Do now
Potential energy = mgh = Fgh = (10N)(5m) = 50 Nm = 50 J Do now Potential energy = mgh = Fgh = (10N)(5m) = 50 Nm = 50 J ET = PE + KE + Q 55J = 50 J + 0J + 5J
We now consider problems in which Q ≠ 0 Energy “Loss” Energy can never by truly destroyed, but it can be converted into non-mechanical forms (mainly heat) that are not ‘useful’. We now consider problems in which Q ≠ 0 Q = Work necessary to overcome friction (it can also represent an increase in energy/temperature)
Constant velocity and Constant mass = Constant kinetic energy (1/2 mv^2) Horizontal Track = Constant Potential energy Sliding along a rough track = friction = increase in internal energy, only (2)
7 minutes to complete worksheet
Review
Extra Credit Last week’s quiz will not count as extra credit There will be a 5-point extra credit question on the exam available to everyone that is very similar (no partial credit)