Shortest Paths C B A E D F 3 2 8 5 4 7 1 9.

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Shortest Paths C B A E D F 3 2 8 5 4 7 1 9

Outline and Reading Weighted graphs (§7.1) Shortest path problem Shortest path properties Dijkstra’s algorithm (§7.1.1) Algorithm Edge relaxation The Bellman-Ford algorithm (§7.1.2) Shortest paths in dags (§7.1.3) All-pairs shortest paths (§7.2.1)

Weighted Graphs PVD ORD SFO LGA HNL LAX DFW MIA 849 1843 142 802 1743 In a weighted graph, each edge has an associated numerical value, called the weight of the edge Edge weights may represent, distances, costs, etc. Example: In a flight route graph, the weight of an edge represents the distance in miles between the endpoint airports 849 PVD 1843 ORD 142 SFO 802 LGA 1743 1205 337 1387 HNL 2555 1099 LAX 1233 DFW 1120 MIA

Shortest Path Problem PVD ORD SFO LGA HNL LAX DFW MIA 849 1843 142 802 Given a weighted graph and two vertices u and v, we want to find a path of minimum total weight between u and v. Length of a path is the sum of the weights of its edges. Example: Shortest path between Providence and Honolulu Applications Internet packet routing Flight reservations Driving directions 849 PVD 1843 ORD 142 SFO 802 LGA 1743 1205 337 1387 HNL 2555 1099 LAX 1233 DFW 1120 MIA

Shortest Path Properties Property 1: A subpath of a shortest path is itself a shortest path Property 2: There is a tree of shortest paths from a start vertex to all the other vertices Example: Tree of shortest paths from Providence 849 PVD 1843 ORD 142 SFO 802 LGA 1743 1205 337 1387 HNL 2555 1099 LAX 1233 DFW 1120 MIA

Dijkstra’s Algorithm The distance of a vertex v from a vertex s is the length of a shortest path between s and v Dijkstra’s algorithm computes the distances of all the vertices from a given start vertex s Assumptions: the graph is connected the edges are undirected the edge weights are nonnegative We grow a “cloud” of vertices, beginning with s and eventually covering all the vertices We store with each vertex v a label d(v) representing the distance of v from s in the subgraph consisting of the cloud and its adjacent vertices At each step We add to the cloud the vertex u outside the cloud with the smallest distance label, d(u) We update the labels of the vertices adjacent to u

Edge Relaxation d(z) = 75 d(z) = 60 Consider an edge e = (u,z) such that u is the vertex most recently added to the cloud z is not in the cloud The relaxation of edge e updates distance d(z) as follows: d(z)  min{d(z),d(u) + weight(e)} d(u) = 50 10 d(z) = 75 e u s z d(u) = 50 10 d(z) = 60 u e s z

Example C B A E D F 4 2 8  7 1 5 3 9 11

Example (cont.) A 8 4 2 7 2 3 7 1 B C D 3 9 5 8 2 5 E F A 4 8 2 7 2 3 A 8 4 2 7 2 3 7 1 B C D 3 9 5 8 2 5 E F A 4 8 2 7 2 3 7 1 B C D 3 9 5 8 2 5 E F

Dijkstra’s Algorithm Algorithm DijkstraDistances(G, s) Q  new heap-based priority queue for all v  G.vertices() if v = s setDistance(v, 0) else setDistance(v, ) l  Q.insert(getDistance(v), v) setLocator(v,l) while Q.isEmpty() u  Q.removeMin() for all e  G.incidentEdges(u) { relax edge e } z  G.opposite(u,e) r  getDistance(u) + weight(e) if r < getDistance(z) setDistance(z,r) Q.replaceKey(getLocator(z),r) A priority queue stores the vertices outside the cloud Key: distance Element: vertex Locator-based methods insert(k,e) returns a locator replaceKey(l,k) changes the key of an item We store two labels with each vertex: Distance (d(v) label) locator in priority queue

Analysis Graph operations Label operations Priority queue operations Method incidentEdges is called once for each vertex Label operations We set/get the distance and locator labels of vertex z O(deg(z)) times Setting/getting a label takes O(1) time Priority queue operations Each vertex is inserted once into and removed once from the priority queue, where each insertion or removal takes O(log n) time The key of a vertex in the priority queue is modified at most deg(w) times, where each key change takes O(log n) time Dijkstra’s algorithm runs in O((n + m) log n) time provided the graph is represented by the adjacency list structure Recall that Sv deg(v) = 2m The running time can also be expressed as O(m log n) since the graph is connected

