Solving Systems by Substitution

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Presentation transcript:

Solving Systems by Substitution Lesson 25 Linear Equations Solving Systems by Substitution

Warm-Up Solve each equation for x. 3x + 4x – 7 = 21 10 + 2x – 4x = 12

Solving Systems by Substitution Target: Determine the solution to a system of equations using the substitution method.

Vocabulary Substitution Method: A method for solving a system of equations.

Solving Systems of Linear Equations by Substitution Solve one of the linear equations for a variable (isolate x or y), if necessary. Replace the variable in the second equation with the expression that you solved for in Step 1. Solve for the variable in your new equation. Substitute your solution into the equation from Step 1 to find the value of the other variable. State your full answer as an ordered pair (x, y). Verify that the ordered pair is the solution by substituting the x- and y-values into both equations in the system or by graphing the system to confirm that the point of intersection matches your solution.

Example 1 y = –2(3) + 5 y = –6 + 5 y = –1 Solution: (3, –1) Use the substitution method to solve the system of linear equations. y = –2x + 5 4x + 3y = 9 4x + 3(–2x + 5) = 9 4x – 6x + 15 = 9 –2x + 15 = 9 – 15 – 15 –2x = –6 –2 –2 x = 3 y = –2(3) + 5 y = –6 + 5 y = –1 Solution: (3, –1)

Exit Problems Solve the system of equations using the substitution method. x = 4y – 5 2x + 3y = 23

Communication Prompt Why do you think there are multiple methods in mathematics to find the answer to a problem?