REDOX PRACTICE MONDAY 4/07/08

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Presentation transcript:

REDOX PRACTICE MONDAY 4/07/08 Balance the redox reaction given C0 C+4 and Fe+3  Fe0 react, answer the following: a) Balance both half reactions. What species is reduced. What species is oxidized How many moles of electrons are transferred in the oxidation? C0  C+4 + + Fe+3  Fe0 4e- Add electrons to most + side to balance 3e- Balance the electrons by finding the LCD of 4 and 3 which is 12, THEN multiply each reaction by the factor that gives 12 electrons. C0  C+4 + 4e- 3e- + Fe+3  Fe0 Balance the electrons by finding the LCD of 4 and 3 which is 12, THEN multiply each reaction by the factor that gives 12 electrons. 3[C0  C+4 + 4e- ] 4[3e- + Fe+3  Fe0] 12 mol of electrons transferred 3C0  3C+4 + 12e- 12e- + 4Fe+3  4Fe0 4Fe+3 + 3C0  3C+4 + 4Fe0 C0 IS OXIDIZED AND LOSES ELECTRONS Fe+3 IS REDUCED AND GAINS ELECTRONS