Computational Methods EML3041

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Computational Methods EML3041 Bring it together Computational Methods EML3041

Why do we use numerical methods?

Why use Numerical Methods? To solve problems that cannot be solved exactly

Why use Numerical Methods? To solve problems that have exact solutions but are otherwise intractable!

Assembling a fulcrum for a bascule bridge Girder Trunnion Hub

What model should I use to calculate contraction of trunnion?

Finding the fluid temperature to get enough contraction

Finding the expression for thermal expansion coefficient

What is the temperature of the trunnion after half an hour? http://numericalmethods.eng.usf.edu

How long does it take a trunnion to cool down? http://numericalmethods.eng.usf.edu

Example A solid steel shaft at room temperature of 27°C is needed to be contracted so that it can be shrunk-fit into a hollow hub. It is placed in a refrigerated chamber that is maintained at −33°C. The rate of change of temperature of the solid shaft q is given by Using Euler’s method, find the temperature of the steel shaft after 86400 seconds. Take a step size of h = 43200 seconds. http://numericalmethods.eng.usf.edu

Temperature vs. Time http://numericalmethods.eng.usf.edu

What is the rate of change of heat stored in the cylinder? http://numericalmethods.eng.usf.edu

Can you identify? We talked about 7 mathematical procedures in this course. Write them down. Now connect the problem just discussed to these 7 mathematical procedures on each of the previous slides.

A 4-letter word that starts with F I am a fool! What one fool can do, another can!

The Newton-Raphson method of finding real roots of the nonlinear equation f(x)=0 can be derived by using the first two terms of the Taylor series. One would then expect that adding one more term of the Taylor series to the Newton-Raphson method would result in higher accuracy of the results for the same number of iterations as the Newton-Raphson method. However, this new approach of adding one more term of Taylor series is not feasible because one has to solve a quadratic equation to get the new estimate of the root of the equation. the estimates of the root of the equation may turn out to be complex numbers one needs to find the first derivative of f(x). one needs to find the second derivative of f(x).

(P × Q) × (R × S) ((P × Q) × R) × S P × ((Q × R) × S) It is desired to compute the following matrix product, P×Q×R×S. The sizes of the four matrices are: P is 1×4, Q is 4×20, R is 20×5, and S is 5×1. Amongst the choices given below, the most efficient (the least number of floating point operations of add, subtract, multiplication and divide) way to compute the matrix product is (P × Q) × (R × S) ((P × Q) × R) × S P × ((Q × R) × S) (P × (Q × R)) × S

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