SA3202, Solution for Tutorial 1

Slides:



Advertisements
Similar presentations
Chapter Topics Confidence Interval Estimation for the Mean (s Known)
Advertisements

/3024/ SUN MON TUE WED THU FRI SAT JANUARY 2011 February 2011 SMTWTFS
The Practice of Statistics Third Edition Chapter (13.1) 14.1: Chi-square Test for Goodness of Fit Copyright © 2008 by W. H. Freeman & Company Daniel S.
Lesoon Statistics for Management Confidence Interval Estimation.
Hypothesis Tests with Critical Values
5 Day Forecast Mon Tues Wed Thu Fri.
Comparing Means from Two Samples
GANTT CHARTS Example Example Example Example text Tasks Example 1
Lecture 6 Comparing Proportions (II)
Mon – 2Tue – 3Wed – 4Thu - 5Fri - 6Sat - 7Sun - 8 Mon – 9Tue – 10Wed – 11Thu - 12Fri – 13Sat – 14Sun -15 Mon – 16Tue – 17Wed – 18Thu - 19Fri – 20Sat –
JANUARY FEBRUARY MARCH APRIL MAY JUNE JULY AUGUST SEPTEMBER
JANUARY FEBRUARY MARCH APRIL MAY JUNE JULY AUGUST SEPTEMBER
SA3202, Solution for Tutorial 2


Lecture 4. The Multinomial Distribution (II)
Sun. Mon. Tues. Wed. Thurs. Fri. Sat.
MON TUE WED THU
GANTT CHARTS Example Text Text Here Text Here Text Here Text Here
Lecture 5, Goodness of Fit Test
1   1.テキストの入れ替え テキストを自由に入れ替えることができます。 フチなし全面印刷がおすすめです。 印刷のポイント.
JANUARY FEBRUARY MARCH APRIL MAY JUNE JULY AUGUST SEPTEMBER
Logo Calendar – January 2012 TO DO LIST 01/04/2012 Example TO DO LIST
January MON TUE WED THU FRI SAT SUN
January MON TUE WED THU FRI SAT SUN
2017 Jan Sun Mon Tue Wed Thu Fri Sat

ANNUAL CALENDAR HOLIDAYS JANUARY FEBRUARY MARCH APRIL MAY JUNE
HOLIDAYS ANNUAL CALENDAR JANUARY FEBRUARY MARCH APRIL MAY JUNE
Free PPT Diagrams : ALLPPT.com
Free PPT Diagrams : ALLPPT.com
January Sun Mon Tue Wed Thu Fri Sat
January MON TUE WED THU FRI SAT SUN
January MON TUE WED THU FRI SAT SUN

Lecture 3. The Multinomial Distribution
Jan Sun Mon Tue Wed Thu Fri Sat
HOLIDAYS ANNUAL CALENDAR JANUARY FEBRUARY MARCH APRIL MAY JUNE
2008 Calendar.
S M T W F S M T W F
January MON TUE WED THU FRI SAT SUN
Sun Mon Tue Wed Thu Fri Sat
1 - January - Sun Mon The Wed Thu Fri Sat
2 0 X X s c h e d u l e 1 MON TUE WED THU JANUARY 20XX FRI SAT SUN MEMO.
January MON TUE WED THU FRI SAT SUN
JANUARY 1 Sun Mon Tue Wed Thu Fri Sat
Calendar
Calendar – 2010 (October, November & December)
Calendar.
January MON TUE WED THU FRI SAT SUN
JANUARY 1 Sun Mon Tue Wed Thu Fri Sat
Sun Mon Tue Wed Thu Fri Sat
SA3202, Solution for Tutorial 3
Name: ______________________________

1/○~1/○ weekly schedule MON TUE WED THU FRI SAT SUN MEMO
January MON TUE WED THU FRI SAT SUN
S M T W F S M T W F
2016 | 10 OCT SUN MON TUE WED THU FRI SAT
No. in group wearing glasses
Sun Mon Tue Wed Thu Fri Sat
JANUARY 1 Sun Mon Tue Wed Thu Fri Sat
WEB PAGES: Tables Welcome Back !.

1 January 2018 Sun Mon Tue Wed Thu Fri Sat
1 January MON TUE WED THU FRI SAT SUN MEMO 2 February MON TUE WED THU FRI SAT SUN.
2008 Calendar.
S M T W F S M T W F
S M T W F S M T W F
1 January MON TUE WED THU FRI SAT SUN MEMO 2 February MON TUE WED THU FRI SAT SUN.
Presentation transcript:

SA3202, Solution for Tutorial 1 Digit 1 2 3 4 5 6 7 8 9 0 Total Observed Freq. 7 11 7 12 11 6 15 9 13 9 100 Expected Freq. 10 10 10 10 10 10 10 10 10 10 100 (no free parameter) T=7.6, G=7.8825, df=10-1-0=9, 95% table=16.92, 90% table=14.68. Don’t reject H0. The digits follow the equi-probability model. Day Mon Tue Wed Thu Fri Sat Sun Total # of Suicide 1001 1035 982 1033 905 737 894 6587 Expected 941 941 941 941 941 941 941 6587 (Expected) 1013 1013 1013 1013 899 737 899 6587 T=71.95, G=78.38, df=7-1-0=6, 95% table=12.59, 90%table=10.6446 Reject H0. That is, the data do not follow the equi-probability model. H0: p1=p2=p3=p4, p5=p7 (2 free parameters: p1, p5 while p6=1-(4p1+2p5) is not free) T=2.031, G=2.039, df=7-1-2=4, 95% table=9.488, 90% table=7.779. Do not reject H0. 11/14/2018 SA3202, Solution for Tutorial 1

SA3202, Solution for Tutorial 1 3. T=87.43, df= 12-1=11, 95%table=19.675, 90%table=17.275. Reject H0. Assume a new model that the probability for a month is proportional to the days of the month: H0: p1=31/365, p2=28/365,…,p11=30/365,p12=31/365. (no free parameter) T=56.76, G=57.35, df=12-1=11. 95% table=19.675. Reject H0. It is clear that the equi-probability model doesn’t fit the data sets. For the Number of Boys Data, assume that the number of boys following a binomial distribution with probability ½: H0: p0=1/16, p1=4/16, p2=6/16, p3=4/16,p4=1/16 (no free parameter) T=14.26, df=5-1=4, 95% table=9.488, 90% table=7.779. Reject H0. Assume that the number of boys following a binomial distribution with unknown success probability theta. The theta is estimated as .5158. (1 free parameter) T=.627. Df=5-1-1=3, 90%table=6.25, 95%table=7.81. Do not eject H0. More boys were born. For the Political View Data, assume that the political views are symmetric: H0: p1=p7, p2=p6, p3=p5. ( 3 free parameters p1, p2,p3 while p4=1-2(p1+p2+p3) is not free) T=7.078, df=7-1-3=3, 90%table=6.25, 95%table=7.81. Do not eject H0 when alpha=5%. For the World Cup Data, we may assume a Poisson distribution for the # of Goals. Shall discuss more in future lectures and tutorials. 11/14/2018 SA3202, Solution for Tutorial 1