Extension Using the template method pattern, we can extend Dijkstra’s algorithm to return a tree of shortest paths from the start vertex to all other vertices We store with each vertex a third label: parent edge in the shortest path tree In the edge relaxation step, we update the parent label Algorithm DijkstraShortestPathsTree(G, s) … for all v  G.vertices() setParent(v, ) for all e  G.incidentEdges(u) { relax edge e } z  G.opposite(u,e) r  getDistance(u) + weight(e) if r < getDistance(z) setDistance(z,r) setParent(z,e) Q.replaceKey(getLocator(z),r)

Why Dijkstra’s Algorithm Works Dijkstra’s algorithm is based on the greedy method. It adds vertices by increasing distance. Suppose it didn’t find all shortest distances. Let F be the first wrong vertex the algorithm processed. When the previous node, D, on the true shortest path was considered, its distance was correct. But the edge (D,F) was relaxed at that time! Thus, so long as d(F)>d(D), F’s distance cannot be wrong. That is, there is no wrong vertex. A 8 4 2 7 2 3 7 1 B C D 3 9 5 8 2 5 E F

Why It Doesn’t Work for Negative-Weight Edges Dijkstra’s algorithm is based on the greedy method. It adds vertices by increasing distance. A 8 4 If a node with a negative incident edge were to be added late to the cloud, it could mess up distances for vertices already in the cloud. 6 7 5 4 7 1 B C D -8 5 9 2 5 E F C’s true distance is 1, but it is already in the cloud with d(C)=5!

Bellman-Ford Algorithm Algorithm BellmanFord(G, s) for all v  G.vertices() if v = s setDistance(v, 0) else setDistance(v, ) for i  1 to n-1 do for each e  G.edges() { relax edge e } u  G.origin(e) z  G.opposite(u,e) r  getDistance(u) + weight(e) if r < getDistance(z) setDistance(z,r) Works even with negative-weight edges Must assume directed edges (for otherwise we would have negative-weight cycles) Iteration i finds all shortest paths that use i edges. Running time: O(nm). Can be extended to detect a negative-weight cycle if it exists How?

Nodes are labeled with their d(v) values Bellman-Ford Example Nodes are labeled with their d(v) values 4 4 8 8 -2 -2 8 -2 4 7 1 7 1       3 9 3 9 -2 5 -2 5     4 4 8 8 -2 -2 5 7 1 -1 7 1 8 -2 4 5 -2 -1 1 3 9 3 9 6 9 4 -2 5 -2 5   1 9

All-Pairs Shortest Paths Algorithm AllPair(G) {assumes vertices 1,…,n} for all vertex pairs (i,j) if i = j D0[i,i]  0 else if (i,j) is an edge in G D0[i,j]  weight of edge (i,j) else D0[i,j]  +  for k  1 to n do for i  1 to n do for j  1 to n do Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} return Dn Find the distance between every pair of vertices in a weighted directed graph G. We can make n calls to Dijkstra’s algorithm (if no negative edges), which takes O(n m log n) time. Likewise, n calls to Bellman-Ford would take O(n2m) time. We can achieve O(n3) time using dynamic programming (similar to the Floyd-Warshall algorithm). Uses only vertices numbered 1,…,k (compute weight of this edge) i Uses only vertices numbered 1,…,k-1 j Uses only vertices numbered 1,…,k-1 k

All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} 09-08-04 All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} Original graph Paths through V1 V1 V2 V3 V4 3 2 -3 4 1 V1 V2 V3 V4 3 2 -3 4 1 Check v2-v3, 2-4, 3-2, 3-4, 4-2, 4-3

All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} 09-08-04 All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} Paths through V1 Paths through V2 V1 V2 V3 V4 3 2 -3 4 1 V1 V2 V3 V4 3 2 0 -3 4 1 3 1

All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} 09-08-04 All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} Paths through V2 Paths through V3 V1 V2 V3 V4 3 -3 4 1 V1 V2 V3 V4 3 4 -3 1

