1) How many moles of water are in an 82.3g sample?

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Presentation transcript:

1) How many moles of water are in an 82.3g sample?

82.3g water 1mole water x = 1 18.02g water 4.57 mole water

2) How many grams of oxygen are in a sample of gas that has a volume of 8.61L at STP?

8.61L O2 1 mole O2 32g O2 x x = 1 22.4L O2 1 mole O2 12.3g O2

3) How many liters of gas are contained in a sample that is made up of 42.48g of sulfur trioxide at STP?

42.48g SO3 1 mole SO3 22.4L SO3 x x = 1 80.06g SO3 1 mole SO3 11.89L SO3

4) How many formula units are present in a Iron (III) oxide sample that contains 1.68x1025 atoms

1.68x1025 atoms 1 F.U. Fe2O3 x = 1 5 atoms 3.36x1024 F.U. Fe2O3

5) How many atoms are present in a sample containing 1 5) How many atoms are present in a sample containing 1.96g of ammonium phosphate?

x = x x 1 20 atoms 1.58x1023 atoms 1.96g (NH4)3PO4 1 mole (NH4)3PO4 6.02x1023F.U. (NH4)3PO4 x x 1 149.12g (NH4)3PO4 1 mole (NH4)3PO4 20 atoms x = 1.58x1023 atoms 1 F.U. (NH4)3PO4

6) How many liters of gas at STP are contained in a sample of chlorine that contains 3.2x1011 atoms?

x = x x 1 6.0x10-12L Cl2 22.4L Cl2 1 mole Cl2 3.2x1011 atoms Cl 1 molecule of Cl2 1 mole Cl2 x x 1 2 atoms Cl 6.02x1023 molecules Cl2 22.4L Cl2 x = 6.0x10-12L Cl2 1 mole Cl2

7) How many atoms of oxygen are contained in a 53 7) How many atoms of oxygen are contained in a 53.82g sample of aluminum sulfate?

x = x x 1 12 atoms O 1.136x1024 atoms O 53.82g Al2(SO4)3 1 mole Al2(SO4)3 6.02x1023F.U. Al2(SO4)3 x x 1 342.14g Al2(SO4)3 1 mole Al2(SO4)3 12 atoms O x = 1.136x1024 atoms O 1 F.U. Al2(SO4)3

8) How many formula units of hydrochloric acid are present in a 75 8) How many formula units of hydrochloric acid are present in a 75.0mL solution if it has a concentration of 0.258M?

x = x x 1 0.258moles HCl 1.16x1022 F.U. HCl 75.0mL HCl Soln. 1 mole HCl

9) What is the length of a copper wire (cylinder) that has a diameter of 0.0200cm and contains 4.91x1022 copper atoms? Vcyl=πr2h, Dcu = 8.96g/mL

x = x x 1 h = 1840cm 1 mole Cu 0.5785 cm3 Vcyl=πr2h 4.91x1022atoms Cu x 1 mole Cu x 63.55g Cu 1 1 mole Cu 6.02x1023atoms Cu 1 cm3Cu x = 0.5785 cm3 8.96g Cu Vcyl=πr2h 0.5785cm3 = 3.14(0.0100cm)2h h = 1840cm

Answers 1) 4.57 mole water 2) 12.3g O2 3) 11.89L SO3 4) 3.36x1024 F.U. Fe2O3 5) 1.58x1023 atoms 6) 6.0x10-12L Cl2 7) 1.136x1024 atoms O 8) 1.16x1022 F.U. HCl 9) 1840cm