Solutions and Molarity

Slides:



Advertisements
Similar presentations
Example 1 How many mL of M NaOH will completely neutralize 100 mL M H2SO4?
Advertisements

Solutions Calculations. Questions 1.What mass of NaOH is needed to make 350 mL of 0.45 mol/L NaOH solution? 2.What is the molarity if 25 g of KClO 3 is.
Balanced equations. HIGHER GRADE CHEMISTRY CALCULATIONS Calculation from a balanced equation A balanced equation shows the number of moles of each reactant.
Unit 10B Review Reg Chem When a solution sits out over a long period of time and water evaporates the concentration of the solution __________.
Solution types of stoichiometry problems are no harder than any other stoichiometry problem. You must use the concentration given (molarity) to convert.
Helpful Definitions Solutions: homogeneous mixture of two or more substances physically mixed together in a uniform way. Solute: substance being dissolved.
Concentration Units: Terms like “dilute” and “concentrated” are not specific. Percent by Mass: Mass % = mass of solute x 100 Total mass of solution Recall:
III. Molarity Topic 9 The Mole. A. Molarity Concentration of a solution. total combined volume substance being dissolved.
Moles in Solution A solution consists of a solvent with a solute dissolved in it The concentration of a solutions tells us how much solute is present in.
3.6 Solubility Solution: homogeneous mixture or mixture in which components are uniformly intermingled Solution: homogeneous mixture or mixture in which.
Mole Conversions Balanced Equations Stoich!!! Chemical Formulas
Solutions Concentration of Solutions. Objectives 1.Define molarity and calculate its value. 2.Define molality and calculate its value. 3.Apply the principles.
Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 12 Solutions 12.6 Solutions in Chemical Reactions When a BaCl 2 solution is added to.
Name ___________________________________________ Date ________________ Period __________ Part II: Moley-moley-moley One mole is _____________________________.
Molarity, pH, and Stoichiometry of Solutions Chapter 5 part 4.
Remembering: Molarity and Stoichiometry Because we know you brain is getting full!!!
Molarity and Stoichiometry. 1.Calculate the number of grams of sodium carbonate that are required to react fully with mL of M HCl. Na 2 CO.
Molarity moles of solute Liters of solution Unit for molarity mole mol LiterL = M.
Conversion Stoich. Moles to Quantity Moles of 1 substance are given and you are asked to find the mass, concentration or volume of another.
 Which of the following is an empirical formula? a. C 2 H 6 O 2 b. C 4 H 8 O 10 c. C 2 H 2 O 2 d. C 2 H 3 O 2.
Solution Stoichiometry
Moles to Grams Grams to Moles Liters to Moles Moles to Liters
Neutralization & Titration
Molarity Thornburg 2014.
Solutions & Chemical Equilibrium
Unit 13: Solutions & Equilibrium
9.4 Solution Concentrations and Reactions
Molarity (M): State the ratio between the number of moles of solute & the volume of solution (in liters). Molarity (M) =
Gas Stoichiometry.
First write a balanced equation.
Chapter 15 Acids and Bases
Unit 13 – Acid, Bases, & Salts
Chapter 8 Acids and Bases
What mass of CaF2 must be added to 1,000 L of water
Chapter 9 Stoichiometry part I
Unit 13: Solutions & Equilibrium
Molarity and Stoichiometry
Generic Stoichiometry
Section 2: Concentration
The Mole Molar Conversions.
Molarity (m).
Titrations!.
ICE Challenge.
Acid/Base pH and pOH Solubility Molarity Neutral- ization
Solutions and Molarity
Molarity & Dilution.
Ch. 3 & 7 – The Mole II. Molarity (p ) C. Johannesson.
Solution Concentration
Review Limiting Reactants
Generic Stoichiometry
Acid/Base pH and pOH Solubility Molarity Neutral- ization
Lesson 3 Percentage Yield and Energy.
REVIEW 12/11, MOLES For the combustion reaction
Solutions.
Chemistry – Apr 25, 2018 Get out Limiting Reactant Worksheet for HMK check Do Now – Consider the reaction NH3 + O2  NO + H2O (balance first!!) If 3.25.
II. Molarity.
First write a balanced equation.
First write a balanced equation.
Chapter 3.4 Acids and Bases
Solution Concentration: Molarity
Chemistry – Apr 24, 2018 Get out Limiting Reactant Worksheet for HMK check Do Now – Consider the reaction NH3 + O2  NO + H2O (balance first!!) If 3.25.
What mass of CaF2 must be added to 1,000 L of water
ICE Challenge.
Experiment No. 2 Preparation and standardization of approximately 0.1N sodium hydroxide (NaOH) by using standardized hydrochloric acid (HCl)
Solution Concentration
Solutions.
Chapter 9 Acids and Bases
Concentration of Solutions :
Molarity (M): State the ratio between the number of moles of solute & the volume of solution (in liters). Molarity (M) =
The Mole Molar Conversions.
Presentation transcript:

Solutions and Molarity

1. 13. 8 L of CO2 @ STP is dissolved in 250. 0 mL of water 1. 13.8 L of CO2 @ STP is dissolved in 250.0 mL of water. What is the molarity of the resulting solution? 13.8 L CO2 x 1 mol CO2 Molarity 22.4 L = 0.250 L = 2.46 M

If a 1. 89 M solution is made by dissolving chlorine gas in 600 If a 1.89 M solution is made by dissolving chlorine gas in 600.0 mL of water, what volume of Cl2 gas was dissolved? 0.600 L x 1.89 mol x 22.4 L = 25.4 L of Cl2 gas 1 mol 1 L

3. Calculate the molarity of a solution when 2 3. Calculate the molarity of a solution when 2.96 x 1024 FU’s of CaF2 are dissolved in 0.500 L of water? 2.96 x 1024 FU x 1 mol 6.02 x 1023 FU Molarity = = 9.83 M 0.500 L

4. How many molecules are dissolved in 1.00 L of water if the molarity of the H2SO4 solution is 0.2 M? 1.00 L x 0.2 mol x 6.02 x 1023 molecules = 1 x1023 molecules 1 mol 1L

5. Excess sodium hydroxide solution is added to 80. 0 mL of 0. 336 M 5. Excess sodium hydroxide solution is added to 80.0 mL of 0.336 M ZnCl2, calculate the mass of zinc hydroxide that will precipitate. 2 NaOH (aq) +ZnCl2(aq) → Zn(OH)2(s)+ 2NaCl (aq) 0.0800 L ? g 0.0800 L ZnCl2 x 0.336 mole x 1 mole Zn(OH)2 x 99.4 g 1 L 1 mole ZnCl2 1 mol = 2.67 g Zn(OH)2

6. Calculate the volume of 0. 100 M HCl solution that is required to 6. Calculate the volume of 0.100 M HCl solution that is required to completely neutralize 250.0 mL of 0.200 M Ba(OH)2 solution. 2HCl(aq) + Ba(OH)2 (aq) → BaCl2(aq) + 2H2O (l) ? L 0.2500 L 0.2500L Ba(OH)2 x 0.200 mole x 2 mole HCl x 1 L 1 L 1 mole Ba(OH)2 0.100 mol = 1.00 L