All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} 09-08-04 All Pairs example Dk[i,j]  min{Dk-1[i,j], Dk-1[i,k]+Dk-1[k,j]} Paths through V3 Paths through V4 V1 V2 V3 V4 3 4 -3 1 V1 V2 V3 V4 3 4 2 -3 5 8 1

Minimum Spanning Trees JFK BOS MIA ORD LAX DFW SFO BWI PVD 867 2704 187 1258 849 144 740 1391 184 946 1090 1121 2342 1846 621 802 1464 1235 337

Outline and Reading Minimum Spanning Trees (§7.3) Definitions A crucial fact The Prim-Jarnik Algorithm (§7.3.2)

Minimum Spanning Tree ORD PIT DEN DCA STL DFW ATL 10 1 6 7 9 3 4 8 5 2 Spanning subgraph Subgraph of a graph G containing all the vertices of G Spanning tree Spanning subgraph that is itself a (free) tree Minimum spanning tree (MST) Spanning tree of a weighted graph with minimum total edge weight Applications Communications networks Transportation networks 1 PIT DEN 6 7 9 3 DCA STL 4 8 5 2 DFW ATL

Replacing f with e yields a better spanning tree Cycle Property 8 4 2 3 6 7 9 e C f Cycle Property: Let T be a minimum spanning tree of a weighted graph G Let e be an edge of G that is not in T and C let be the cycle formed by e with T For every edge f of C, weight(f)  weight(e) Proof: By contradiction If weight(f) > weight(e) we can get a spanning tree of smaller weight by replacing e with f Replacing f with e yields a better spanning tree 8 4 2 3 6 7 9 C e f

Replacing f with e yields another MST Partition Property U V 7 f 4 9 5 Partition Property: Consider a partition of the vertices of G into subsets U and V Let e be an edge of minimum weight across the partition There is a minimum spanning tree of G containing edge e Proof: Let T be an MST of G If T does not contain e, consider the cycle C formed by e with T and let f be an edge of C across the partition By the cycle property, weight(f)  weight(e) Thus, weight(f) = weight(e) We obtain another MST by replacing f with e 2 8 8 3 e 7 Replacing f with e yields another MST U V 7 f 4 9 5 2 8 8 3 e 7

Prim-Jarnik’s Algorithm Similar to Dijkstra’s algorithm (for a connected graph) We pick an arbitrary vertex s and we grow the MST as a cloud of vertices, starting from s We store with each vertex v a label d(v) = the smallest weight of an edge connecting v to a vertex in the cloud At each step: We add to the cloud the vertex u outside the cloud with the smallest distance label We update the labels of the vertices adjacent to u

Prim-Jarnik’s Algorithm (cont.) Algorithm PrimJarnikMST(G) Q  new heap-based priority queue s  a vertex of G for all v  G.vertices() if v = s setDistance(v, 0) else setDistance(v, ) setParent(v, ) l  Q.insert(getDistance(v), v) setLocator(v,l) while Q.isEmpty() u  Q.removeMin() for all e  G.incidentEdges(u) z  G.opposite(u,e) r  weight(e) if r < getDistance(z) setDistance(z,r) setParent(z,e) Q.replaceKey(getLocator(z),r) A priority queue stores the vertices outside the cloud Key: distance Element: vertex Locator-based methods insert(k,e) returns a locator replaceKey(l,k) changes the key of an item We store three labels with each vertex: Distance Parent edge in MST Locator in priority queue

Example B D C A F E 7 4 2 8 5 3 9 

Example (contd.) B D C A F E 7 4 2 8 5 3 9

Analysis Graph operations Label operations Priority queue operations Method incidentEdges is called once for each vertex Label operations We set/get the distance, parent and locator labels of vertex z O(deg(z)) times Setting/getting a label takes O(1) time Priority queue operations Each vertex is inserted once into and removed once from the priority queue, where each insertion or removal takes O(log n) time The key of a vertex w in the priority queue is modified at most deg(w) times, where each key change takes O(log n) time Prim-Jarnik’s algorithm runs in O((n + m) log n) time provided the graph is represented by the adjacency list structure Recall that Sv deg(v) = 2m The running time is O(m log n) since the graph is connected