Maria’s Restaurant Chapter 3 Section 12

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Presentation transcript:

Maria’s Restaurant Chapter 3 Section 12

Maria’s Duct Layout Sketch

Zone 1 Fittings Supply Take Off

Zone 1 Fittings 4 90s

Zone 1 Fittings 5 Wye Fittings

6 Supply Diffusers & Boxes

Zone 1 Fittings Return Take Off

Zone 1 Fittings Return Filter & Grille

Zone 2 Fittings Supply Take Off

Zone 2 Fittings Supply 90

Zone 2 Fittings Supply 5 Wyes

6 Supply Diffusers & Boxes

Manual Q Commercial Low Pressure, Low Velocity Duct System Design

Duct Pressure Drop Calculation (Typical 90) Coefficient C for 90O Duct (Bottom Row) Height ÷ Width (Top Row) 0.25 0.50 0.75 1.0 1.5 2.0 3.0 4.0 5.0 6.0 8.0 1.3 1.2 1.1 0.98 0.92 0.89 0.85 0.83 90O Rectangular Elbow CFM = 2,400 H = 24 W = 27 H ÷ W = .8888 CFM ˃ 500 So, N = 1 So, C = 1.2 Velocity Pressure = (Velocity ÷ 4005 × ACF)2 Velocity Pressure = (600 ÷ 4005 × 1)2 = 0.0225 Reynolds Number Correction (N) CFM N 50 to 200 1.25 200 to 350 1.15 350 to 500 1.05 Above 500 1.00 Adjusted loss Coefficient = C × N Loss Item Pt = C × Pv H 90O W Pt = 1.2 × 0.0225 = 0.027

Duct Pressure Drop Calculation (Smooth Radius 3 Vane 90) Velocity Pressure = (600 ÷ 4005 × 1)2 = 0.0225 Loss Item Pt = C × Pv Pt = 0.01 × 0.0225 = 0.000225

What Does The C Value Difference Mean? The Pressure Loss is the Coefficient value C multiplied by the velocity pressure (VP) inside of the duct. Use a VP of 0.359 as an example, to get a total pressure drop across the 90 fitting as the air flows through it. Thus, for the Smooth radius 3 vane 90 the pressure drop would be: 0.01 × 0.359 = 0.00359

Pressure Drop Value for Standard 90? Thus, for the standard square 90 with a C value of 1.2, the pressure drop across the fitting would be: 1.2 × 0.359 = 0.43

Total Pressure Drop Question 1 Use a VP of 0.14536 to get a total pressure drop across the standard square 90 fitting that has a C value of 1.15 as the air flows through it. 1.15 × 0.14536 = 0.167164

Total Pressure Drop Question 2 Use a VP of 0.011362 to get a total pressure drop across the standard square 90 fitting that has a C value of 1.15 as the air flows through it. 1.15 × 0.011362 = 0.0130663

Total Pressure Drop Question 3 Use a VP of 0.359 to get a total pressure drop across the 90 fitting as the air flows through it for the standard square 90 with a C value of 1.15. For the Standard Square 90 the pressure drop would be: 1.15 × 0.359 = 0.41285 Note: 0.41285 is called the loss item in Manual Q. It is added to the other loss items to get a total loss for the whole duct run/system

Question 4 loss Item Total? Using the loss item totals from Figure 23 on page 52 values for the two shown 90O Ls, find the total loss difference between the two Ls, and which is the more efficient L? 0.0748 – 0.00539 = 0.0694 difference in pressure loss for the two fittings. The smooth radius 3 vain Elbow is by “far and away” the more efficient choice for the duct system.

Pressure Drop Difference Means What ? Zone 2 duct design pressure loss totals

Pressure Drop Difference Means What ? VP = (518 ÷ 4,005)2 = 0.0167 0.01 × 0.0167 = 0.000167 or 0.0002 a pressure loss item value of 0.0002 The Zone 2 total pressure loss is 0.503

What Happens If Our Previous Regular 90 Is Put In ? VP = (518 ÷ 4,005)2 = 0.0167 1.2 × 0.0167 = 0.02004 0.02004 – 0.0002 = 0.01984 + 0.503 = 0.523

How About Doing The Same 90 Change For Zone 1’s 4 90’s? Original Chart Values: Line 8 Loss Item = 0.00359 Line 15 Loss Item = 0.001264 Line 21 Loss Item = 0.000399 Line 25 Loss Item = 0.0000988 Total = 0.00539

How About Doing The Same 90 Change For Zone 1’s 4 90’s? Using the chart’s VP values for each line & our C of 1.20: Line 8 Loss Item = 0.027 Line 15 Loss Item = 0.022 Line 21 Loss Item = 0.015 Line 25 Loss Item = 0.0108 Total = 0.0748 Total 0.0748 - 0.00539 = 0.06941

For Zone 1 How Would Blower Motor Size be Changed Due To Changing A Systems Total Pressure Drop from 0.4 to 0.5 ESP? Looking at Table 12 on Page 46 of the Guide & Workbook: The motor size would increase. For example at 1,750 CFM system with an ESP of 0.4 would require a motor with approximately 0.39 Bhp and at 0.50 it would be 0.57 Bhp

Field Notes Whenever a duct design is done it is important to make sure the fittings were installed as designed. Often, when a duct system is too small the problem can be resolved by replacing a few standard duct fittings with some higher efficiency ones. It may be as easy as adding some turning vanes to the existing 90s. Redesigning and replacing an entire duct system is a lot more expensive than replacing four or five fittings.