Discrete Mathematics and its Applications

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Discrete Mathematics and its Applications 11/13/2018 University of Florida Dept. of Computer & Information Science & Engineering COT 3100 Applications of Discrete Structures Dr. Michael P. Frank Slides for a Course Based on the Text Discrete Mathematics & Its Applications (5th Edition) by Kenneth H. Rosen A word about organization: Since different courses have different lengths of lecture periods, and different instructors go at different paces, rather than dividing the material up into fixed-length lectures, we will divide it up into “modules” which correspond to major topic areas and will generally take 1-3 lectures to cover. Within modules, we have smaller “topics”. Within topics are individual slides. 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Module #2: Basic Proof Methods Discrete Mathematics and its Applications 11/13/2018 Module #2: Basic Proof Methods Rosen 5th ed., §1.5 48 slides, ~3 lectures 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Nature & Importance of Proofs Discrete Mathematics and its Applications 11/13/2018 Nature & Importance of Proofs In mathematics, a proof is: a correct (well-reasoned, logically valid) and complete (clear, detailed) argument that rigorously & undeniably establishes the truth of a mathematical statement. Why must the argument be correct & complete? Correctness prevents us from fooling ourselves. Completeness allows anyone to verify the result. In this course (& throughout mathematics), a very high standard for correctness and completeness of proofs is demanded!! 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Discrete Mathematics and its Applications 11/13/2018 Overview of §1.5 Methods of mathematical argument (i.e., proof methods) can be formalized in terms of rules of logical inference. Mathematical proofs can themselves be represented formally as discrete structures. We will review both correct & fallacious inference rules, & several proof methods. 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Applications of Proofs Discrete Mathematics and its Applications 11/13/2018 Applications of Proofs An exercise in clear communication of logical arguments in any area of study. The fundamental activity of mathematics is the discovery and elucidation, through proofs, of interesting new theorems. Theorem-proving has applications in program verification, computer security, automated reasoning systems, etc. Proving a theorem allows us to rely upon on its correctness even in the most critical scenarios. Of course, when one is proving things about a mathematical model of the real world, one must always recognize the risk that the postulates that are supposed to connect the premises of the model with the real world may fail to be true. 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Discrete Mathematics and its Applications 11/13/2018 Proof Terminology Theorem A statement that has been proven to be true. Axioms, postulates, hypotheses, premises Assumptions (often unproven) defining the structures about which we are reasoning. Rules of inference Patterns of logically valid deductions from hypotheses to conclusions. Axioms are statements that are taken as true that serve to define the very structures we are reasoning about. Postulates are assumptions stating that some characteristic of an applied mathematical model corresponds to some truth about the real world or some situation being modeled. Hypotheses are statements that are temporarily adopted as being true, for purposes of proving the consequences they would have if they were true, leading to possible falsification of the hypothesis if a predicted consequence turns out to be false. Usually a hypothesis is offered as a way of explaining a known consequence. Hypotheses are not necessarily believed or disbelieved except in the context of the scenario being explored. Premises are statements that the reasoner adopts as true so he can see what the consequences would be. Like hypotheses, they may or may not be believed. Conjectures are statements that are proposed to be logical consequences of other statements, and that may be strongly believed to be such, but that have not yet been proven. Lemmas are relatively uninteresting statements that are proved on the way to proving an actual theorem of interest. 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

More Proof Terminology Discrete Mathematics and its Applications 11/13/2018 More Proof Terminology Lemma - A minor theorem used as a stepping-stone to proving a major theorem. Corollary - A minor theorem proved as an easy consequence of a major theorem. Conjecture - A statement whose truth value has not been proven. (A conjecture may be widely believed to be true, regardless.) Theory – The set of all theorems that can be proven from a given set of axioms. 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Graphical Visualization A Particular Theory … A proof The Axioms of the Theory Various Theorems 11/13/2018 (c)2001-2003, Michael P. Frank

Inference Rules - General Form Discrete Mathematics and its Applications 11/13/2018 Inference Rules - General Form An Inference Rule is A pattern establishing that if we know that a set of antecedent statements of certain forms are all true, then we can validly deduce that a certain related consequent statement is true. antecedent 1 antecedent 2 …  consequent “” means “therefore” 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Inference Rules & Implications Each valid logical inference rule corresponds to an implication that is a tautology. antecedent 1 Inference rule antecedent 2 …  consequent Corresponding tautology: ((ante. 1)  (ante. 2)  …)  consequent 11/13/2018 (c)2001-2003, Michael P. Frank

