Vbat Circuit Lab Practice #10—Kirchhoff’s Voltage/Current Laws, Wheatstone Bridges, Thévenin’s Theorem, and Norton’s Theorem Mr. Burleson geaux15@hotmail.com.

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Vbat Circuit Lab Practice #10—Kirchhoff’s Voltage/Current Laws, Wheatstone Bridges, Thévenin’s Theorem, and Norton’s Theorem Mr. Burleson geaux15@hotmail.com

Multiple Sources Sometimes a circuit has more than one source Voltage Sources should be added in series Current Sources should be added in parallel You shouldn’t put voltage sources in parallel or current sources in series, as it can create a situation that violates circuit rules.

Kirchhoff's Voltage Law (KCL) (Division C Only) The directed sum of the electrical potential differences (voltage) around any closed network is zero or: the sum of the voltage in any closed loop is equivalent to the sum of the potential drops in that loop

KVL Examples Vbat = 9V VR1 = VR2 = 3V What is VR3 Vbat = 12V VR1 = 5V, VR2 = 3V Vbat = 15V VR1 = 7V, VR2 = 8V Vbat

More KVL Examples Vbat = 9V What is VR1? What is VR2? VR1 = = 3V What is VR3 and VR2 Vbat = 12V VR2 = = 3V What is VR1 and VR3 Vbat Vbat

Kirchhoff's Current Law (KCL) (Division C Only) At any node (junction) in an electrical circuit, the sum of currents flowing into that node is equal to the sum of currents flowing out of that node or: The algebraic sum of currents in a network of conductors meeting at a point is zero. or: All current into a node equals all current out!

KCL Examples I1 = 9A IR1 = 3A What is IR2 and I2 IR1 = 6A I1 = 10A

More KCL Examples I1 = 9A, I2 = 9A, I3 = 9A What is I4

Wheatstone Bridge A Wheatstone bridge is an electrical circuit used to measure an unknown electrical resistance by balancing two legs of a bridge circuit, one leg of which includes the unknown component. It was invented by Samuel Hunter Christie in 1833 and improved and popularized by Sir Charles Wheatstone in 1843. One of the Wheatstone bridge's initial uses was for the purpose of soils analysis and comparison

Wheatstone Bridge Usage Rx is the unknown resistance R1, R2, and R3 are the known resistance If the bridge is balanced then the ratio of R2/R1 =Rx/R3, and the voltage and current between Node D and Node B equals zero. Or Rx = R2/R1 * R3 Normally R2 is a variable resistor If the bridge is unbalanced, the direction of the current indicates whether R2 is too big or too small.

Wheatstone Examples R1=R2=R3=100Ω VD=VB, IDB = 0 A What is Rx

Thévenin’s Theorem/Equivalent Thévenin's theorem states that any combination of voltage sources, current sources, and resistors with two terminals is electrically equivalent to a single voltage source V and a single series resistor R.

How to find Thévenin Equivalent Values Calculate the output voltage, VAB, when in open circuit condition (no load resistor—meaning infinite resistance). This is VTh. Calculate the output current, IAB, when the output terminals are short circuited (load resistance is 0). RTh equals VTh divided by this IAB. or Replace independent voltage sources with short circuits and independent current sources with open circuits. The total resistance across the output port is the Thévenin impedance RTh.

Thévenin Example Find Vth and Rth A and B are Open, so no current flows through R1 and therefore VR1=0 The current from the battery is then I=V/ Req Req= 2kΩ + 1kΩ + 1kΩ = 4kΩ I=15V/4kΩ= 3.75mA Using a KVL at the output Vr2+Vr3=Vr1+Vab=0+Vab=Vab Vr2=Vr3=(3.75mA)(1kΩ)=3.75V Vab=3.75V+3.75V=7.5V= Vth Rth = R1 + (R4 in parallel with (R3 + R2)) Rth = 1kΩ+1kΩ = 2kΩ

Norton’s Theorem Equivalent Norton's theorem states that any collection of voltage sources, current sources, and resistors with two terminals is electrically equivalent to an ideal current source, I, in parallel with a single resistor, R.

How to find Norton’s Equivalent Values Find the Norton current INo. Calculate the output current, IAB, with a short circuit as the load (meaning 0 resistance between A and B). This is INo. Find the Norton resistance RNo. When there are no dependent sources (all current and voltage sources are independent), there are two methods of determining the Norton impedance RNo. Calculate the output voltage, VAB, when in open circuit condition (i.e., no load resistor — meaning infinite load resistance). RNo equals this VAB divided by INo. or Replace independent voltage sources with short circuits and independent current sources with open circuits. The total resistance across the output port is the Norton impedance RNo.

Norton Example Find Ino and Rno Find current through A and B if shorted The current from the battery is then I=V/Req Req = 2kΩ + 1kΩ in parallel with 2kΩ = 2.67kΩ I=15V/2.67kΩ= 5.625mA Iab = 5.625mA*(2/3)= 3.75mA= Ino Removing the power supply with a short, Rno is the resistance looking into AB Rno = 1kΩ + 2kΩ in parallel with 2kΩ = 1kΩ +1kΩ = 2kΩ

How are they related Rno= Rth Vth = Ino * Rno Ino = Vth / Rth Use whichever one makes the problem easier to solve. Make sure the current source and resistor are in parallel for Norton Make sure the voltage source and resistor are in series for Thévenin

In Practice Sample Competition 100 points Timed—30 minutes Do the following written quiz individually You may use any and all notes in your notebook You may use your calculator Make sure you fill out your name and team at the top of each page Tackle the easy problems first, then the tough ones you know how to tackle, then finally the ones you have to guess on. If you have time, check your answers

Homework Update your binder to get it competition ready Complete the circuit problems from the Homework Generator Level 10 Resistors Level 11 Wheatstone Level 14 Norton-Thevenin Correct the problems you missed on the practice competition on separate paper.