Practice Quiz 3 Hurley 4.3 - 4.7.

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Practice Quiz 3 Hurley 4.3 – 4.6.
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Practice Quiz 3 Hurley 4.3 - 4.7

For the quiz … I will provide you with a categorical proposition, like… No apples sold in Minnesota are mushy weapons I’ll ask you for its quality qualifier quantity quantifier copula distribution letter name terms

1 Consider: No non-A are B (T) Obversion Some non-A are B. (F) All A are non-B. (Und.) All non-A are non-B. (T) Some non-A are not B. (T) No B are non-A. (T)

2 Consider: All A are non-B. (F) Contraposition All A are non-B. (F) All non-B are A. (Und.) No non-A are B. (Und.) All B are non-A. (F) Some non-A are not B. (T)

3 Consider: Some A are not non-B. (T)  Some A are B. Contraposition (T) Contrary (F) Conversion (T) Obversion (T) Subcontrary (Und.)

4 Consider: Some non-A are B. (F)  Some B are non-A. Subcontrary (T) Conversion (Und.) Contraposition (Und.) Conversion (F) Contraposition (F)

5 Assume Aristotle (Traditional standpoint). Consider: Some A are non-B. (F)  Some A are not non-B. (F) Illicit, contrary Illicit, subalternation Subcontrary Illicit, subcontrary Contraposition

6 No S are P. (Aristotelian standpoint) After filling in the diagram … Area 2 is shaded, and there is a circled X in area 1. Areas 1 and 3 are shaded. Area 1 is shaded, and there is a circled X in area 2. There is an X in area 2. Area 1 is shaded, and there are no other marks.

7 All S are P. (Boolean standpoint) After filling in the diagram … Areas 1 and 3 are shaded. Area 2 is shaded, and there are no other marks. Area 1 is shaded, and there is a circled X in area 2. There is an X in area 2. Area 1 is shaded, and there are no other marks.

8 Shade area 2 and place an X in area 1. Which of the following would be valid inferences: shaded area 2. an X in area 3. an X in area 1. shaded 1. no X’s or shadings.

9 Shade area 1 and place an X in area 2. Which of the following would be valid inferences: shaded area 2. an X in area 3. shaded area 1, and X in area 2. shaded 1. no X’s or shadings.

10 Assume Aristotle (Traditional standpoint). Consider: No non-A are B. (T)  Some non-A are not B. (F) Illicit, subalternation Illicit, contradictory Contradictory Illicit, subcontrary Conversion

11 Assume Bool (Modern standpoint). Consider: No A are B. (T)  Some A are B. (F) Existential fallacy Illicit, contradictory Contradictory Illicit, subcontrary Conversion

12 Assume Bool (Modern standpoint). Consider: No A are B. (T)  All A are B. (F) Existential fallacy Illicit, contrary Contradictory Illicit, subcontrary Conversion

13 Assume Aristotle (Traditional standpoint) All square circles are happy shapes.  Some square circles are happy shapes. Existential fallacy Valid, contradictory Valid, subcontrary Invalid, subalternation Invalid, contrary