Some Inference Rules p Rule of Addition  pq pq Rule of Simplification  p p Rule of Conjunction q  pq 11/13/2018 (c)2001-2003, Michael P. Frank

“the mode of affirming” Modus Ponens & Tollens “the mode of affirming” p Rule of modus ponens pq (a.k.a. law of detachment) q q pq Rule of modus tollens p “the mode of denying” 11/13/2018 (c)2001-2003, Michael P. Frank

Syllogism Inference Rules Discrete Mathematics and its Applications 11/13/2018 Syllogism Inference Rules pq Rule of hypothetical qr syllogism pr p  q Rule of disjunctive p syllogism  q Many valid inference rules were first described by Aristotle. He called these patterns of argument “syllogisms.” Aristotle (ca. 384-322 B.C.) 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Formal Proofs A formal proof of a conclusion C, given premises p1, p2,…,pn consists of a sequence of steps, each of which applies some inference rule to premises or previously-proven statements (antecedents) to yield a new true statement (the consequent). A proof demonstrates that if the premises are true, then the conclusion is true. 11/13/2018 (c)2001-2003, Michael P. Frank

Formal Proof Example Suppose we have the following premises: “It is not sunny and it is cold.” “We will swim only if it is sunny.” “If we do not swim, then we will canoe.” “If we canoe, then we will be home early.” Given these premises, prove the theorem “We will be home early” using inference rules. 11/13/2018 (c)2001-2003, Michael P. Frank

Proof Example cont. Let us adopt the following abbreviations: sunny = “It is sunny”; cold = “It is cold”; swim = “We will swim”; canoe = “We will canoe”; early = “We will be home early”. Then, the premises can be written as: (1) sunny  cold (2) swim  sunny (3) swim  canoe (4) canoe  early 11/13/2018 (c)2001-2003, Michael P. Frank

Proof Example cont. Step Proved by 1. sunny  cold Premise #1. 2. sunny Simplification of 1. 3. swimsunny Premise #2. 4. swim Modus tollens on 2,3. 5. swimcanoe Premise #3. 6. canoe Modus ponens on 4,5. 7. canoeearly Premise #4. 8. early Modus ponens on 6,7. 11/13/2018 (c)2001-2003, Michael P. Frank

Inference Rules for Quantifiers x P(x) P(o) (substitute any specific object o) P(g) (for g a general element of u.d.) x P(x) x P(x) P(c) (substitute a new constant c) P(o) (substitute any extant object o) x P(x) Universal instantiation Universal generalization Existential instantiation Existential generalization 11/13/2018 (c)2001-2003, Michael P. Frank

Discrete Mathematics and its Applications 11/13/2018 Common Fallacies A fallacy is an inference rule or other proof method that is not logically valid. A fallacy may yield a false conclusion! Fallacy of affirming the conclusion: “pq is true, and q is true, so p must be true.” (No, because FT is true.) Fallacy of denying the hypothesis: “pq is true, and p is false, so q must be false.” (No, again because FT is true.) It’s easy for each fallacy to give a counter-example showing why it is not valid. 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Discrete Mathematics and its Applications 11/13/2018 Circular Reasoning The fallacy of (explicitly or implicitly) assuming the very statement you are trying to prove in the course of its proof. Example: Prove that an integer n is even, if n2 is even. Attempted proof: “Assume n2 is even. Then n2=2k for some integer k. Dividing both sides by n gives n = (2k)/n = 2(k/n). So there is an integer j (namely k/n) such that n=2j. Therefore n is even.” Circular reasoning is used in this proof. Where? The given statement is implicitly universal: FORALL integers n, n is even if n-squared is even. Note that although the statement we are trying to prove is true, our proof of it is invalid. It does not give a clear, valid path to the conclusion. Begs the question: How do you show that j=k/n=n/2 is an integer, without first assuming that n is even? 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

A Correct Proof We know that n must be either odd or even. If n were odd, then n2 would be odd, since an odd number times an odd number is always an odd number. Since n2 is even, it is not odd, since no even number is also an odd number. Thus, by modus tollens, n is not odd either. Thus, by disjunctive syllogism, n must be even. ■ This proof is correct, but not quite complete, since we used several lemmas without proving them. Can you identify what they are? 11/13/2018 (c)2001-2003, Michael P. Frank

