N2 + 3H2 -> 2NH3 Determine the ∆G in kJ/mol for the following reaction: N2 + 3H2 -> 2NH3 At 293°K the Δ in enthalpy is -9.2x104 J/mol and the Δ in entropy is -199 J/K.

Q7: Answer Δ G = Δ H - T ( Δ S) = (-92000J/mol ) – (293K)(-199 J/K) = -33 THIS WILL NOT BE ON THE MIDTERM  YOU’RE WELCOME