Discrete Mathematics and its Applications 11/13/2018 A More Verbose Version Uses some number theory we haven’t defined yet. Suppose n2 is even 2|n2  n2 mod 2 = 0. Of course n mod 2 is either 0 or 1. If it’s 1, then n1 (mod 2), so n21 (mod 2), using the theorem that if ab (mod m) and cd (mod m) then acbd (mod m), with a=c=n and b=d=1. Now n21 (mod 2) implies that n2 mod 2 = 1. So by the hypothetical syllogism rule, (n mod 2 = 1) implies (n2 mod 2 = 1). Since we know n2 mod 2 = 0  1, by modus tollens we know that n mod 2  1. So by disjunctive syllogism we have that n mod 2 = 0 2|n  n is even. This is a relatively involved example and it should perhaps be saved until after some easier ones have already been done. We also need number theory first for this example. The vertical bar “|” means “divides (evenly).” mod refers to the remainder of a division. Later in the class we will encounter the theorem mentioned (first red-highlighted statement). The triple horizontal lines mean between two numbers means those numbers are “congruent” under the given modulus, that is, they give the same remainder when divided by the modulus. 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Proof Methods for Implications For proving implications pq, we have: Direct proof: Assume p is true, and prove q. Indirect proof: Assume q, and prove p. Vacuous proof: Prove p by itself. Trivial proof: Prove q by itself. Proof by cases: Show p(a  b), and (aq) and (bq). 11/13/2018 (c)2001-2003, Michael P. Frank

Discrete Mathematics and its Applications 11/13/2018 Direct Proof Example Definition: An integer n is called odd iff n=2k+1 for some integer k; n is even iff n=2k for some k. Theorem: Every integer is either odd or even. This can be proven from even simpler axioms. Theorem: (For all numbers n) If n is an odd integer, then n2 is an odd integer. Proof: If n is odd, then n = 2k+1 for some integer k. Thus, n2 = (2k+1)2 = 4k2 + 4k + 1 = 2(2k2 + 2k) + 1. Therefore n2 is of the form 2j + 1 (with j the integer 2k2 + 2k), thus n2 is odd. □ The statement that every integer is either odd or even can actually be proven from simpler axioms, the Peano axioms of arithmetic. However, for 11/13/2018 (c)2001-2003, Michael P. Frank (c)2001-2002, Michael P. Frank

Indirect Proof Example Theorem: (For all integers n) If 3n+2 is odd, then n is odd. Proof: Suppose that the conclusion is false, i.e., that n is even. Then n=2k for some integer k. Then 3n+2 = 3(2k)+2 = 6k+2 = 2(3k+1). Thus 3n+2 is even, because it equals 2j for integer j = 3k+1. So 3n+2 is not odd. We have shown that ¬(n is odd)→¬(3n+2 is odd), thus its contra-positive (3n+2 is odd) → (n is odd) is also true. □ 11/13/2018 (c)2001-2003, Michael P. Frank

Vacuous Proof Example Theorem: (For all n) If n is both odd and even, then n2 = n + n. Proof: The statement “n is both odd and even” is necessarily false, since no number can be both odd and even. So, the theorem is vacuously true. □ 11/13/2018 (c)2001-2003, Michael P. Frank

Trivial Proof Example Theorem: (For integers n) If n is the sum of two prime numbers, then either n is odd or n is even. Proof: Any integer n is either odd or even. So the conclusion of the implication is true regardless of the truth of the antecedent. Thus the implication is true trivially. □ 11/13/2018 (c)2001-2003, Michael P. Frank

Proof by Contradiction A method for proving p. Assume p, and prove both q and q for some proposition q. (Can be anything!) Thus p (q  q) (q  q) is a trivial contradiction, equal to F Thus pF, which is only true if p=F Thus p is true. 11/13/2018 (c)2001-2003, Michael P. Frank

Proof by Contradiction Example Theorem: is irrational. Proof: Assume 21/2 were rational. This means there are integers i,j with no common divisors such that 21/2 = i/j. Squaring both sides, 2 = i2/j2, so 2j2 = i2. So i2 is even; thus i is even. Let i=2k. So 2j2 = (2k)2 = 4k2. Dividing both sides by 2, j2 = 2k2. Thus j2 is even, so j is even. But then i and j have a common divisor, namely 2, so we have a contradiction. □ 11/13/2018 (c)2001-2003, Michael P. Frank

Review: Proof Methods So Far Direct, indirect, vacuous, and trivial proofs of statements of the form pq. Proof by contradiction of any statements. Next: Constructive and nonconstructive existence proofs. 11/13/2018 (c)2001-2003, Michael P. Frank